ThreeDimensionalConfigurations/FerrersPotential: Difference between revisions

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</table>
</table>


Following &sect;2.3.2 (beginning on p. 60) of [[Appendix/References#BT87|BT87]], let's examine ''inhomogeneous'' configurations whose isodensity surfaces (including the surface, itself) are defined by triaxial ellipsoids on which the Cartesian coordinates <math>~(x_1, x_2, x_3)</math> satisfy the condition that,
Following &sect;2.3.2 (beginning on p. 60) of [[Appendix/References#BT87|BT87]], let's examine ''inhomogeneous'' configurations whose isodensity surfaces (including the surface, itself) are defined by triaxial ellipsoids on which the Cartesian coordinates <math>(x_1, x_2, x_3)</math> satisfy the condition that,
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~m^2</math>
<math>m^2</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\equiv</math>
<math>\equiv</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~a_1^2 \sum_{i=1}^{3} \frac{x_i^2}{a_i^2} \, ,</math>
<math>a_1^2 \sum_{i=1}^{3} \frac{x_i^2}{a_i^2} \, ,</math>
   </td>
   </td>
</tr>
</tr>
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<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\rho(m^2)</math>
<math>\rho(m^2)</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~\rho_c \biggl[1 - \frac{m^2}{a_1^2}\biggr]^n </math>
<math>\rho_c \biggl[1 - \frac{m^2}{a_1^2}\biggr]^n </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\rho_c \biggl[1 -  
\rho_c \biggl[1 -  
\sum_{i=1}^{3} \frac{x_i^2}{a_i^2} \biggr]^n  
\sum_{i=1}^{3} \frac{x_i^2}{a_i^2} \biggr]^n  
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   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\rho_c \biggl[1 - \biggl( \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2}\biggr) \biggr]^n  
\rho_c \biggl[1 - \biggl( \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2}\biggr) \biggr]^n  
\, .</math>
\, .</math>
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<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\Phi_\mathrm{grav}(\bold{x})</math>
<math>\Phi_\mathrm{grav}(\bold{x})</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
- \frac{\pi G \rho_c a_1 a_2 a_3}{(n+1)}  \int_0^\infty \frac{ du}{\Delta } Q^{n+1}  \, ,
- \frac{\pi G \rho_c a_1 a_2 a_3}{(n+1)}  \int_0^\infty \frac{ du}{\Delta } Q^{n+1}  \, ,
</math>
</math>
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</td></tr>
</td></tr>
</table>
</table>
where, <math>~\Delta</math> has the same definition as [[ThreeDimensionalConfigurations/HomogeneousEllipsoids#Derivation_of_Expressions_for_Ai|above]], and,
where, <math>\Delta</math> has the same definition as [[ThreeDimensionalConfigurations/HomogeneousEllipsoids#Derivation_of_Expressions_for_Ai|above]], and,
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~Q</math>
<math>Q</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\equiv</math>
<math>\equiv</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \, .
1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \, .
</math>
</math>
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</table>
</table>


For purposes of illustration, in what follows we will assume that, <math>~a_1 > a_2 > a_3</math>.
For purposes of illustration, in what follows we will assume that, <math>a_1 > a_2 > a_3</math>.


