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===Sterne's Presentation=== In what follows, as before, text presented in a green font has been taken verbatim from {{ Sterne37hereafter }}. He begins by writing the unknown eigenfunction as a power series expanded about the origin, specifically, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\xi_1</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>\sum\limits_{0}^{\infty} a_k x^k \, ,</math> </td> </tr> </table> </div> with, <math>a_0 = 1</math>. <font color="green">It is found by substitution that the terms in odd powers of <math>x</math> vanish, and that the coefficients of the even terms satisfy the recurrence formula</font>, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>a_{k+2}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>a_k \cdot \frac{k^2 + 5k - \mathfrak{F}}{(k+2)(k+5)} \, .</math> </td> </tr> </table> </div> The wave equation and attending boundary conditions will all <font color="green">be satisfied if we choose <math>\mathfrak{F}</math> so as to make the series solution terminate with some term, say the <math>2 j^\mathrm{th}</math> where <math>j</math> is zero or any positive integer. This it will do</font> [via the above recurrence relation] if, <div align="center"> <math>\mathfrak{F} = 2j(2j+5) \, .</math> </div> The first few solutions are displayed in the following boxed-in image that has been extracted directly from §2 (p. 587) of {{ Sterne37 }}; to the right of his table, we have added a column that expressly records the value of the square of the normalized eigenfrequency that corresponds to each of the solutions presented by {{ Sterne37hereafter }}. <div align="center"> <table border="2" cellpadding="5" width="70%"> <tr> <td align="center" colspan="1"> Table of exact eigenvector expressions extracted from §2 (p. 587) of …<br /> {{ Sterne37figure }} </td> <td align="center" colspan="1"> <math>\frac{n^2}{4\pi G \bar\rho}</math> </td> </tr> <tr> <td colspan="1" rowspan="1"> <!-- [[File:Sterne1937SolutionTable1.png|600px|center|Sterne (1937)]] --> <table border="0" align="left"> <tr> <td align="right"><math>j=0 \, ;</math> </td> <td align="right"><math>\mathfrak{F}=0 \, ;</math> </td> <td align="right"> <math>\xi_1 = 1</math></td> </tr> </table> </td> <td align="center"><math>\gamma - 4/3</math></td> </tr> <tr> <td colspan="1" rowspan="1"> <table border="0" align="left"> <tr> <td align="right"><math>j=1 \, ;</math> </td> <td align="right"><math>\mathfrak{F}= 14 \, ;</math> </td> <td align="right"><math>\xi_1 = 1 - (7/5)x^2</math></td> </tr> </table> </td> <td align="center"><math>2(5\gamma - 2)/3</math></td> </tr> <tr> <td colspan="1" rowspan="1"> <table border="0" align="left"> <tr> <td align="right"><math>j=2 \, ;</math> </td> <td align="right"><math>\mathfrak{F}= 36 \, ;</math> </td> <td align="right"><math>\xi_1 = 1 - (18/5)x^2 + (99/35)x^4</math></td> </tr> </table> </td> <td align="center"><math>7\gamma - 4/3</math></td> </tr> <tr> <td colspan="1" rowspan="1"> <table border="0" align="left"> <tr> <td align="right"><math>j=3 \, ;</math> </td> <td align="right"><math>\mathfrak{F}=66 \, ;</math> </td> <td align="right"><math>\xi_1 = 1 - (33/5)x^2 + (429/35)x^4 - (143/21)x^6</math></td> </tr> </table> </td> <td align="center"><math>12\gamma - 4/3</math></td> </tr> </table> </div>
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