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Created page with "=Bipolytrope Generalization (Pt 2)= <table border="1" align="center" width="100%" colspan="8"> <tr> <td align="center" bgcolor="lightblue" width="25%"><br />Part I:  Bipolytrope Generalization   </td> <td align="center" bgcolor="lightblue" width="25%"><br />Part II:  Derivations   </td> <td align="center" bgcolor="lightblue" width="25%"><br />SSC/BipolytropeGeneralizat..."
 
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</tr>
</tr>
</table>
</table>
{{ SGFworkInProgress }}
=Detailed Derivations=
Dividing the free-energy expression through by <math>~E_\mathrm{norm}</math> generates,
<div align="center">
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~\mathfrak{G}^* \equiv \frac{\mathfrak{G}}{E_\mathrm{norm}}</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>
- \frac{3}{5} \biggl( \frac{GM_\mathrm{tot}^2}{E_\mathrm{norm}} \biggr) \biggl( \frac{1}{R} \biggr) \cdot \mathfrak{f}_{WM}
+ \biggl[ \frac{\nu s_\mathrm{core} }{(\gamma_c - 1)} \biggr] \biggl[ \frac{M_\mathrm{tot} K_c \rho_{ic}^{\gamma_c-1} }{E_\mathrm{norm}} \biggr] 
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>
~+ \biggl[ \frac{(1-\nu) s_\mathrm{env} }{(\gamma_e - 1)} \biggr] \biggl[ \frac{M_\mathrm{tot} K_e \rho_{ie}^{\gamma_e-1} }{E_\mathrm{norm}}  \biggr]
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>
- \frac{3\cdot \mathfrak{f}_{WM}}{5} \biggl[ \frac{K_c G^{(3\gamma_c -4)}M_\mathrm{tot}^{2(3\gamma_c -4)}}{G^{3\gamma_c-3} M_\mathrm{tot}^{5\gamma_c-6}} \biggr]^{1/(3\gamma_c -4)} \biggl( \frac{1}{R} \biggr)
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>
+ \biggl[ \frac{\nu s_\mathrm{core} }{(\gamma_c - 1)} \biggr] \biggl[ \frac{K_c M_\mathrm{tot}^{3\gamma_c -4} K_c^{3\gamma_c -4}  }{G^{3\gamma_c-3} M_\mathrm{tot}^{5\gamma_c-6}}
\biggr]^{1/(3\gamma_c -4)}  \biggl( \frac{\rho_{ic}}{\bar\rho} \biggr)^{\gamma_c-1} \biggl[ \frac{3M_\mathrm{tot}}{4\pi R^3} \biggr]^{\gamma_c-1}
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>
~+ \biggl[ \frac{(1-\nu) s_\mathrm{env} }{(\gamma_e - 1)} \biggr] \biggl[ \frac{K_c M_\mathrm{tot}^{3\gamma_c -4} K_e^{3\gamma_c -4}  }{G^{3\gamma_c-3} M_\mathrm{tot}^{5\gamma_c-6}}
\biggr]^{1/(3\gamma_c -4)}  \biggl( \frac{\rho_{ie}}{\bar\rho} \biggr)^{\gamma_e-1} \biggl[ \frac{3M_\mathrm{tot}}{4\pi R^3} \biggr]^{\gamma_e-1}
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>
- \frac{3\cdot \mathfrak{f}_{WM}}{5} \biggl( \frac{R_\mathrm{norm}}{R} \biggr)
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>
+ \biggl[ \frac{\nu s_\mathrm{core} }{(\gamma_c - 1)} \biggr] \biggl( \frac{3M_\mathrm{tot}}{4\pi} \biggr)^{\gamma_c-1}
\biggl[ \frac{ K_c^{3\gamma_c -3}  }{G^{3\gamma_c-3} M_\mathrm{tot}^{2\gamma_c-2}}
\biggr]^{1/(3\gamma_c -4)}  \biggl[ \frac{R_\mathrm{norm}}{R} \biggr]^{3(\gamma_c-1)}
\biggl[ \biggl( \frac{K_c}{G} \biggr) M_\mathrm{tot}^{\gamma_c-2} \biggr]^{-3(\gamma_c-1)/(3\gamma_c -4)}
\biggl( \frac{\rho_{ic}}{\bar\rho} \biggr)^{\gamma_c-1}