===The Case Where n = 0===
===The Case Where n = 0===


When <math>~n = 0</math>, we have a uniform-density configuration, and the "interior" potential will be given by the expression,
When <math>n = 0</math>, we have a uniform-density configuration, and the "interior" potential will be given by the expression,
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\Phi_\mathrm{grav}(\bold{x})</math>
<math>\Phi_\mathrm{grav}(\bold{x})</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
- \pi G \rho_c a_1 a_2 a_3  \int_0^\infty \frac{ du}{\Delta } \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
- \pi G \rho_c a_1 a_2 a_3  \int_0^\infty \frac{ du}{\Delta } \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
</math>
</math>
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   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
- \pi G \rho_c a_1 a_2 a_3 \biggl\{   
- \pi G \rho_c a_1 a_2 a_3 \biggl\{   
\int_0^\infty \frac{ du}{\Delta }  
\int_0^\infty \frac{ du}{\Delta }  
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   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
- \pi G \rho_c a_1 a_2 a_3 \biggl\{   
- \pi G \rho_c a_1 a_2 a_3 \biggl\{   
\int_0^\infty \frac{ du}{\Delta }  
\int_0^\infty \frac{ du}{\Delta }  
~ - ~x^2 \int_0^\infty \frac{ du}{\Delta (a_1^2 + u) }  
- ~x^2 \int_0^\infty \frac{ du}{\Delta (a_1^2 + u) }  
~ - ~y^2 \int_0^\infty \frac{ du}{\Delta (a_2^2 + u) }   
- ~y^2 \int_0^\infty \frac{ du}{\Delta (a_2^2 + u) }   
~ - ~ \int_0^\infty \frac{ du}{\Delta (a_3^2 + u) }  
- ~ \int_0^\infty \frac{ du}{\Delta (a_3^2 + u) }  
\biggr\}
\biggr\}
</math>
</math>
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   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
-\pi G \rho_c \biggl[ I_\mathrm{BT} a_1^2 - \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr) \biggr] \, .</math>
-\pi G \rho_c \biggl[ I_\mathrm{BT} a_1^2 - \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr) \biggr] \, .</math>
   </td>
   </td>
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<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\sum_{\ell = 1}^3 A_\ell</math>
<math>\sum_{\ell = 1}^3 A_\ell</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~2 \, ,</math>
<math>2 \, ,</math>
   </td>
   </td>
</tr>
</tr>
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<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\nabla^2\Phi_\mathrm{grav} = \biggl[\frac{\partial^2}{\partial x^2}  + \frac{\partial^2}{\partial y^2} + \frac{\partial^2}{\partial z^2}\biggr]\Phi_\mathrm{grav}</math>
<math>\nabla^2\Phi_\mathrm{grav} = \biggl[\frac{\partial^2}{\partial x^2}  + \frac{\partial^2}{\partial y^2} + \frac{\partial^2}{\partial z^2}\biggr]\Phi_\mathrm{grav}</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
+ 2\pi G \rho_c (A_1 + A_2 + A_3) = 4\pi G\rho_c \, .
+ 2\pi G \rho_c (A_1 + A_2 + A_3) = 4\pi G\rho_c \, .
</math>
</math>
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===The Case Where n = 1===
===The Case Where n = 1===


When <math>~n = 1</math>, we have a specific heterogeneous density configuration, and the "interior" potential will be given by the expression,
When <math>n = 1</math>, we have a specific heterogeneous density configuration, and the "interior" potential will be given by the expression,
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\frac{ \Phi_\mathrm{grav}(\bold{x})}{(-\pi G\rho_c)} </math>
<math>\frac{ \Phi_\mathrm{grav}(\bold{x})}{(-\pi G\rho_c)} </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\frac{1}{2} a_1 a_2 a_3  \int_0^\infty \frac{ du}{\Delta } \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]^2
\frac{1}{2} a_1 a_2 a_3  \int_0^\infty \frac{ du}{\Delta } \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]^2
</math>
</math>
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   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\frac{1}{2} a_1 a_2 a_3  \biggl\{   
\frac{1}{2} a_1 a_2 a_3  \biggl\{   
\int_0^\infty \frac{ du}{\Delta } \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
\int_0^\infty \frac{ du}{\Delta } \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
~- ~ x^2 \int_0^\infty \frac{ du}{\Delta (a_1^2 + u)} \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
- ~ x^2 \int_0^\infty \frac{ du}{\Delta (a_1^2 + u)} \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
</math>
</math>
   </td>
   </td>
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   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
~- ~y^2 \int_0^\infty \frac{ du}{\Delta (a_2^2 + u)}  \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
- ~y^2 \int_0^\infty \frac{ du}{\Delta (a_2^2 + u)}  \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
~ - ~z^2 \int_0^\infty \frac{ du}{\Delta (a_3^2 + u)} \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
- ~z^2 \int_0^\infty \frac{ du}{\Delta (a_3^2 + u)} \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
\biggr\} \, .
\biggr\} \, .
</math>
</math>
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</table>
</table>


