SSC/Stability/GammaVariation: Difference between revisions
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<td align="right"><math>\mathfrak{F}</math></td> | <td align="right"><math>\mathfrak{F}</math></td> | ||
<td align="center"><math>\equiv</math></td> | <td align="center"><math>\equiv</math></td> | ||
<td align="right"><math> | <td align="right"> | ||
\biggl[\frac{3\omega^2}{2\pi \gamma_g G\bar\rho} - 2 \biggl( 3 - \frac{4}{\gamma_\mathrm{g}}\biggr) \biggr] | <math> | ||
\biggl[\frac{3\omega^2}{2\pi \gamma_g G\bar\rho} - 2 \biggl( 3 - \frac{4}{\gamma_\mathrm{g}}\biggr) \biggr] | |||
~~~~~\Rightarrow ~~~~~\frac{\gamma_\mathrm{g}\mathfrak{F}}{2} = \biggl[\frac{3\omega^2}{4\pi G\bar\rho} + 4 - 3\gamma_\mathrm{g} \biggr] | |||
</math> | |||
</td> | |||
</tr> | </tr> | ||
</table> | </table> | ||
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</td> | </td> | ||
<td align="left"> | <td align="left"> | ||
<math>\frac{1}{\gamma_g} \biggl( 4 - 3\gamma_g + \frac{\omega^2}{4\pi G \bar\rho}\biggr) </math> at <math>~\chi_0 = 1 \, .</math> | <math>\frac{1}{\gamma_g} \biggl( 4 - 3\gamma_g + \frac{3\omega^2}{4\pi G \bar\rho}\biggr) </math> at <math>~\chi_0 = 1 \, .</math> | ||
</td> | </td> | ||
</tr> | </tr> | ||
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</td> | </td> | ||
<td align="left"> | <td align="left"> | ||
<math>\frac{ | <math>\frac{\mathfrak{F}}{2} \, .</math> | ||
</td> | </td> | ||
</tr> | </tr> | ||
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</div> | </div> | ||
<font color="red">Check j = 0:</font> | <b><font color="red">Check j = 0:</font></b> | ||
The eigenvector is <math>x = 1</math>, that is, homologous contraction/expansion, in which case both the first and the second derivative of <math>x</math> are zero. Hence, this eigenvector is a solution to the LAWE only if <math>\mathfrak{F} = 0</math>. What about the two boundary conditions? Well, the central boundary condition is immediately satisfied; for the outer boundary condition, we | The eigenvector is <math>x = 1</math>, that is, homologous contraction/expansion, in which case both the first and the second derivative of <math>x</math> are zero. Hence, this eigenvector is a solution to the LAWE only if <math>\mathfrak{F} = 0</math>. What about the two boundary conditions? Well, the central boundary condition is immediately satisfied; for the outer boundary condition, we see that the logarithmic derivative of <math>x</math> is supposed to be zero, which it is because it equals <math>\mathfrak{F}/2</math>. Finally, since <math>\mathfrak{F} = 0</math>, we see that the oscillation frequency is given by the expression, | ||
<div align="center"> | |||
<math>\frac{\omega^2}{4\pi G\bar\rho} = \gamma_\mathrm{g} - 4/3 \, .</math> | |||
</div> | |||
=How Does Stability Change with P<sub>e</sub>?= | =How Does Stability Change with P<sub>e</sub>?= | ||
Revision as of 00:47, 8 January 2024
How Does Stability Change with γg?
Isolated Uniform-Density Configuration
From our separate discussion, the relevant LAWE is,
where, , , and
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Also, the two relevant boundary conditions are,
at
and,
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Alternatively, this last expression may be written as,
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From the general solution derived by 📚 T. E. Sterne (1937, MNRAS, Vol. 97, pp. 582 - 593), we have …
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The first few solutions are displayed in the following boxed-in image that has been extracted directly from §2 (p. 587) of 📚 Sterne (1937); to the right of his table, we have added a column that expressly records the value of the square of the normalized eigenfrequency that corresponds to each of the solutions presented by Sterne37.
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Based on exact eigenvector expressions extracted from §2 (p. 587) of … |
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Check j = 0: The eigenvector is , that is, homologous contraction/expansion, in which case both the first and the second derivative of are zero. Hence, this eigenvector is a solution to the LAWE only if . What about the two boundary conditions? Well, the central boundary condition is immediately satisfied; for the outer boundary condition, we see that the logarithmic derivative of is supposed to be zero, which it is because it equals . Finally, since , we see that the oscillation frequency is given by the expression,