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>
~+ \biggl[ \frac{(1-\nu) s_\mathrm{env} }{(\gamma_e - 1)} \biggr] \biggl( \frac{3M_\mathrm{tot}}{4\pi} \biggr)^{\gamma_e-1}
\biggl[ \frac{K_c^{3\gamma_c - 3} (K_e/K_c)^{3\gamma_c -4}  }{G^{3\gamma_c-3} M_\mathrm{tot}^{2\gamma_c-2}} \biggr]^{1/(3\gamma_c -4)} 
\biggl[ \frac{R_\mathrm{norm}}{R} \biggr]^{3(\gamma_e-1)}
\biggl[ \biggl( \frac{K_c}{G} \biggr) M_\mathrm{tot}^{\gamma_c-2} \biggr]^{-3(\gamma_e-1)/(3\gamma_c -4)} \biggl( \frac{\rho_{ie}}{\bar\rho} \biggr)^{\gamma_e-1}
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>
- \frac{3\cdot \mathfrak{f}_{WM}}{5} \biggl( \frac{R_\mathrm{norm}}{R} \biggr)
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>
+ \biggl[ \frac{\nu s_\mathrm{core} }{(\gamma_c - 1)} \biggr]  \biggl( \frac{3}{4\pi} \biggr)^{\gamma_c-1} \biggl[ M_\mathrm{tot}^{3\gamma_c-4} \biggr]^{(\gamma_c-1)/(3\gamma_c-4)}
\biggl[ M_\mathrm{tot}^{-2} \biggr]^{(\gamma_c-1)/(3\gamma_c -4)} 
\biggl[ M_\mathrm{tot}^{-3\gamma_c+6} \biggr]^{(\gamma_c-1)/(3\gamma_c -4)}
\biggl[ \frac{R_\mathrm{norm}}{R} \biggr]^{3(\gamma_c-1)}
\biggl( \frac{\rho_{ic}}{\bar\rho} \biggr)^{\gamma_c-1}
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>
~+ \biggl[ \frac{(1-\nu) s_\mathrm{env} }{(\gamma_e - 1)} \biggr] \biggl( \frac{3}{4\pi} \biggr)^{\gamma_e-1} \biggl( \frac{K_e}{K_c} \biggr)
\biggl[ M_\mathrm{tot}^{2(\gamma_e-1)-2(\gamma_c-1)}\biggr]^{1/(3\gamma_c-4)}
\biggl[ \frac{R_\mathrm{norm}}{R} \biggr]^{3(\gamma_e-1)}
\biggl[ \biggl( \frac{K_c}{G} \biggr)^{(\gamma_c-1)-(\gamma_e-1)} \biggr]^{3/(3\gamma_c -4)} \biggl( \frac{\rho_{ie}}{\bar\rho} \biggr)^{\gamma_e-1}
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>
- \frac{3\cdot \mathfrak{f}_{WM}}{5} \biggl( \frac{R}{R_\mathrm{norm}} \biggr)^{-1}
+ \frac{\nu s_\mathrm{core} }{(\gamma_c - 1)} \biggl[ \biggl( \frac{3}{4\pi} \biggr)\frac{\rho_{ic}}{\bar\rho} \biggr]^{\gamma_c-1}
\biggl[ \frac{R}{R_\mathrm{norm}} \biggr]^{-3(\gamma_c-1)}
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
&nbsp;
  </td>
  <td align="left">
<math>
~+ \frac{(1-\nu) s_\mathrm{env} }{(\gamma_e - 1)} \biggl( \frac{K_e}{K_c} \biggr)
\biggl[ \frac{K_c^3}{G^3 M_\mathrm{tot}^2}  \biggr]^{(\gamma_c-\gamma_e)/(3\gamma_c -4)}
\biggl[\biggl( \frac{3}{4\pi} \biggr) \frac{\rho_{ie}}{\bar\rho} \biggr]^{\gamma_e-1} \biggl[ \frac{R}{R_\mathrm{norm}} \biggr]^{-3(\gamma_e-1)} \, .
</math>
  </td>
</tr>
</table>
</div>
<span id="pressureMatch">We also want to ensure that envelope pressure matches the core pressure at the interface.</span>  This means,
<div align="center">
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~K_e \rho_{ie}^{\gamma_e}</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~K_c \rho_{ic}^{\gamma_c}</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>\Rightarrow ~~~~\frac{K_e}{K_c} </math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\rho_{ic}^{\gamma_c} \rho_{ie}^{-\gamma_e} </math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\biggl[ \frac{\rho_{ic}}{\rho_\mathrm{norm}} \biggr]^{\gamma_c} \biggl[ \frac{\rho_{ie}}{\rho_\mathrm{norm}} \biggr]^{-\gamma_e}