The first definite-integral expression inside the curly braces is, to within a leading factor of <math>~\tfrac{1}{2}</math>, identical to the entire expression for the normalized potential that was derived in the case where n = 0. That is, we can write,
The first definite-integral expression inside the curly braces is, to within a leading factor of <math>\tfrac{1}{2}</math>, identical to the entire expression for the normalized potential that was derived in the case where n = 0. That is, we can write,
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">


<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\frac{ \Phi_\mathrm{grav}(\bold{x})}{(-\pi G\rho_c)} </math>
<math>\frac{ \Phi_\mathrm{grav}(\bold{x})}{(-\pi G\rho_c)} </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\frac{1}{2} \biggl[ I_\mathrm{BT} a_1^2 - \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr) \biggr]
\frac{1}{2} \biggl[ I_\mathrm{BT} a_1^2 - \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr) \biggr]
~- \frac{1}{2} a_1 a_2 a_3  \biggl\{ ~ x^2 \int_0^\infty \frac{ du}{\Delta (a_1^2 + u)} \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
- \frac{1}{2} a_1 a_2 a_3  \biggl\{ ~ x^2 \int_0^\infty \frac{ du}{\Delta (a_1^2 + u)} \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
</math>
</math>
   </td>
   </td>
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   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
~+~y^2 \int_0^\infty \frac{ du}{\Delta (a_2^2 + u)}  \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
+~y^2 \int_0^\infty \frac{ du}{\Delta (a_2^2 + u)}  \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
~ + ~z^2 \int_0^\infty \frac{ du}{\Delta (a_3^2 + u)} \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
+ ~z^2 \int_0^\infty \frac{ du}{\Delta (a_3^2 + u)} \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]
\biggr\} \, .
\biggr\} \, .
</math>
</math>
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<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~a_1 a_2 a_3 \int_0^\infty \frac{ du}{\Delta (a_i^2 + u)}  \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]</math>
<math>a_1 a_2 a_3 \int_0^\infty \frac{ du}{\Delta (a_i^2 + u)}  \biggl[ 1 - \sum_{\ell = 1}^3 \frac{x_\ell^2}{ a_\ell^2 + u }  \biggr]</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
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   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\biggl( A_i - \sum_{\ell=1}^3 A_{i\ell} x_\ell^2 \biggr) \, .
\biggl( A_i - \sum_{\ell=1}^3 A_{i\ell} x_\ell^2 \biggr) \, .
</math>
</math>
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<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\frac{ \Phi_\mathrm{grav}(\bold{x})}{(-\pi G\rho_c)} </math>
<math>\frac{ \Phi_\mathrm{grav}(\bold{x})}{(-\pi G\rho_c)} </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\frac{1}{2} \biggl[ I_\mathrm{BT} a_1^2 - \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr) \biggr]
\frac{1}{2} \biggl[ I_\mathrm{BT} a_1^2 - \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr) \biggr]
~- \frac{x^2}{2}  \biggl( A_1 - \sum_{\ell=1}^3 A_{1\ell} x_\ell^2 \biggr)
- \frac{x^2}{2}  \biggl( A_1 - \sum_{\ell=1}^3 A_{1\ell} x_\ell^2 \biggr)
~- \frac{y^2}{2}  \biggl( A_2 - \sum_{\ell=1}^3 A_{2\ell} x_\ell^2 \biggr)
- \frac{y^2}{2}  \biggl( A_2 - \sum_{\ell=1}^3 A_{2\ell} x_\ell^2 \biggr)
~- \frac{z^2}{2}  \biggl( A_3 - \sum_{\ell=1}^3 A_{3\ell} x_\ell^2 \biggr) \, .
- \frac{z^2}{2}  \biggl( A_3 - \sum_{\ell=1}^3 A_{3\ell} x_\ell^2 \biggr) \, .
</math>
</math>
   </td>
   </td>
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   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\frac{1}{2} \biggl[ I_\mathrm{BT} a_1^2 - \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr) \biggr]
\frac{1}{2} \biggl[ I_\mathrm{BT} a_1^2 - \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr) \biggr]
~- \frac{x^2}{2}  \biggl[ A_1 - \biggl( A_{11}x^2 + A_{12}y^2 + A_{13}z^2 \biggr) \biggr]
- \frac{x^2}{2}  \biggl[ A_1 - \biggl( A_{11}x^2 + A_{12}y^2 + A_{13}z^2 \biggr) \biggr]
</math>
</math>
   </td>
   </td>
Line 516: Line 516:
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
~- \frac{y^2}{2}  \biggl[ A_2 - \biggl( A_{21}x^2 + A_{22}y^2 + A_{23}z^2 \biggr) \biggr]
- \frac{y^2}{2}  \biggl[ A_2 - \biggl( A_{21}x^2 + A_{22}y^2 + A_{23}z^2 \biggr) \biggr]
~- \frac{z^2}{2}  \biggl[ A_3 - \biggl( A_{31}x^2 + A_{32}y^2 + A_{33}z^2 \biggr) \biggr]  
- \frac{z^2}{2}  \biggl[ A_3 - \biggl( A_{31}x^2 + A_{32}y^2 + A_{33}z^2 \biggr) \biggr]  
</math>
</math>
   </td>
   </td>
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   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\frac{1}{2} I_\mathrm{BT} a_1^2  
\frac{1}{2} I_\mathrm{BT} a_1^2  
- \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr)  
- \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr)  
Line 548: Line 548:


<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">
<tr><td align="center" colspan="3">for <math>~i \ne j</math></td></tr>
<tr><td align="center" colspan="3">for <math>i \ne j</math></td></tr>
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~A_{ij}</math>
<math>A_{ij}</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~\equiv</math>
<math>\equiv</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~-\frac{A_i-A_j}{(a_i^2 - a_j^2)} </math>
<math>-\frac{A_i-A_j}{(a_i^2 - a_j^2)} </math>
   </td>
   </td>
</tr>
</tr>
Line 567: Line 567:


<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">
<tr><td align="center" colspan="3">for <math>~i = j</math></td></tr>
<tr><td align="center" colspan="3">for <math>i = j</math></td></tr>
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~2A_{ii} + \sum_{\ell = 1}^3 A_{i\ell}</math>
<math>2A_{ii} + \sum_{\ell = 1}^3 A_{i\ell}</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~\frac{2}{a_i} </math>
<math>\frac{2}{a_i} </math>
   </td>
   </td>
</tr>
</tr>
Line 587: Line 587:




and we have made use of the symmetry relation, <math>~A_{ij} = A_{ji}</math>.  Again, as a check, let's see if this scalar potential satisfies the differential form of the
and we have made use of the symmetry relation, <math>A_{ij} = A_{ji}</math>.  Again, as a check, let's see if this scalar potential satisfies the differential form of the
<div align="center">
<div align="center">
<span id="PGE:Poisson"><font color="#770000">'''Poisson Equation'''</font></span><br />
<span id="PGE:Poisson"><font color="#770000">'''Poisson Equation'''</font></span><br />
Line 598: Line 598:
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\nabla^2 \biggl[ \frac{\Phi_\mathrm{grav}}{-2\pi G \rho_c} \biggr] </math>
<math>\nabla^2 \biggl[ \frac{\Phi_\mathrm{grav}}{-2\pi G \rho_c} \biggr] </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\frac{1}{2}\biggl[\frac{\partial^2}{\partial x^2}  + \frac{\partial^2}{\partial y^2} + \frac{\partial^2}{\partial z^2}\biggr]  
\frac{1}{2}\biggl[\frac{\partial^2}{\partial x^2}  + \frac{\partial^2}{\partial y^2} + \frac{\partial^2}{\partial z^2}\biggr]  
\biggl[- \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr)  
\biggl[- \biggl(A_1 x^2 + A_2 y^2 +A_3 z^2 \biggr)  
~+ \biggl( A_{12} x^2y^2 + A_{13} x^2z^2 + A_{23} y^2z^2\biggr)
+ \biggl( A_{12} x^2y^2 + A_{13} x^2z^2 + A_{23} y^2z^2\biggr)
~+ \frac{1}{2}  \biggl(A_{11}x^4 +  A_{22}y^4 + A_{33}z^4  \biggr)  
+ \frac{1}{2}  \biggl(A_{11}x^4 +  A_{22}y^4 + A_{33}z^4  \biggr)  
\biggr]
\biggr]
</math>
</math>
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   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\frac{\partial}{\partial x}  \biggl[- A_1 x  ~+ A_{12} x y^2 + A_{13} x z^2 ~+ A_{11}x^3  \biggr]
\frac{\partial}{\partial x}  \biggl[- A_1 x  ~+ A_{12} x y^2 + A_{13} x z^2 ~+ A_{11}x^3  \biggr]
+\frac{\partial}{\partial y}  \biggl[- A_2 y  ~+  A_{12} x^2y  + A_{23} y z^2~+ A_{22}y^3  \biggr]
+\frac{\partial}{\partial y}  \biggl[- A_2 y  ~+  A_{12} x^2y  + A_{23} y z^2~+ A_{22}y^3  \biggr]
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   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~
<math>
\biggl[- A_1  + A_{12} y^2 + A_{13} z^2 ~+ 3A_{11}x^2  \biggr]
\biggl[- A_1  + A_{12} y^2 + A_{13} z^2 ~+ 3A_{11}x^2  \biggr]
+ \biggl[- A_2 +  A_{12} x^2  + A_{23} z^2~+ 3A_{22}y^2  \biggr]
+ \biggl[- A_2 +  A_{12} x^2  + A_{23} z^2~+ 3A_{22}y^2  \biggr]
Line 651: Line 651:
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~ - (A_1 + A_2 + A_3) + x^2(3A_{11} + A_{12} + A_{13}) + y^2( 3A_{22} + A_{12} + A_{23}) + z^2( 3A_{33} + A_{13} + A_{23})\, .
<math>- (A_1 + A_2 + A_3) + x^2(3A_{11} + A_{12} + A_{13}) + y^2( 3A_{22} + A_{12} + A_{23}) + z^2( 3A_{33} + A_{13} + A_{23})\, .
</math>
</math>
   </td>
   </td>
Line 660: Line 660:
</table>
</table>


