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__FORCETOC__ <!-- will force the creation of a Table of Contents --> <!-- __NOTOC__ will force TOC off --> =Total Pressure= {| class="PGEclass" style="float:left; margin-right: 20px; border-style: solid; border-width: 3px border-color: black" |- ! style="height: 125px; width: 125px; background-color:white;" | <font size="-1">[[H_BookTiledMenu#Context|Total Pressure]]</font> |} In our overview of [[SR#Time-Dependent_Problems|equations of state]], we identified analytic expressions for the pressure of an ideal gas, <math>P_\mathrm{gas}</math>, electron degeneracy pressure, <math>P_\mathrm{deg}</math>, and radiation pressure, <math>P_\mathrm{rad}</math>. Rather than considering these relations one at a time, in general we should consider the contributions to the pressure that are made by all three simultaneously. That is, we should examine the total pressure, <div align="center"> <math> P_\mathrm{total} = P_\mathrm{gas} + P_\mathrm{deg} + P_\mathrm{rad} . </math> </div> In order to assess which of these three contributions will dominate <math>P_\mathrm{total}</math> in different density and temperature regimes, it is instructive to normalize <math>P_\mathrm{total}</math> to the characteristic Fermi pressure, {{ Template:Math/C_FermiPressure }}, as defined in the accompanying [[Appendix/VariablesTemplates|Variables Appendix]]. As derived below, this normalized total pressure can be written as, <div align="center"> {{ Template:Math/EQ_PressureTotal01 }} </div> ==Derivation== We begin by defining the normalized total gas pressure as follows: <div align="center"> <math> p_\mathrm{total} \equiv \frac{1}{A_\mathrm{F}} \biggl[ P_\mathrm{gas} + P_\mathrm{deg} + P_\mathrm{rad} \biggr] . </math> </div> To derive the expression for <math>p_\mathrm{total}</math> shown in the opening paragraph above, we begin by normalizing each component pressure independently. ===Normalized Degenerate Electron Pressure=== This normalization is trivial. Given the original expression for the pressure due to a degenerate electron gas (or a zero-temperature Fermi gas), <div align="center"> {{ Template:Math/EQ_ZTFG01 }} </div> we see that, <div align="center"> <math> \frac{P_\mathrm{deg}}{A_\mathrm{F}} = F(\chi) . </math> </div> ===Normalized Ideal-Gas Pressure=== Given the original expression for the pressure of an ideal gas, <div align="center"> {{ Template:Math/EQ_EOSideal0A }} </div> along with the definitions of the physical constants, {{ Template:Math/C_GasConstant }}, {{ Template:Math/C_FermiPressure }}, and {{ Template:Math/C_FermiDensity }} provided in the accompanying [[Appendix/VariablesTemplates|Variables Appendix]], we can write, <div align="center"> <math> \frac{P_\mathrm{gas}}{A_\mathrm{F}} = \frac{B_\mathrm{F}}{A_\mathrm{F}} \frac{\Re}{\bar{\mu}} \chi^3 T = \frac{\mu_e}{\bar{\mu}} \biggl[ \chi^3 T \biggr] \frac{8\pi m_p}{3} \biggl( \frac{m_e c}{h} \biggr)^3 \frac{3h^3}{\pi m_e^4 c^5} \biggl(k N_\mathrm{A} \biggr) = \biggl(m_p N_\mathrm{A} \biggr)\frac{\mu_e}{\bar{\mu}} \biggl[8 \chi^3 T \biggr] \frac{k}{ m_e c^2} . </math> </div> Therefore, letting <math>T_e \equiv m_e c^2/k</math> represent the temperature associated with the rest-mass energy of the electron, the normalized ideal gas pressure is, <div align="center"> <math> \frac{P_\mathrm{gas}}{A_\mathrm{F}} = \biggl(\frac{\mu_e m_p}{\bar{\mu} m_u} \biggr) \biggl[8 \chi^3 \frac{T}{T_e} \biggr] , </math> </div> where, by definition, the [http://en.wikipedia.org/wiki/Atomic_mass_unit atomic mass unit] is, <math>m_u \equiv (1/N_\mathrm{A})~\mathrm{g} = 0.992776 m_p</math>, that is, <math>~m_p/m_u = 1.007276</math>. ===Normalized Radiation Pressure=== Given the original expression for the radiation pressure, <div align="center"> {{ Template:Math/EQ_EOSradiation01 }} </div> along with the definitions of the physical constants, {{ Template:Math/C_FermiPressure }}, and {{ Template:Math/C_RadiationConstant }} provided in the accompanying [[Appendix/VariablesTemplates|Variables Appendix]], we can write, <div align="center"> <math> \frac{P_\mathrm{rad}}{A_\mathrm{F}} = \biggl( \frac{T^4}{3} \biggr) \frac{a_\mathrm{rad}}{A_\mathrm{F}} = \biggl( \frac{T^4}{3} \biggr) \frac{8\pi^5}{15}\frac{k^4}{(hc)^3} \frac{3h^3}{\pi m_e^4 c^5} = \frac{8\pi^4}{15} \biggl( \frac{T}{T_e} \biggr)^4 . </math> </div> ==Discussion== For simplicity of presentation, in what follows we will use <div align="center"> <math> z \equiv \frac{T}{T_e} \, , </math> </div> to represent a normalized temperature, in addition to using <math>\chi</math> to represent (the cube root of) the normalized mass density, and <math>p_\mathrm{total}</math> to represent the normalized total pressure. ===Relationship Between State Variables=== If the two normalized state variables, <math>\chi</math> and <math>z</math>, are known, then the third normalized state variable, <math>p_\mathrm{total}</math>, can be obtained directly from the [[SR/PressureCombinations#Total_Pressure|above key expression for the total pressure]], that is, <div align="center"> <math>p_\mathrm{total}(\chi, z) = 8(C_g \chi)^3 z + F(\chi) + \biggl(\frac{8\pi^4}{15}\biggr) z^4 \, ,</math> </div> where, <div align="center"> <math>C_g \equiv \biggl(\frac{\mu_e m_p}{\bar\mu m_u}\biggr)^{1/3} \, .</math> </div> If it is the two normalized state variables, <math>\chi</math> and <math>p_\mathrm{total}</math>, that are known, the third normalized state variable — namely, the normalized temperature, <math>z</math> — also can be obtained analytically. But the governing expression is not as simple because it results from an inversion of the total pressure equation and, hence, the solution of a quartic equation. As is [[SR/Ptot_QuarticSolution#Determining_Temperature_from_Density_and_Pressure|detailed in the accompanying discussion]], the desired solution is, <div align="center"> <math> z(\chi, p_\mathrm{total}) = \theta_\chi \phi^{-1/3}\biggl[ (\phi - 1)^{1/2} - 1 \biggr] , </math> </div> where, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\theta_\chi</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left" bgcolor="white"> <math>\biggl( \frac{3\cdot 5}{2^2 \pi^4} \biggr)^{1/3} C_g\chi \, ,</math> </td> </tr> <tr> <td align="right"> <math>\phi</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left" bgcolor="white"> <math>2^{3/2} \biggl[ 1 + (1 + \lambda^3)^{1/2} \biggr]^{1/2} \biggl\{ \biggl[ 1 + (1 + \lambda^3)^{1/2} \biggr]^{2/3} - \lambda \biggr\}^{-3/2}\, ,</math> </td> </tr> <tr> <td align="right"> <math>\lambda</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left" bgcolor="white"> <math> \biggl(\frac{\pi^4}{2\cdot 3^4\cdot 5} \biggr)^{1/3} \biggl[\frac{p_\mathrm{total}-F(\chi)}{(C_g \chi)^{4}}\biggr] \, . </math> </td> </tr> </table> </div> It also would be desirable to have an analytic expression for the function, <math>\chi(z, p_\mathrm{total})</math>, in order to be able to immediately determine the normalized density from any specified values of the normalized temperature and normalized pressure. However, it does not appear that the [[SR/PressureCombinations#Total_Pressure|above key expression for the total pressure]] can be inverted to provide such a closed-form expression. ===Dominant Contributions=== Let's examine which pressure contributions