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===Mass-Radius Relationship=== Third, [[Appendix/References|Chandrasekhar [C67]]] shows — see his Equation (72), p. 98 — that the general mass-radius relationship for isolated spherical polytropes is, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~GM^{(n-1)/n} R^{(3-n)/n}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> ~\frac{(n+1)K}{(4\pi)^{1/n}} \biggl[ - \xi^{(n+1)/(n-1)} \frac{d\Theta_H}{d\xi} \biggr]^{(n-1)/n}_{\xi=\xi_1} \, , </math> </td> </tr> </table> </div> which we choose to rewrite as, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~4\pi \biggl( \frac{G}{K}\biggr)^n M^{(n-1)} R^{(3-n)}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> ~(n+1)^n\biggl[ \xi^{(n+1)} (-\Theta^')^{(n-1)}\biggr]_{\xi=\xi_1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> - \biggl( \frac{\xi}{\Theta^'} \biggr)_{\xi=\xi_1} \biggl[ (n+1) \xi ~(-\Theta^') \biggr]^n_{\xi=\xi_1} \, . </math> </td> </tr> </table> </div> By comparison, the expression for the equilibrium radius that has been derived, above, from an analysis of extrema in the free energy function — specifically, see the last expression in the left-hand column of the [[SSC/Virial/Polytropes#TwoPointsOfView|table titled "Two Points of View"]] — we obtain, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~4\pi \biggl( \frac{G}{K}\biggr)^n M^{(n-1)} R_\mathrm{eq}^{(3-n)}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> ~\frac{3}{\mathfrak{f}_M} \biggl( \frac{5\mathfrak{f}_A \mathfrak{f}_M}{\mathfrak{f}_W} \biggr)^n \, . </math> </td> </tr> </table> </div> Hence, it appears as though, quite generally, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ \frac{1}{\mathfrak{f}_M} \biggl( \frac{5\mathfrak{f}_A \mathfrak{f}_M}{\mathfrak{f}_W} \biggr)^n </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> - \biggl( \frac{\xi}{3\Theta^'} \biggr)_{\xi=\xi_1} \biggl[ (n+1) \xi ~(-\Theta^') \biggr]^n_{\xi=\xi_1} \, . </math> </td> </tr> </table> </div> Or, taking into account the expressions for <math>~\mathfrak{f}_M</math> and <math>~\mathfrak{f}_W</math> that have just been uncovered, we conclude that, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ \frac{5\mathfrak{f}_A \mathfrak{f}_M}{\mathfrak{f}_W} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> \biggl[ (n+1) \xi ~(-\Theta^') \biggr]_{\xi=\xi_1} </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~~ \frac{\mathfrak{f}_A}{\mathfrak{f}_W} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> \frac{(n+1) }{3\cdot 5} ~\xi_1^2 \, . </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~~ \mathfrak{f}_A </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> \frac{(n+1) }{3\cdot 5} ~\xi_1^2 \biggl\{ \frac{3^2\cdot 5}{5-n} \biggl[ \frac{\Theta^'}{\xi} \biggr]^2_{\xi_1} \biggr\}\, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> \frac{3(n+1) }{(5-n)} ~\biggl[ \Theta^' \biggr]^2_{\xi_1} \, . </math> </td> </tr> </table> </div>
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