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===10<sup>th</sup> Try=== ====Repeating Key Relations==== <table border="0" cellpadding="5" align="center"> <tr> <td align="left"><font color="orange"><b>Density:</b></font></td> <td align="right"> <math>\frac{\rho(\varpi, z)}{\rho_c}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[1 - \chi^2 - \zeta^2(1-e^2)^{-1} \biggr] \, ,</math> </td> </tr> <tr> <td align="left"><font color="orange"><b>Gravitational Potential:</b></font></td> <td align="right"> <math>\frac{ \Phi_\mathrm{grav}(\varpi,z)}{(-\pi G\rho_c a_\ell^2)} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{1}{2} I_\mathrm{BT} - A_\ell \chi^2 - A_s \zeta^2 + \frac{1}{2}\biggl[(A_{s s} a_\ell^2) \zeta^4 + 2(A_{\ell s}a_\ell^2 )\chi^2 \zeta^2 + (A_{\ell \ell} a_\ell^2) \chi^4 \biggr] \, . </math> </td> </tr> </tr> <tr> <td align="left"><font color="orange"><b>Vertical Pressure Gradient:</b></font></td> <td align="right"><math>\biggl[\frac{1}{(\pi G\rho_c^2 a_\ell^2)} \biggr] \frac{\partial P}{\partial \zeta}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{\rho}{\rho_c} \cdot \biggl[ 2A_{\ell s}a_\ell^2 \chi^2\zeta - 2A_s \zeta + 2A_{ss} a_\ell^2 \zeta^3 \biggr] </math> </td> </tr> </table> From the [[#Starting_Key_Relations|above (9<sup>th</sup> Try) examination]] of the vertical pressure gradient, we determined that a reasonably good approximation for the normalized pressure throughout the configuration is given by the expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\biggl[\frac{1}{(\pi G\rho_c^2 a_\ell^2)} \biggr] \int \biggl[\frac{\partial P}{\partial \zeta}\biggr] d\zeta </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[-A_s \zeta^2 + \frac{1}{2}A_{ss}a_\ell^2 \zeta^4 + \frac{1}{2}(1-e^2)^{-1}A_s\zeta^4 - \frac{1}{3}(1-e^2)^{-1}A_{ss} a_\ell^2 \zeta^6 \biggr]\chi^0 + \biggl[ A_{\ell s}a_\ell^2 \zeta^2 + A_s\zeta^2 - \frac{1}{2}A_{ss}a_\ell^2 \zeta^4 - \frac{1}{2}(1-e^2)^{-1}(A_{\ell s}a_\ell^2 \zeta^4 ) \biggr]\chi^2 + \biggl[- A_{\ell s}a_\ell^2 \zeta^2 \biggr]\chi^4 + ~\mathrm{const.} </math> </td> </tr> </table> If we set <math>\chi = 0</math> — that is, if we look along the vertical axis — this approximation should be particularly good, resulting in the expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>P_z \equiv \biggl\{ \biggl[\frac{1}{(\pi G\rho_c^2 a_\ell^2)} \biggr] \int \biggl[\frac{\partial P}{\partial \zeta}\biggr] d\zeta \biggr\}_{\chi=0}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math>P_c^* - A_s \zeta^2 + \frac{1}{2}A_{ss}a_\ell^2 \zeta^4 + \frac{1}{2}(1-e^2)^{-1}A_s\zeta^4 - \frac{1}{3}(1-e^2)^{-1}A_{ss} a_\ell^2 \zeta^6 \, . </math> </td> </tr> </table> <table border="1" align="center" cellpadding="8" width="80%"><tr><td align="left"> Note that in the limit that <math>z \rightarrow a_s</math> — that is, at the pole along the vertical (symmetry) axis where the <math>P_z</math> should drop to zero — we should set <math>\zeta \rightarrow (1 - e^2)^{1 / 2}</math>. This allows us to determine the central pressure. <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>P_c^* </math></td> <td align="center"><math>=</math></td> <td align="left"> <math>A_s (1-e^2) - \frac{1}{2}A_{ss}a_\ell^2 (1-e^2)^2 - \frac{1}{2}(1-e^2)^{-1}A_s(1-e^2)^2 + \frac{1}{3}(1-e^2)^{-1}A_{ss} a_\ell^2 (1-e^2)^3 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math>A_s (1-e^2) - \frac{1}{2}A_s(1-e^2) + \frac{1}{3}A_{ss} a_\ell^2 (1-e^2)^2 - \frac{1}{2}A_{ss}a_\ell^2 (1-e^2)^2 