\rho_\mathrm{norm}^{\gamma_c - \gamma_e}</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\biggl[ \frac{\rho_{ic}}{\rho_\mathrm{norm}} \biggr]^{\gamma_c} \biggl[ \frac{\rho_{ie}}{\rho_\mathrm{norm}} \biggr]^{-\gamma_e}
\biggl\{ \frac{3}{4\pi} \biggl[ \frac{G^3 M_\mathrm{tot}^2}{K_c^3} \biggr]^{1/(3\gamma_c -4)}  \biggr\}^{\gamma_c - \gamma_e}</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>\Rightarrow ~~~~\frac{K_e}{K_c} \biggl[ \frac{K_c^3}{G^3 M_\mathrm{tot}^2} \biggr]^{(\gamma_c - \gamma_e)/(3\gamma_c -4)} 
\biggl[\biggl( \frac{3}{4\pi} \biggr) \frac{\rho_{ie}}{\bar\rho} \biggr]^{\gamma_e-1}</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>~\biggl[ \biggl( \frac{3}{4\pi} \biggr)\frac{\rho_{ic}}{\rho_\mathrm{norm}} \biggr]^{\gamma_c}
\biggl[ \biggl( \frac{3}{4\pi} \biggr)\frac{\rho_{ie}}{\rho_\mathrm{norm}} \biggr]^{-\gamma_e}
\biggl[\biggl( \frac{3}{4\pi} \biggr) \frac{\rho_{ie}}{\bar\rho} \biggr]^{\gamma_e-1}
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>
\biggl[ \biggl( \frac{3}{4\pi} \biggr)\frac{\rho_{ic}}{\bar\rho} \biggr]^{\gamma_c-1}
\biggl( \frac{\rho_{ic}}{\rho_{ie}} \biggr) \biggl( \frac{\rho_\mathrm{norm}}{ \bar\rho } \biggr)^{\gamma_e - \gamma_c}
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>
\biggl[ \biggl( \frac{3}{4\pi} \biggr)\frac{\rho_{ic}}{\bar\rho} \biggr]^{\gamma_c-1}
\biggl( \frac{\rho_{ic}}{\rho_{ie}} \biggr) \biggl( \frac{ R}{R_\mathrm{norm}} \biggr)^{3(\gamma_e - \gamma_c)}
</math>
  </td>
</tr>
</table>
</div>
Hence, we can write the normalized (and dimensionless) free energy as,
<div align="center">
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>~\mathfrak{G}^*</math>
  </td>
  <td align="center">
<math>~=</math>
  </td>
  <td align="left">
<math>
- \frac{3\cdot \mathfrak{f}_{WM}}{5} \biggl( \frac{R}{R_\mathrm{norm}} \biggr)^{-1}
+ \biggl\{ \frac{\nu s_\mathrm{core} }{(\gamma_c - 1)} + \frac{(1-\nu) s_\mathrm{env} }{(\gamma_e - 1)} \biggl( \frac{ \rho_{ic} }{ \rho_{ie} } \biggr)\biggr\}
\biggl[ \biggl( \frac{3}{4\pi} \biggr)\frac{\rho_{ic}}{\bar\rho} \biggr]^{\gamma_c-1}
\biggl[ \frac{R}{R_\mathrm{norm}} \biggr]^{-3(\gamma_c-1)} \, .
</math>
  </td>
</tr>
</table>
</div>
Keep in mind that, if the envelope and core both have uniform (but different) densities, then <math>~\rho_{ic} = \rho_c</math>, <math>~\rho_{ie} = \rho_e</math>, and
<div align="center">
<math>
\frac{\rho_c}{\bar\rho} = \frac{\nu}{q^3} \, ; ~~~~~ \frac{\rho_e}{\bar\rho} = \frac{1-\nu}{1-q^3} \, ; ~~~~~ \frac{\rho_e}{\rho_c} = \frac{q^3(1-\nu)}{\nu (1-q^3)} \, .
</math>
</div>
==Free Energy and Its Derivatives==
Now, the free energy can be written as,
<div align="center">
<table border="0">
<tr>
  <td align="right">
<math>~\mathfrak{G}</math>
