SSC/BipolytropeGeneralization/Pt2

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Bipolytrope Generalization (Pt 2)[edit]


Part I:  Bipolytrope Generalization

 


Part II:  Derivations

 


Part III:  Examples

 


Part IV:  Best of the Best

 



Material that appears after this point in our presentation is under development and therefore
may contain incorrect mathematical equations and/or physical misinterpretations.
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Detailed Derivations[edit]

Dividing the free-energy expression through by Enorm generates,

𝔊*𝔊Enorm

=

35(GMtot2Enorm)(1R)𝔣WM+[νscore(γc1)][MtotKcρicγc1Enorm]

 

 

+[(1ν)senv(γe1)][MtotKeρieγe1Enorm]

 

=

3𝔣WM5[KcG(3γc4)Mtot2(3γc4)G3γc3Mtot5γc6]1/(3γc4)(1R)

 

 

+[νscore(γc1)][KcMtot3γc4Kc3γc4G3γc3Mtot5γc6]1/(3γc4)(ρicρ¯)γc1[3Mtot4πR3]γc1

 

 

+[(1ν)senv(γe1)][KcMtot3γc4Ke3γc4G3γc3Mtot5γc6]1/(3γc4)(ρieρ¯)γe1[3Mtot4πR3]γe1

 

=

3𝔣WM5(RnormR)

 

 

+[νscore(γc1)](3Mtot4π)γc1[Kc3γc3G3γc3Mtot2γc2]1/(3γc4)[RnormR]3(γc1)[(KcG)Mtotγc2]3(γc1)/(3γc4)(ρicρ¯)γc1

 

 

+[(1ν)senv(γe1)](3Mtot4π)γe1[Kc3γc3(Ke/Kc)3γc4G3γc3Mtot2γc2]1/(3γc4)[RnormR]3(γe1)[(KcG)Mtotγc2]3(γe1)/(3γc4)(ρieρ¯)γe1

 

=

3𝔣WM5(RnormR)

 

 

+[νscore(γc1)](34π)γc1[Mtot3γc4](γc1)/(3γc4)[Mtot2](γc1)/(3γc4)[Mtot3γc+6](γc1)/(3γc4)[RnormR]3(γc1)(ρicρ¯)γc1

 

 

+[(1ν)senv(γe1)](34π)γe1(KeKc)[Mtot2(γe1)2(γc1)]1/(3γc4)[RnormR]3(γe1)[(KcG)(γc1)(γe1)]3/(3γc4)(ρieρ¯)γe1

 

=

3𝔣WM5(RRnorm)1+νscore(γc1)[(34π)ρicρ¯]γc1[RRnorm]3(γc1)

 

 

+(1ν)senv(γe1)(KeKc)[Kc3G3Mtot2](γcγe)/(3γc4)[(34π)ρieρ¯]γe1[RRnorm]3(γe1).

We also want to ensure that envelope pressure matches the core pressure at the interface. This means,

Keρieγe

=

Kcρicγc

KeKc

=

ρicγcρieγe

 

=

[ρicρnorm]γc[ρieρnorm]γeρnormγcγe

 

=

[ρicρnorm]γc[ρieρnorm]γe{34π[G3Mtot2Kc3]1/(3γc4)}γcγe

KeKc[Kc3G3Mtot2](γcγe)/(3γc4)[(34π)ρieρ¯]γe1

=

[(34π)ρicρnorm]γc[(34π)ρieρnorm]γe[(34π)ρieρ¯]γe1

 

=

[(34π)ρicρ¯]γc1(ρicρie)(ρnormρ¯)γeγc

 

=

[(34π)ρicρ¯]γc1(ρicρie)(RRnorm)3(γeγc)

Hence, we can write the normalized (and dimensionless) free energy as,

𝔊*

=

3𝔣WM5(RRnorm)1+{νscore(γc1)+(1ν)senv(γe1)(ρicρie)}[(34π)ρicρ¯]γc1[RRnorm]3(γc1).

Keep in mind that, if the envelope and core both have uniform (but different) densities, then ρic=ρc, ρie=ρe, and

ρcρ¯=νq3;ρeρ¯=1ν1q3;ρeρc=q3(1ν)ν(1q3).

Free Energy and Its Derivatives[edit]

Now, the free energy can be written as,

𝔊

=

Utot+W

 

=

[23(γc1)]Score+[23(γe1)]Senv+W

 

=

[23(γc1)]CcoreR33γc+[23(γe1)]CenvR33γeAR1.

The first derivative of the free energy with respect to radius is, then,

d𝔊dR

=

2CcoreR23γc2CenvR23γe+AR2.

And the second derivative is,

d2𝔊dR2

=

2(23γc)CcoreR13γc2(23γe)CenvR13γe2AR3.

 

=

2R2[(3γc2)CcoreR33γc+(3γe2)CenvR33γeAR1]

 

=

2R2[(3γc2)Score+(3γe2)Senv+W].

Equilibrium[edit]

The radius, Req, of the equilibrium configuration(s) is determined by setting the first derivative of the free energy to zero. Hence,

0

=

2CcoreReq23γc+2CenvReq23γeAReq2

 

=

Req1[2CcoreReq33γc+2CenvReq33γeAReq1]

 

=

Req1[2Score+2Senv+W]

2Stot+W

=

0.

This is the familiar statement of virial equilibrium. From it we should always be able to derive the radius of equilibrium configurations.

Stability[edit]

To assess the relative stability of an equilibrium configuration, we need to determine the sign of the second derivative of the free energy, evaluated at the equilibrium radius. If the sign of the second derivative is positive, the system is dynamically stable; if the sign is negative, he system is dynamically unstable. Using the above statement of virial equilibrium, that is, setting,

2Stot+W

=

0,

Senv

=

ScoreW2,

we obtain,

d2𝔊dR2|eq

=

2Req2[(3γc2)Score+W(3γe2)(Score+W2)]eq

 

=

2Req2[3(γcγe)Score+(232γe)W]eq

 

=

6Req2[(γcγe)Score+12(43γe)W]eq

 

=

6Req2[W2(γe43)(γeγc)Score]eq.

So, if when evaluated at the equilibrium state, the expression inside of the square brackets of this last expression is negative, the equilibrium configuration will be dynamically unstable. We have chosen to write the expression in this particular final form because we generally will be interested in bipolytropes for which the adiabatic exponent of the envelope is greater than 4/3 and the adiabatic exponent of the core is less than or equal to 4/3 — that is, γe>4/3γc. Hence, because the gravitational potential energy, W, is intrinsically negative, the system will be dynamically unstable only if the second term (involving Score) is greater in magnitude than the first term (involving W).

It is worth noting that, instead of drawing upon Score and W to define the stability condition, we could have used an appropriate combination of Senv and W, or the Score and Senv pair. Also, for example, because the virial equilibrium condition is Stot=W/2, it is easy to see that the following inequality also equivalently defines stability:

Stot(γe43)(γeγc)Score

>

0.

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