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math>\frac{1}{2}A_s(1-e^2) - \frac{1}{6}A_{ss} a_\ell^2 (1-e^2)^2 \, . </math> </td> </tr> </table> </td></tr></table> This means that, along the vertical axis, the pressure gradient is, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>P_z \equiv \biggl\{ \biggl[\frac{1}{(\pi G\rho_c^2 a_\ell^2)} \biggr] \int \biggl[\frac{\partial P}{\partial \zeta}\biggr] d\zeta \biggr\}_{\chi=0}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math>P_c^* - A_s \zeta^2 + \frac{1}{2}A_{ss}a_\ell^2 \zeta^4 + \frac{1}{2}(1-e^2)^{-1}A_s\zeta^4 - \frac{1}{3}(1-e^2)^{-1}A_{ss} a_\ell^2 \zeta^6 \, . </math> </td> </tr> </table> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\frac{\partial P_z}{\partial\zeta}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math>- 2A_s \zeta + 2A_{ss}a_\ell^2 \zeta^3 + 2(1-e^2)^{-1}A_s\zeta^3 - 2(1-e^2)^{-1}A_{ss} a_\ell^2 \zeta^5 \, . </math> </td> </tr> </table> This should match the more general "<font color="orange">vertical pressure gradient</font>" expression when we set, <math>\chi=0</math>, that is, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\biggl\{ \biggl[\frac{1}{(\pi G\rho_c^2 a_\ell^2)} \biggr] \frac{\partial P}{\partial \zeta} \biggr\}_{\chi=0}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ 1 - \cancelto{0}{\chi^2} - \zeta^2(1-e^2)^{-1}\biggr]\cdot \biggl[ 2A_{\ell s}a_\ell^2 \zeta \cancelto{0}{\chi^2} - 2A_s \zeta + 2A_{ss} a_\ell^2 \zeta^3 \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[- 2A_s \zeta + 2A_{ss} a_\ell^2 \zeta^3 \biggr] + \zeta^2(1-e^2)^{-1} \biggl[2A_s \zeta - 2A_{ss} a_\ell^2 \zeta^3 \biggr] </math> </td> </tr> </table> <b><font color="red">Yes! The expressions match!</font></b> ====Shift to ξ<sub>1</sub> Coordinate==== In an [[ParabolicDensity/Axisymmetric/Structure/Try1thru7#Setup|accompanying chapter]], we defined the coordinate, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\biggl(\frac{\xi_1}{a_s}\biggr)^2</math></td> <td align="center"><math>\equiv</math></td> <td align="left"> <math> \biggl(\frac{\varpi}{a_\ell}\biggr)^2 + \biggl(\frac{z}{a_s}\biggr)^2 = \chi^2 + \zeta^2(1-e^2)^{-1} \, . </math> </td> </tr> </table> Given that we want the pressure to be constant on <math>\xi_1</math> surfaces, it seems plausible that <math>\zeta^2</math> should be replaced by <math>(1-e^2)(\xi_1/a_s)^2 = [(1-e^2)\chi^2 + \zeta^2]</math> in the expression for <math>P_z</math>. That is, we might expect the expression for the pressure at any point in the meridional plane to be, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>P_\mathrm{test01}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math>P_c^* - A_s \biggl[ (1-e^2)\chi^2 + \zeta^2 \biggr]^1 + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]\biggl[ (1-e^2)\chi^2 + \zeta^2 \biggr]^2 - \frac{1}{3}(1-e^2)^{-1}A_{ss} a_\ell^2 \biggl[ (1-e^2)\chi^2 + \zeta^2 \biggr]^3 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math>P_c^* - A_s \biggl[ (1-e^2)\chi^2 + \zeta^2 \biggr]^1 + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]\biggl[ (1-e^2)^2\chi^4 + 2(1-e^2)\chi^2\zeta^2 + \zeta^4 \biggr] - \frac{1}{3}(1-e^2)^{-1}A_{ss} a_\ell^2 \biggl[ (1-e^2)\chi^2 + \zeta^2 \biggr]\biggl[ (1-e^2)^2\chi^4 + 2(1-e^2)\chi^2\zeta^2 + \zeta^4 \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> P_c^* - A_s \biggl[ (1-e^2)\chi^2 + \zeta^2 \biggr] + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]\biggl[ (1-e^2)^2\chi^4 + 2(1-e^2)\chi^2\zeta^2 + \zeta^4 \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> - \frac{1}{3} A_{ss} a_\ell^2 \biggl[ (1-e^2)^2\chi^6 + 2(1-e^2)\chi^4\zeta^2 + \chi^2\zeta^4 \biggr] - \frac{1}{3}A_{ss} a_\ell^2 \biggl[ (1-e^2)\chi^4\zeta^2 + 2\chi^2\zeta^4 + (1-e^2)^{-1}\zeta^6 \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \chi^0 \biggl\{ P_c^* -A_s\zeta^2 + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]\zeta^4 - \frac{1}{3}A_{ss} a_\ell^2(1-e^2)^{-1}\zeta^6 \biggr\} + \chi^2 \biggl\{ -A_s(1-e^2) + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]2(1-e^2)\zeta^2 -\frac{1}{3}A_{ss}a_\ell^2\zeta^4 - \frac{2}{3}A_{ss} a_\ell^2\zeta^4 \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> + \chi^4 \biggl\{ \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr](1-e^2)^2 - \frac{2}{3}A_{ss} a_\ell^2(1-e^2)\zeta^2 - \frac{1}{3}A_{ss} a_\ell^2(1-e^2)\zeta^2 \biggr\} + \chi^6 \biggl\{ - \frac{1}{3} A_{ss} a_\ell^2 (1-e^2)^2 \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \chi^0 \biggl\{ P_c^* -A_s\zeta^2 + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]\zeta^4 - \frac{1}{3}A_{ss} a_\ell^2(1-e^2)^{-1}\zeta^6 \biggr\} + \chi^2 \biggl\{ -A_s(1-e^2) + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]2(1-e^2)\zeta^2 - A_{ss}a_\ell^2\zeta^4 \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> + \chi^4 \biggl\{ \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr](1-e^2)^2 - A_{ss} a_\ell^2(1-e^2)\zeta^2 \biggr\} + \chi^6 \biggl\{ - \frac{1}{3} A_{ss} a_\ell^2 (1-e^2)^2 \biggr\} </math> </td> </tr> </table> <table border="1" align="center" cellpadding="8"> <tr> <td align="center" width="6%"> </td> <td align="center" width="47%">Integration over <math>\zeta</math></td> <td align="center">Pressure Guess</td> </tr> <tr> <td align="center"><math>\chi^0</math></td> <td align="right"><math>-A_s \zeta^2 + \frac{1}{2}A_{ss}a_\ell^2 \zeta^4 + \frac{1}{2}(1-e^2)^{-1}A_s\zeta^4 - \frac{1}{3}(1-e^2)^{-1}A_{ss} a_\ell^2 \zeta^6 </math></td> <td align="left"> <math> P_c^* -A_s\zeta^2 + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]\zeta^4 - \frac{1}{3}A_{ss} a_\ell^2(1-e^2)^{-1}\zeta^6 </math> </td> </tr> <tr> <td align="center"><math>\chi^2</math></td> <td align="right"> <math>A_{\ell s}a_\ell^2 \zeta^2 + A_s\zeta^2 - \frac{1}{2}A_{ss}a_\ell^2 \zeta^4 - \frac{1}{2}(1-e^2)^{-1}(A_{\ell s}a_\ell^2 \zeta^4 )</math> </td> <td align="left"> <math> -A_s(1-e^2) + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]2(1-e^2)\zeta^2 - A_{ss}a_\ell^2\zeta^4 </math> </td> </tr> <tr> <td align="center"><math>\chi^4</math></td> <td align="right"> <math>- A_{\ell s}a_\ell^2 \zeta^2 </math> </td> <td align="left"> <math> \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr](1-e^2)^2 - A_{ss} a_\ell^2(1-e^2)\zeta^2 </math> </td> </tr> <tr> <td align="center"><math>\chi^6</math></td> <td align="right"> none </td> <td align="left"> <math> - \frac{1}{3} A_{ss} a_\ell^2 (1-e^2)^2 </math> </td> </tr> </table> ====Compare Vertical Pressure Gradient Expressions==== From our [[#Starting_Key_Relations|above (9<sup>th</sup> try) derivation]] we know that the vertical pressure gradient is given by the expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\biggl[\frac{1}{(\pi G\rho_c^2 a_\ell^2)} \biggr] \frac{\partial P}{\partial \zeta}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[1 - \chi^2 - \zeta^2(1-e^2)^{-1} \biggr] \biggl[ 2A_{\ell s}a_\ell^2 \chi^2\zeta - 2A_s \zeta + 2A_{ss} a_\ell^2 \zeta^3 \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ (2A_{\ell s}a_\ell^2 \chi^2 - 2A_s ) - (2A_{\ell s}a_\ell^2 \chi^4 - 2A_s \chi^2)\biggr]\zeta + \biggl[ 2A_{ss} a_\ell^2 - 2A_{ss} a_\ell^2 \chi^2 - (1-e^2)^{-1}(2A_{\ell s}a_\ell^2 \chi^2 - 2A_s )\biggr]\zeta^3 + \biggl[ - (1-e^2)^{-1}2A_{ss} a_\ell^2 \biggr] \zeta^5 \, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ 2A_s (\chi^2-1) + 2A_{\ell s}a_\ell^2 (1 - \chi^2)\chi^2 \biggr]\zeta + \biggl[ 2A_{ss} a_\ell^2(1 - \chi^2 ) - 2A_{\ell s}a_\ell^2 (1-e^2)^{-1}\chi^2 + 2(1-e^2)^{-1}A_s \biggr]\zeta^3 + \biggl[ - 2A_{ss} a_\ell^2 (1-e^2)^{-1}\biggr] \zeta^5 \, . </math> </td> </tr> </table> By comparison, the vertical derivative of our "test01" pressure expression gives, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>P_\mathrm{test01}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \chi^0 \biggl\{ P_c^* -A_s\zeta^2 + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]\zeta^4 - \frac{1}{3}A_{ss} a_\ell^2(1-e^2)^{-1}\zeta^6 \biggr\} + \chi^2 \biggl\{ -A_s(1-e^2) + \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]2(1-e^2)\zeta^2 - A_{ss}a_\ell^2\zeta^4 \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> + \chi^4 \biggl\{ \frac{1}{2}\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr](1-e^2)^2 - A_{ss} a_\ell^2(1-e^2)\zeta^2 \biggr\} + \chi^6 \biggl\{ - \frac{1}{3} A_{ss} a_\ell^2 (1-e^2)^2 \biggr\} </math> </td> </tr> <tr> <td align="right"><math>\Rightarrow ~~~ \frac{\partial P_\mathrm{test01}}{\partial \zeta}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \chi^0 \biggl\{ -2A_s\zeta + 2\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr]\zeta^3 - 2A_{ss} a_\ell^2(1-e^2)^{-1}\zeta^5 \biggr\} + \chi^2 \biggl\{ 2\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr](1-e^2)\zeta - 4A_{ss}a_\ell^2\zeta^3 \biggr\} + \chi^4 \biggl\{ - 2A_{ss} a_\ell^2(1-e^2)\zeta \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \zeta^1\biggl\{ - 2A_s + 2\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr](1-e^2)\chi^2 - 2A_{ss} a_\ell^2(1-e^2)\chi^4 \biggr\} + \zeta^3\biggl\{ 2\biggl[ A_{ss}a_\ell^2 + (1-e^2)^{-1}A_s\biggr] - 4A_{ss}a_\ell^2\chi^2 \biggr\} + \zeta^5\biggl\{ - 2A_{ss} a_\ell^2(1-e^2)^{-1} \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \zeta^1\biggl\{ 2A_s (\chi^2- 1) + 2A_{ss}a_\ell^2(1-e^2)\chi^2 (1-\chi^2) \biggr\} + \zeta^3\biggl\{ 2A_{ss}a_\ell^2(1-2\chi^2) + 2(1-e^2)^{-1}A_s \biggr\} + \zeta^5\biggl\{ - 2A_{ss} a_\ell^2(1-e^2)^{-1} \biggr\} </math> </td> </tr> </table> Instead, try … <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\frac{P_\mathrm{test02}}{P_c}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> p_2 \biggl(\frac{\rho}{\rho_c}\biggr)^2 + p_3\biggl(\frac{\rho}{\rho_c}\biggr)^3 </math> </td> </tr> <tr> <td align="right"><math>\Rightarrow ~~~ \frac{\partial}{\partial \zeta}\biggl[\frac{P_\mathrm{test02}}{P_c}\biggr]</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> 2p_2\biggl(\frac{\rho}{\rho_c}\biggr)\frac{\partial}{\partial\zeta}\biggl[ \frac{\rho}{\rho_c} \biggr] + 3p_3\biggl(\frac{\rho}{\rho_c}\biggr)^2 \frac{\partial}{\partial\zeta}\biggl[ \frac{\rho}{\rho_c} \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl(\frac{\rho}{\rho_c}\biggr)\biggl\{2p_2 + 3p_3\biggl(\frac{\rho}{\rho_c}\biggr) \biggr\} \frac{\partial}{\partial\zeta}\biggl[ \frac{\rho}{\rho_c} \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl(\frac{\rho}{\rho_c}\biggr)\biggl\{2p_2 + 3p_3\biggl[1 - \chi^2 - \zeta^2(1-e^2)^{-1} \biggr] \biggr\} \frac{\partial}{\partial\zeta}\biggl[ 1 - \chi^2 - \zeta^2(1-e^2)^{-1} \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl(\frac{\rho}{\rho_c}\biggr)\biggl\{(2p_2 + 3p_3) - 3p_3\chi^2 - 3p_3\zeta^2(1-e^2)^{-1} \biggr\} \biggl[ - 2\zeta(1-e^2)^{-1} \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl(\frac{\rho}{\rho_c}\biggr)(1-e^2)^{-2}\biggl\{ 6p_3\chi^2\zeta(1-e^2) - 2(2p_2 + 3p_3)(1-e^2)\zeta + 6p_3\zeta^3 \biggr\} </math> </td> </tr> </table> Compare the term inside the curly braces with the term, from the beginning of this subsection, inside the square brackets, namely, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math> 2A_{\ell s}a_\ell^2 \chi^2\zeta - 2A_s \zeta + 2A_{ss} a_\ell^2 \zeta^3 </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{2}{e^4} \biggl[(3-e^2) - \Upsilon \biggr]\chi^2\zeta - \biggl[\frac{4}{e^2}\biggl(1-\frac{1}{3}\Upsilon\biggr)\biggr] \zeta + \frac{4}{3e^4}\biggl[\frac{4e^2-3}{(1-e^2)} + \Upsilon \biggr] \zeta^3 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{1}{3e^4(1-e^2)}\biggl\{ 6 \biggl[(3-e^2) - \Upsilon \biggr](1-e^2)\chi^2\zeta - \biggl[12e^2\biggl(1-\frac{1}{3}\Upsilon\biggr)\biggr](1-e^2) \zeta + 4\biggl[(4e^2-3) + \Upsilon \biggr] \zeta^3 \biggr\} \, . </math> </td> </tr> </table> <font color="red"><b>Pretty Close!!</b></font> <table border="1" align="center" width="80%" cellpadding="5"><tr><td align="left"> Alternatively: according to the third term, we need to set, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math> 6p_3 </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> 4\biggl[(4e^2-3) + \Upsilon \biggr] </math> </td> </tr> <tr> <td align="right"><math> \Rightarrow ~~~ \Upsilon </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{3}{2}p_3 + (3 - 4e^2) </math> </td> </tr> </table> in which case, the first coefficient must be given by the expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math> \biggl[(3-e^2) - \Upsilon \biggr] </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> (3-e^2) - \frac{3}{2}p_3 + (4e^2 - 3 ) \biggr] = \biggl[ 3e^2 - \frac{3}{2}p_3 \biggr] \, . </math> </td> </tr> </table> And, from the second coefficient, we find, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math> 2(2p_2 + 3p_3) </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[12e^2\biggl(1-\frac{1}{3}\Upsilon\biggr)\biggr]</math> </td> </tr> <tr> <td align="right"><math> \Rightarrow ~~~ 2p_2 </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> 2e^2\biggl(3-\Upsilon\biggr) - 3p_3 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> - 3p_3 + 6e^2 - 2e^2\biggl[ \frac{3}{2}p_3 + (3 - 4e^2) \biggr]</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> - 3p_3 + 6e^2 - \biggl[ 3e^2 p_3 + 6e^2 - 8e^4 \biggr]</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 8e^4 - 3p_3(1+e^2) \, ;</math> </td> </tr> </table> or, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>p_2</math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 4e^4 - (1+e^2)\biggl[(4e^2-3) + \Upsilon \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 4e^4 - (1+e^2)(4e^2-3) - (1+e^2)\Upsilon </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 4e^4 - [4e^2-3 + 4e^4-3e^2 ] - (1+e^2)\Upsilon </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 3 - e^2 - (1+e^2)\Upsilon </math> </td> </tr> </table> ---- SUMMARY: <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\frac{P_\mathrm{test02}}{P_c}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> p_2 \biggl(\frac{\rho}{\rho_c}\biggr)^2 + p_3\biggl(\frac{\rho}{\rho_c}\biggr)^3 \, , </math> </td> </tr> <tr> <td align="right"> <math>p_2</math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 