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~U_\mathrm{tot} + W</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~\biggl[ \frac{2}{3(\gamma_c - 1)} \biggr] S_\mathrm{core} + \biggl[ \frac{2}{3(\gamma_e - 1)} \biggr] S_\mathrm{env} + W</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~\biggl[ \frac{2}{3(\gamma_c - 1)} \biggr] C_\mathrm{core} R^{3-3\gamma_c}
+ \biggl[ \frac{2}{3(\gamma_e - 1)} \biggr] C_\mathrm{env} R^{3-3\gamma_e} - A R^{-1} \, .</math>
  </td>
</tr>
</table>
</div>
The first derivative of the free energy with respect to radius is, then,
<div align="center">
<table border="0">
<tr>
  <td align="right">
<math>~\frac{d\mathfrak{G}}{dR}</math>
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ -2 C_\mathrm{core} R^{2-3\gamma_c} -2 C_\mathrm{env} R^{2-3\gamma_e} + A R^{-2} \, .</math>
  </td>
</tr>
</table>
</div>
And the second derivative is,
<div align="center">
<table border="0">
<tr>
  <td align="right">
<math>~\frac{d^2\mathfrak{G}}{dR^2}</math>
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ -2 (2-3\gamma_c) C_\mathrm{core} R^{1-3\gamma_c} -2 (2-3\gamma_e) C_\mathrm{env} R^{1-3\gamma_e} - 2A R^{-3} \, .</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ \frac{2}{R^2} \biggl[(3\gamma_c-2) C_\mathrm{core} R^{3-3\gamma_c} +
(3\gamma_e-2) C_\mathrm{env} R^{3-3\gamma_e} - A R^{-1} \biggr]</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ \frac{2}{R^2} \biggl[(3\gamma_c-2) S_\mathrm{core} +
(3\gamma_e-2) S_\mathrm{env}  +W \biggr] \, .</math>
  </td>
</tr>
</table>
</div>
==Equilibrium==
The radius, <math>~R_\mathrm{eq}</math>, of the equilibrium configuration(s) is determined by setting the first derivative of the free energy to zero.  Hence,
<div align="center">
<table border="0">
<tr>
  <td align="right">
<math>~0 </math>
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ 2 C_\mathrm{core} R_\mathrm{eq}^{2-3\gamma_c} + 2 C_\mathrm{env} R_\mathrm{eq}^{2-3\gamma_e} - A R_\mathrm{eq}^{-2} </math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ R_\mathrm{eq}^{-1} \biggl[ 2 C_\mathrm{core} R_\mathrm{eq}^{3-3\gamma_c} +
2 C_\mathrm{env} R_\mathrm{eq}^{3-3\gamma_e} - A R_\mathrm{eq}^{-1} \biggr]</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ R_\mathrm{eq}^{-1} \biggl[ 2 S_\mathrm{core} +
2 S_\mathrm{env}  +W \biggr]</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>\Rightarrow ~~~~ 2 S_\mathrm{tot} + W </math>
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~0 \, .</math>
  </td>
</tr>
</table>
</div>
This is the familiar statement of virial equilibrium.  From it we should always be able to derive the radius of equilibrium configurations.
==Stability==
To assess the relative stability of an equilibrium configuration, we need to determine the sign of the second derivative of the free energy, evaluated at the equilibrium radius.  If the sign of the second derivative is positive, the system is dynamically stable; if the sign is negative, he system is dynamically unstable.  Using the above statement of virial equilibrium, that is, setting,
<div align="center">
<table border="0">