In addition to recognizing, as [[#SumTo2|stated above]], that <math>~(A_1 + A_2 + A_3) = 2</math>, and making explicit use of the relation,
In addition to recognizing, as [[#SumTo2|stated above]], that <math>(A_1 + A_2 + A_3) = 2</math>, and making explicit use of the relation,
<table border="0" cellpadding="5" align="center">
<table border="0" cellpadding="5" align="center">
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~2A_{ii} + \sum_{\ell = 1}^3 A_{i\ell}</math>
<math>2A_{ii} + \sum_{\ell = 1}^3 A_{i\ell}</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~\frac{2}{a_i} \, ,</math>
<math>\frac{2}{a_i} \, ,</math>
   </td>
   </td>
</tr>
</tr>
Line 679: Line 679:
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\nabla^2 \biggl[ \frac{\Phi_\mathrm{grav}}{-2\pi G \rho_c} \biggr] </math>
<math>\nabla^2 \biggl[ \frac{\Phi_\mathrm{grav}}{-2\pi G \rho_c} \biggr] </math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~ - (2) + \frac{2x^2}{a_1^2} + \frac{2y^2}{a_2^2} + \frac{2z^2}{a_3^2}
<math>- (2) + \frac{2x^2}{a_1^2} + \frac{2y^2}{a_2^2} + \frac{2z^2}{a_3^2}
</math>
</math>
   </td>
   </td>
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<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\Rightarrow ~~~ \nabla^2 \Phi_\mathrm{grav}</math>
<math>\Rightarrow ~~~ \nabla^2 \Phi_\mathrm{grav}</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>~ 4\pi G \rho_c \biggl[ 1 -  \biggl( \frac{x^2}{a_1^2} + \frac{y^2}{a_2^2} + \frac{z^2}{a_3^2}\biggr) \biggr] \, .
<math>4\pi G \rho_c \biggl[ 1 -  \biggl( \frac{x^2}{a_1^2} + \frac{y^2}{a_2^2} + \frac{z^2}{a_3^2}\biggr) \biggr] \, .
</math>
</math>
   </td>
   </td>
Line 708: Line 708:
<tr>
<tr>
   <td align="right">
   <td align="right">
<math>~\rho</math>
<math>\rho</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>~=</math>
<math>=</math>
   </td>
   </td>
   <td align="left">
   <td align="left">
<math>\rho_c \biggl[ 1 -  \biggl( \frac{x^2}{a_1^2} + \frac{y^2}{a_2^2} + \frac{z^2}{a_3^2}\biggr) \biggr] \, .
<math>
\rho_c \biggl[ 1 -  \biggl( \frac{x^2}{a_1^2} + \frac{y^2}{a_2^2} + \frac{z^2}{a_3^2}\biggr) \biggr] \, .
</math>
</math>
   </td>
   </td>