will dominate in various temperature-density regimes. Note, first, that {{ Template:Math/C_ProtonMass }}/{{ Template:Math/C_AtomicMassUnit }} <math>\approx 1</math> and, for fully ionized gases, the ratio {{ Template:Math/MP_ElectronMolecularWeight }}<math>/</math>{{ Template:Math/MP_MeanMolecularWeight }} is of order unity — more precisely, the ratio of these two molecular weights falls within the narrow range <math>1 < </math> {{ Template:Math/MP_ElectronMolecularWeight }}<math>/</math>{{ Template:Math/MP_MeanMolecularWeight }} <math>\le 2</math>. Hence, we can assume that the numerical coefficient of the first term in our expression for <math>p_\mathrm{total}</math> is approximately <math>8</math>, so the ratio of radiation pressure to gas pressure is, <div align="center"> <math> \frac{P_\mathrm{rad}}{P_\mathrm{gas}} \approx \frac{\pi^4}{15} \biggl( \frac{z}{\chi} \biggr)^3 </math> . </div> This means that radiation pressure will dominate over ideal gas pressure in any regime where, <div align="center"> <math> T \gg T_e \biggl[\frac{15}{\pi^4} \biggl(\frac{\rho}{B_F} \biggr) \biggr]^{1/3} </math> , </div> that is, whenever, <div align="center"> <math> T_7 \gg 3.2 \biggl[\frac{\rho_1}{\mu_e} \biggr]^{1/3} </math> , </div> where <math>T_7</math> is the temperature expressed in units of <math>10^7~K</math> and <math>\rho_1</math> is the matter density expressed in units of <math>\mathrm{g~cm}^{-3}</math>. Second, note that the function <math>F(\chi)</math> can be written in a simpler form when examining regions of either very low or very high matter densities. Specifically — see our [[SR#Nonrelativistic_ZTF_Gas|separate discussion of the Zero-Temperature Fermi gas]] — in the limit <math>\chi \ll 1</math>, <div align="center"> <math> F(\chi) \approx \frac{8}{5} \chi^5 </math> ; </div> and in the limit <math>\chi \gg 1</math>, <div align="center"> <math> F(\chi) \approx 2 \chi^4 </math> . </div> Hence, at low densities (<math>\chi \ll 1</math>), <div align="center"> <math> \frac{P_\mathrm{gas}}{P_\mathrm{deg}} \approx \frac{5 z}{ \chi^{2}} ~~~~~ \mathrm{and} ~~~~~ \frac{P_\mathrm{rad}}{P_\mathrm{deg}} \approx \biggl(\frac{\pi^4}{3}\biggr) \frac{z^4}{ \chi^5} ; </math> </div> and at high densities (<math>\chi \gg 1</math>), <div align="center"> <math> \frac{P_\mathrm{gas}}{P_\mathrm{deg}} \approx \frac{4z}{\chi} ~~~~~ \mathrm{and} ~~~~~ \frac{P_\mathrm{rad}}{P_\mathrm{deg}} \approx \frac{4 \pi^4}{15} \biggl( \frac{z}{\chi} \biggr)^4 . </math> </div> <!-- OMIT NEXT SHORT SECTION ===Just Ideal-Gas and Radiation=== In certain density-temperature regimes, contributions from the electron degeneracy pressure can be ignored and, to a good approximation, the normalized total pressure will take the form, <div align="center"> <math>~p_\mathrm{total} = C_g \chi^3 z + C_r z^4 ,</math> </div> where the coefficients, <div align="center"> <math> C_g \equiv 8\biggl(\frac{\mu_e m_p}{\bar{\mu} m_u} \biggr) ~~~~~ \mathrm{and} ~~~~~ C_r \equiv \frac{8\pi^4}{15} . </math> </div> Given any values for the pair of state variables, <math>~\chi</math> and <math>~z</math>, the third state variable can be calculated analytically from this specified function, <math>~p_\mathrm{total}(\chi,z)</math>. It is easy to see as well that, given any values for the pair of state variables, <math>~p_\mathrm{total}</math> and <math>~z</math>, the third state variable can be calculated analytically from the function, <div align="center"> <math>\chi^3(p_\mathrm{total},z) = \frac{1}{C_g z} \biggl[ p_\mathrm{total} - C_r z^4 \biggr] .</math> </div> --> {{ SGFfooter }}
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