<tr>
  <td align="right">
<math>~2 S_\mathrm{tot} + W</math>
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~0 \, ,</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>\Rightarrow ~~~~ S_\mathrm{env} </math>
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~- S_\mathrm{core} - \frac{W}{2} \, ,</math>
  </td>
</tr>
</table>
</div>
we obtain,
<div align="center">
<table border="0">
<tr>
  <td align="right">
<math>~\frac{d^2\mathfrak{G}}{dR^2}\biggr|_\mathrm{eq}</math>
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ \frac{2}{R_\mathrm{eq}^2} \biggl[ (3\gamma_c-2) S_\mathrm{core}
+W - (3\gamma_e-2)\biggl( S_\mathrm{core} + \frac{W}{2}\biggr) \biggr]_\mathrm{eq} </math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ \frac{2}{R_\mathrm{eq}^2} \biggl[ 3(\gamma_c-\gamma_e) S_\mathrm{core}
+ \biggl(2 - \frac{3}{2}\gamma_e\biggr)W \biggr]_\mathrm{eq} </math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ \frac{6}{R_\mathrm{eq}^2} \biggl[ (\gamma_c-\gamma_e) S_\mathrm{core}
+ \frac{1}{2}\biggl(\frac{4}{3} - \gamma_e\biggr)W \biggr]_\mathrm{eq} </math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>~=~</math>
  </td>
  <td align="left">
<math>~ \frac{6}{R_\mathrm{eq}^2} \biggl[ -\frac{W}{2}\biggl( \gamma_e - \frac{4}{3}\biggr) -
(\gamma_e-\gamma_c) S_\mathrm{core} \biggr]_\mathrm{eq} \, .</math>
  </td>
</tr>
</table>
</div>
So, if when evaluated at the equilibrium state, the expression inside of the square brackets of this last expression is negative, the equilibrium configuration will be dynamically unstable.  We have chosen to write the expression in this particular final form because we generally will be interested in bipolytropes for which the adiabatic exponent of the envelope is greater than <math>~4/3</math> and the adiabatic exponent of the core is less than or equal to <math>~4/3</math> &#8212; that is, <math>~\gamma_e > 4/3 \ge \gamma_c</math>.  Hence, because the gravitational potential energy, <math>~W</math>, is intrinsically negative, the system will be dynamically unstable only if the second term (involving <math>~S_\mathrm{core}</math>) is greater in magnitude than the first term (involving <math>~W</math>).
It is worth noting that, instead of drawing upon <math>~S_\mathrm{core}</math> and <math>~W</math> to define the stability condition, we could have used an appropriate combination of <math>~S_\mathrm{env}</math> and <math>~W</math>, or the <math>~S_\mathrm{core}</math> and <math>~S_\mathrm{env}</math> pair.  Also, for example, because the virial equilibrium condition is <math>~S_\mathrm{tot} = -W/2</math>, it is easy to see that the following inequality also equivalently defines stability:
<div align="center">
<table border="0">
<tr>
  <td align="right">
<math>~ S_\mathrm{tot}\biggl( \gamma_e - \frac{4}{3}\biggr) -
(\gamma_e-\gamma_c) S_\mathrm{core} </math>
  </td>
  <td align="center">
<math>~>~</math>
  </td>
  <td align="left">
<math>~ 0 \, .</math>
  </td>
</tr>
</table>
</div>