3 - e^2 - (1+e^2)\Upsilon = e^4(A_{\ell s}a_\ell^2) - e^2\Upsilon \, ,</math> </td> </tr> <tr> <td align="right"><math> p_3 </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{2}{3}\biggl[(4e^2-3) + \Upsilon \biggr] = e^4(A_{ss}a_\ell^2) + \frac{2}{3}e^2\Upsilon \, . </math> </td> </tr> </table> </td></tr></table> <table border="1" align="center" width="80%" cellpadding="5"><tr><td align="left"> Note: according to the first term, we need to set, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math> p_3 </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[(3-e^2) - \Upsilon \biggr] </math> </td> </tr> <tr> <td align="right"><math> \Rightarrow ~~~ \Upsilon </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[(3-e^2) - p_3 \biggr] \, , </math> </td> </tr> </table> in which case, the third coefficient must be given by the expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math> 4\biggl[(4e^2-3) + \Upsilon \biggr] </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> 4\biggl[(4e^2-3) + (3-e^2) - p_3 \biggr] = 4\biggl[3e^2- p_3 \biggr] \, . </math> </td> </tr> </table> And, from the second coefficient, we find, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math> 2(2p_2 + 3p_3) </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[12e^2\biggl(1-\frac{1}{3}\Upsilon\biggr)\biggr]</math> </td> </tr> <tr> <td align="right"><math> \Rightarrow ~~~ 2p_2 </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> 2e^2\biggl(3-\Upsilon\biggr) - 3p_3 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 2e^2\biggl[3-[(3-e^2) - p_3]\biggr] - 3p_3</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 2e^2\biggl[e^2 + p_3\biggr] - 3p_3</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 2e^4 + (2e^2 - 3)p_3 \, ; </math> </td> </tr> </table> or, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> 2p_2 </math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 2e^4 + (2e^2 - 3)\biggl[(3-e^2) - \Upsilon \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 2e^4 + (2e^2 - 3)(3-e^2) - (2e^2 - 3)\Upsilon </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 2e^4 + (6e^2 - 2e^4 -9 +3e^2) - (2e^2 - 3)\Upsilon </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 9(e^2 -1 ) - (2e^2 - 3)\Upsilon </math> </td> </tr> </table> </td></tr></table> Better yet, try … <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\frac{P_\mathrm{test03}}{P_c}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> p_2 \biggl(\frac{\rho}{\rho_c}\biggr)^2 \biggl[ 1 - \beta\biggl(1 - \frac{\rho}{\rho_c} \biggr)\biggr] = p_2 \biggl(\frac{\rho}{\rho_c}\biggr)^2 \biggl[ (1 - \beta) + \beta\biggl(\frac{\rho}{\rho_c} \biggr)\biggr] </math> </td> </tr> <tr> <td align="right"><math>\Rightarrow ~~~ \frac{\partial}{\partial \zeta}\biggl[\frac{P_\mathrm{test03}}{P_c}\biggr]</math></td> <td align="center"><math>=</math></td> <td align="left"> <math>\cdots</math> </td> </tr> </table> where, in the case of a [[SSC/Structure/OtherAnalyticModels#Pressure|spherically symmetric parabolic-density configuration]], <math>\beta = 1 / 2</math>. Well … this wasn't a bad idea, but as it turns out, this "test03" expression is no different from the "test02" guess. Specifically, the "test03" expression can be rewritten as, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\frac{P_\mathrm{test03}}{P_c}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> p_2 (1 - \beta)\biggl(\frac{\rho}{\rho_c}\biggr)^2 + p_2\beta \biggl(\frac{\rho}{\rho_c}\biggr)^3 \, , </math> </td> </tr> </table> which has the same form as the "test02" expression. ====Test04==== From above, we understand that, analytically, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\biggl[\frac{1}{(\pi G\rho_c^2 a_\ell^2)} \biggr] \frac{\partial P}{\partial \zeta}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[1 - \chi^2 - \zeta^2(1-e^2)^{-1} \biggr] \biggl[ 2A_{\ell s}a_\ell^2 \chi^2\zeta - 2A_s \zeta + 2A_{ss} a_\ell^2 \zeta^3 \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ (2A_{\ell s}a_\ell^2 \chi^2 - 2A_s ) - (2A_{\ell s}a_\ell^2 \chi^4 - 2A_s \chi^2)\biggr]\zeta + \biggl[ 2A_{ss} a_\ell^2 - 2A_{ss} a_\ell^2 \chi^2 - (1-e^2)^{-1}(2A_{\ell s}a_\ell^2 \chi^2 - 2A_s )\biggr]\zeta^3 + \biggl[ - (1-e^2)^{-1}2A_{ss} a_\ell^2 \biggr] \zeta^5 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ 2A_s (\chi^2-1) + 2A_{\ell s}a_\ell^2 (1 - \chi^2)\chi^2 \biggr]\zeta + \biggl[ 2A_{ss} a_\ell^2(1 - \chi^2 ) - 2A_{\ell s}a_\ell^2 (1-e^2)^{-1}\chi^2 + 2(1-e^2)^{-1}A_s \biggr]\zeta^3 + \biggl[ - 2A_{ss} a_\ell^2 (1-e^2)^{-1}\biggr] \zeta^5 \, . </math> </td> </tr> </table> Also from above, we have shown that if, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\frac{P_\mathrm{test02}}{P_c}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> p_2 \biggl(\frac{\rho}{\rho_c}\biggr)^2 + p_3\biggl(\frac{\rho}{\rho_c}\biggr)^3 </math> </td> </tr> </table> <table border="1" width="60%" align="center" cellpadding="5"><tr><td align="left"> SUMMARY from test02: <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>p_2</math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 3 - e^2 - (1+e^2)\Upsilon = e^4(A_{\ell s}a_\ell^2) - e^2\Upsilon \, ,</math> </td> </tr> <tr> <td align="right"><math> p_3 </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{2}{3}\biggl[(4e^2-3) + \Upsilon \biggr] = e^4(A_{ss}a_\ell^2) + \frac{2}{3}e^2\Upsilon \, . </math> </td> </tr> </table> </td></tr></table> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\Rightarrow ~~~ \frac{\partial}{\partial \zeta}\biggl[\frac{P_\mathrm{test02}}{P_c}\biggr]</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl(\frac{\rho}{\rho_c}\biggr)(1-e^2)^{-2}\biggl\{ 6p_3\chi^2\zeta(1-e^2) - 2(2p_2 + 3p_3)(1-e^2)\zeta + 6p_3\zeta^3 \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl(\frac{\rho}{\rho_c}\biggr)(1-e^2)^{-2}\biggl\{ 6\biggl[ e^4(A_{ss}a_\ell^2) + \frac{2}{3}e^2\Upsilon \biggr]\chi^2\zeta(1-e^2) - 2\biggl[2e^4(A_{\ell s}a_\ell^2) + 3e^4(A_{ss}a_\ell^2) \biggr](1-e^2)\zeta + 6\biggl[ e^4(A_{ss}a_\ell^2) + \frac{2}{3}e^2\Upsilon \biggr]\zeta^3 \biggr\} </math> </td> </tr> </table> ---- Here (test04), we add a term that is linear in the normalized density, which means, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"><math>\frac{P_\mathrm{test04}}{P_c}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{P_\mathrm{test02}}{P_c} + p_1 \biggl(\frac{\rho}{\rho_c}\biggr) </math> </td> </tr> <tr> <td align="right"><math>\Rightarrow ~~~ \frac{\partial}{\partial \zeta}\biggl[\frac{P_\mathrm{test04}}{P_c}\biggr]</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{\partial}{\partial \zeta}\biggl[\frac{P_\mathrm{test02}}{P_c}\biggr] + \frac{\partial}{\partial \zeta}\biggl[p_1 \biggl(\frac{\rho}{\rho_c}\biggr)\biggr] = \frac{\partial}{\partial \zeta}\biggl[\frac{P_\mathrm{test02}}{P_c}\biggr] + p_1 \frac{\partial}{\partial \zeta}\biggl[ 1 - \chi^2 - \zeta^2(1-e^2)^{-1}\biggr] </math> </td> </tr> </table>
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