Revision as of 18:54, 22 June 2024

Ferrers (1877) Gravitational Potential for Inhomogeneous Ellipsoids

Ferrers
Potential
(1877)

In an accompanying chapter titled, Properties of Homogeneous Ellipsoids (1), we have shown how analytic expressions may be derived for the gravitational potential inside of uniform-density ellipsoids. In that discussion, we largely followed the derivations of EFE. In the latter part of the nineteenth-century, 📚 N. M. Ferrers (1877, Quart. J. Pure Appl. Math., Vol. 14, pp. 1 - 22) showed that very similar analytic expressions can be derived for ellipsoids that have certain, specific inhomogeneous mass distributions. Here we specifically discuss the case of configurations that exhibit concentric ellipsoidal iso-density surfaces of the form,

ρ

=

ρc[1(x2a12+y2a22+z2a32)].

SUMMARY — copied from accompanying, Trial #2 Discussion

After studying the relevant sections of both EFE and BT87 — this is an example of a heterogeneous density distribution whose gravitational potential has an analytic prescription. As is discussed in a separate chapter, the potential that it generates is sometimes referred to as a Ferrers potential, for the exponent, n = 1.

In our accompanying discussion we find that,

Φgrav(𝐱)(πGρc)

=

12IBTa12(A1x2+A2y2+A3z2)+(A12x2y2+A13x2z2+A23y2z2)+16(3A11x4+3A22y4+3A33z4),

where,

for ij

Aij

AiAj(ai2aj2)

[ EFE, §21, Eq. (107) ]
for i=j

2Aii+=13Ai

=

2ai

[ EFE, §21, Eq. (109) ]

More specifically, in the three cases where the indices, i=j,

3A11

=

2a12(A12+A13),

3A22

=

2a22(A21+A23),

3A33

=

2a32(A31+A32).


Derivation

Other references to Ferrers Potential:

Following §2.3.2 (beginning on p. 60) of BT87, let's examine inhomogeneous configurations whose isodensity surfaces (including the surface, itself) are defined by triaxial ellipsoids on which the Cartesian coordinates (x1,x2,x3) satisfy the condition that,

m2

a12i=13xi2ai2,

[ EFE, Chapter 3, §20, p. 50, Eq. (75) ]
[ BT87, §2.3.2, p. 61, Eq. (2-97) ]

be constant. More specifically, let's consider the case (related to the so-called Ferrers potentials) in which the configuration's density distribution is given by the expression,

ρ(m2)

=

ρc[1m2a12]n

=

ρc[1i=13xi2ai2]n

=

ρc[1(x2a2+y2b2+z2c2)]n.

NOTE:     In our accompanying discussion of compressible analogues of Riemann S-type ellipsoids, we have discovered that — at least in the context of infinitesimally thin, nonaxisymmetric disks — this heterogeneous density profile can be nicely paired with an analytically expressible stream function, at least for the case where the integer exponent is, n = 1.

According to Theorem 13 of EFE — see his Chapter 3, §20 (p. 53) — the potential at any point inside a triaxial ellipsoid with this specific density distribution is given by the expression,

Φgrav(𝐱)

=

πGρca1a2a3(n+1)0duΔQn+1,

[ EFE, Chapter 3, §20, p. 53, Eq. (101) ]

where, Δ has the same definition as above, and,

Q

1=13x2a2+u.

For purposes of illustration, in what follows we will assume that, a1>a2>a3.

The Case Where n = 0

When n=0, we have a uniform-density configuration, and the "interior" potential will be given by the expression,

Φgrav(𝐱)

=

πGρca1a2a30duΔ[1=13x2a2+u]

 

=

πGρca1a2a3{0duΔ0duΔ(x2a12+u)0duΔ(y2a22+u)0duΔ(z2a32+u)}

 

=

πGρca1a2a3{0duΔx20duΔ(a12+u)y20duΔ(a22+u)0duΔ(a32+u)}

 

=

πGρc[IBTa12(A1x2+A2y2+A3z2)].