=Related Discussions=
=Related Discussions=

Revision as of 23:43, 15 January 2024

Bipolytrope Generalization (Pt 2)


Part I:  Bipolytrope Generalization

 


Part II:  Derivations

 


Part III:  Examples

 


Part IV:  Best of the Best

 



Material that appears after this point in our presentation is under development and therefore
may contain incorrect mathematical equations and/or physical misinterpretations.
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Detailed Derivations

Dividing the free-energy expression through by Enorm generates,

𝔊*≡𝔊Enorm

=

−35(GMtot2Enorm)(1R)⋅𝔣WM+[νscore(γc−1)][MtotKcρicγc−1Enorm]

 

 

+[(1−ν)senv(γe−1)][MtotKeρieγe−1Enorm]

 

=

−3⋅𝔣WM5[KcG(3γc−4)Mtot2(3γc−4)G3γc−3Mtot5γc−6]1/(3γc−4)(1R)

 

 

+[νscore(γc−1)][KcMtot3γc−4Kc3γc−4G3γc−3Mtot5γc−6]1/(3γc−4)(ρicρ¯)γc−1[3Mtot4πR3]γc−1

 

 

+[(1−ν)senv(γe−1)][KcMtot3γc−4Ke3γc−4G3γc−3Mtot5γc−6]1/(3γc−4)(ρieρ¯)γe−1[3Mtot4πR3]γe−1

 

=

−3⋅𝔣WM5(RnormR)

 

 

+[νscore(γc−1)](3Mtot4π)γc−1[Kc3γc−3G3γc−3Mtot2γc−2]1/(3γc−4)[RnormR]3(γc−1)[(KcG)Mtotγc−2]−3(γc−1)/(3γc−4)(ρicρ¯)γc−1

 

 

+[(1−ν)senv(γe−1)](3Mtot4π)γe−1[Kc3γc−3(Ke/Kc)3γc−4G3γc−3Mtot2γc−2]1/(3γc−4)[RnormR]3(γe−1)[(KcG)Mtotγc−2]−3(γe−1)/(3γc−4)(ρieρ¯)γe−1

 

=

−3⋅𝔣WM5(RnormR)

 

 

+[νscore(γc−1)](34π)γc−1[Mtot3γc−4](γc−1)/(3γc−4)[Mtot−2](γc−1)/(3γc−4)[Mtot−3γc+6](γc−1)/(3γc−4)[RnormR]3(γc−1)(ρicρ¯)γc−1

 

 

+[(1−ν)senv(γe−1)](34π)γe−1(KeKc)[Mtot2(γe−1)−2(γc−1)]1/(3γc−4)[RnormR]3(γe−1)[(KcG)(γc−1)−(γe−1)]3/(3γc−4)(ρieρ¯)γe−1

 

=

−3⋅𝔣WM5(RRnorm)−1+νscore(γc−1)[(34π)ρicρ¯]γc−1[RRnorm]−3(γc−1)

 

 

+(1−ν)senv(γe−1)(KeKc)[Kc3G3Mtot2](γc−γe)/(3γc−4)[(34π)ρieρ¯]γe−1[RRnorm]−3(γe−1).

