0=d2xdξ2+[4−(n+1)Q]1ξ⋅dxdξ+(n+1)[(σc26γg)ξ2θ−αQ]xξ2
where: Q(ξ)≡−dlnθdlnξ, σc2≡3ω22πGρc, and, α≡(3−4γg)