As a check, let's see if this scalar potential satisfies the differential form of the

Poisson Equation

2Φ=4πGρ

Given that,

=13A

=

2,

[ EFE, §21, Eq. (108) ]

we find,

2Φgrav=[2x2+2y2+2z2]Φgrav

=

+2πGρc(A1+A2+A3)=4πGρc.

Q.E.D.

The Case Where n = 1

When n=1, we have a specific heterogeneous density configuration, and the "interior" potential will be given by the expression,

Φgrav(𝐱)(πGρc)

=

12a1a2a30duΔ[1=13x2a2+u]2

 

=

12a1a2a3{0duΔ[1=13x2a2+u]x20duΔ(a12+u)[1=13x2a2+u]

 

 

y20duΔ(a22+u)[1=13x2a2+u]z20duΔ(a32+u)[1=13x2a2+u]}.

The first definite-integral expression inside the curly braces is, to within a leading factor of 12, identical to the entire expression for the normalized potential that was derived in the case where n = 0. That is, we can write,

Φgrav(𝐱)(πGρc)

=

12[IBTa12(A1x2+A2y2+A3z2)]12a1a2a3{x20duΔ(a12+u)[1=13x2a2+u]

 

 

+y20duΔ(a22+u)[1=13x2a2+u]+z20duΔ(a32+u)[1=13x2a2+u]}.

Then, from §22, p. 56 of EFE, we see that,

a1a2a30duΔ(ai2+u)[1=13x2a2+u]

=

(Ai=13Aix2).

[ EFE, Chapter 3, §22, p. 53, Eq. (125) ]

Applying this result to each of the other three definite integrals gives us,

Φgrav(𝐱)(πGρc)

=

12[IBTa12(A1x2+A2y2+A3z2)]x22(A1=13A1x2)y22(A2=13A2x2)z22(A3=13A3x2).

 

=

12[IBTa12(A1x2+A2y2+A3z2)]x22[A1(A11x2+A12y2+A13z2)]

 

 

y22[A2(A21x2+A22y2+A23z2)]z22[A3(A31x2+A32y2+A33z2)]

 

=

12IBTa12(A1x2+A2y2+A3z2)+(A12x2y2+A13x2z2+A23y2z2)+12(A11x4+A22y4+A33z4),

where,

for ij

Aij

AiAj(ai2aj2)

[ EFE, §21, Eq. (107) ]
for i=j

2Aii+=13Ai

=

2ai

[ EFE, §21, Eq. (109) ]


and we have made use of the symmetry relation, Aij=Aji. Again, as a check, let's see if this scalar potential satisfies the differential form of the

Poisson Equation

2Φ=4πGρ

We find,

2[Φgrav2πGρc]

=

12[2x2+2y2+2z2][(A1x2+A2y2+A3z2)+(A12x2y2+A13x2z2+A23y2z2)+12(A11x4+A22y4+A33z4)]

 

=

x[A1x+A12xy2+A13xz2+A11x3]+y[A2y+A12x2y+A23yz2+A22y3]+z[A3z+A13x2z+A23y2z+A33z3]

 

=

[A1+A12y2+A13z2+3A11x2]+[A2+A12x2+A23z2+3A22y2]+[A3+A13x2+A23y2+3A33z2]

 

=

(A1+A2+A3)+x2(3A11+A12+A13)+y2(3A22+A12+A23)+z2(3A33+A13+A23).

In addition to recognizing, as stated above, that (A1+A2+A3)=2, and making explicit use of the relation,

2Aii+=13Ai

=

2ai,

this last expression can be simplified to discover that,

2[Φgrav2πGρc]

=

(2)+2x2a12+2y2a22+2z2a32

2Φgrav

=

4πGρc[1(x2a12+y2a22+z2a32)].

This does indeed demonstrate that the derived gravitational potential is consistent with our selected mass distribution in the case where n = 1, namely,

ρ

=

ρc[1(x2a12+y2a22+z2a32)].

Q.E.D.

See Also


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