We also want to ensure that envelope pressure matches the core pressure at the interface. This means,

Keρieγe

=

Kcρicγc

⇒KeKc

=

ρicγcρie−γe

 

=

[ρicρnorm]γc[ρieρnorm]−γeρnormγc−γe

 

=

[ρicρnorm]γc[ρieρnorm]−γe{34π[G3Mtot2Kc3]1/(3γc−4)}γc−γe

⇒KeKc[Kc3G3Mtot2](γc−γe)/(3γc−4)[(34π)ρieρ¯]γe−1

=

[(34π)ρicρnorm]γc[(34π)ρieρnorm]−γe[(34π)ρieρ¯]γe−1

 

=

[(34π)ρicρ¯]γc−1(ρicρie)(ρnormρ¯)γe−γc

 

=

[(34π)ρicρ¯]γc−1(ρicρie)(RRnorm)3(γe−γc)

Hence, we can write the normalized (and dimensionless) free energy as,

𝔊*

=

−3⋅𝔣WM5(RRnorm)−1+{νscore(γc−1)+(1−ν)senv(γe−1)(ρicρie)}[(34π)ρicρ¯]γc−1[RRnorm]−3(γc−1).

Keep in mind that, if the envelope and core both have uniform (but different) densities, then ρic=ρc, ρie=ρe, and

ρcρ¯=νq3;ρeρ¯=1−ν1−q3;ρeρc=q3(1−ν)ν(1−q3).

Free Energy and Its Derivatives

Now, the free energy can be written as,

𝔊

=

Utot+W

 

=

[23(γc−1)]Score+[23(γe−1)]Senv+W

 

=

[23(γc−1)]CcoreR3−3γc+[23(γe−1)]CenvR3−3γe−AR−1.

The first derivative of the free energy with respect to radius is, then,

d𝔊dR

=

−2CcoreR2−3γc−2CenvR2−3γe+AR−2.

And the second derivative is,

d2𝔊dR2

=

−2(2−3γc)CcoreR1−3γc−2(2−3γe)CenvR1−3γe−2AR−3.

 

=

2R2[(3γc−2)CcoreR3−3γc+(3γe−2)CenvR3−3γe−AR−1]

 

=

2R2[(3γc−2)Score+(3γe−2)Senv+W].

Equilibrium

The radius, Req, of the equilibrium configuration(s) is determined by setting the first derivative of the free energy to zero. Hence,

0

=

2CcoreReq2−3γc+2CenvReq2−3γe−AReq−2

 

=

Req−1[2CcoreReq3−3γc+2CenvReq3−3γe−AReq−1]

 

=

Req−1[2Score+2Senv+W]

⇒2Stot+W

=

0.

This is the familiar statement of virial equilibrium. From it we should always be able to derive the radius of equilibrium configurations.

Stability

To assess the relative stability of an equilibrium configuration, we need to determine the sign of the second derivative of the free energy, evaluated at the equilibrium radius. If the sign of the second derivative is positive, the system is dynamically stable; if the sign is negative, he system is dynamically unstable. Using the above statement of virial equilibrium, that is, setting,

2Stot+W

=

0,

⇒Senv

=

−Score−W2,

we obtain,

d2𝔊dR2|eq

=

2Req2[(3γc−2)Score+W−(3γe−2)(Score+W2)]eq

 

=

2Req2[3(γc−γe)Score+(2−32γe)W]eq

 

=

6Req2[(γc−γe)Score+12(43−γe)W]eq

 

=

6Req2[−W2(γe−43)−(γe−γc)Score]eq.

So, if when evaluated at the equilibrium state, the expression inside of the square brackets of this last expression is negative, the equilibrium configuration will be dynamically unstable. We have chosen to write the expression in this particular final form because we generally will be interested in bipolytropes for which the adiabatic exponent of the envelope is greater than 4/3 and the adiabatic exponent of the core is less than or equal to 4/3 — that is, γe>4/3≥γc. Hence, because the gravitational potential energy, W, is intrinsically negative, the system will be dynamically unstable only if the second term (involving Score) is greater in magnitude than the first term (involving W).

It is worth noting that, instead of drawing upon Score and W to define the stability condition, we could have used an appropriate combination of Senv and W, or the Score and Senv pair. Also, for example, because the virial equilibrium condition is Stot=−W/2, it is easy to see that the following inequality also equivalently defines stability:

Stot(γe−43)−(γe−γc)Score

>

0.

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