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==Tipped Frame== ===For Arbitrary Tip Angles=== Given that, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>x</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>x' \, ,</math> </td> </tr> <tr> <td align="right"> <math>y</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> y' \cos\theta - z'\sin\theta \, ,</math> </td> </tr> <tr> <td align="right"> <math>(z - z_0)</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> z' \cos\theta + y'\sin\theta \, ,</math> </td> </tr> </table> the constraint becomes, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>P'(x', y', z')</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[\frac{y'\cos\theta - z'\sin\theta}{b}\biggr]^2 + \biggl[\frac{z_0 + z'\cos\theta + y'\sin\theta}{c}\biggr]^2 +\biggl(\frac{x'}{a}\biggr)^2 \, . </math> </td> </tr> </table> <span id="gradP">Hence,</span> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\nabla P'(x', y', z')</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \boldsymbol{\hat\imath'} \biggl(\frac{2x'}{a^2}\biggr) + \boldsymbol{\hat\jmath'} \biggl\{ \biggl[\frac{2( y'\cos\theta - z'\sin\theta )\cos\theta}{b^2}\biggr] + \biggl[\frac{2( z_0 + z'\cos\theta + y'\sin\theta) \sin\theta}{c^2}\biggr] \biggr\} + \mathbf{\hat{k}'}\biggl\{- \biggl[\frac{2( y'\cos\theta - z'\sin\theta) \sin\theta}{b^2}\biggr] + \biggl[\frac{2 ( z_0 + z'\cos\theta + y'\sin\theta) \cos\theta}{c^2}\biggr] \biggr\} \, . </math> </td> </tr> </table> And, in the ''tipped'' frame we find, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\boldsymbol{u'}_\mathrm{EFE}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \boldsymbol{\hat\imath'} \biggl\{ - \biggl[\frac{a^2}{a^2+b^2}\biggr] \zeta_3 (y'\cos\theta - z'\sin\theta) + \biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 (z_0 + y'\sin\theta + z'\cos\theta) \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + \biggl[\boldsymbol{\hat\jmath'} \cos\theta - \mathbf{\hat{k}'} \sin\theta \biggr] \biggl\{ \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 x' \biggr\} + \biggl[\boldsymbol{\hat\jmath'} \sin\theta + \mathbf{\hat{k}'} \cos\theta \biggr] \biggl\{ - \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 x' \biggr\} \, . </math> </td> </tr> </table> As a result, we find, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\mathbf{u'}_\mathrm{EFE} \cdot \nabla P'</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl(\frac{2x'}{a^2}\biggr)\biggl\{ - \biggl[\frac{a^2}{a^2+b^2}\biggr] \zeta_3 (y'\cos\theta - z'\sin\theta) + \biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 (z_0 + y'\sin\theta + z'\cos\theta) \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> + \biggl\{ \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 \cos\theta ~ x' - \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2\sin\theta ~x' \biggr\} \biggl\{ \biggl[\frac{2( y'\cos\theta - z'\sin\theta )\cos\theta}{b^2}\biggr] + \biggl[\frac{2( z_0 + z'\cos\theta + y'\sin\theta) \sin\theta}{c^2}\biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> - \biggl\{\biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 \sin\theta~ x' + \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cos\theta~ x' \biggr\} \biggl\{- \biggl[\frac{2( y'\cos\theta - z'\sin\theta) \sin\theta}{b^2}\biggr] + \biggl[\frac{2 ( z_0 + z'\cos\theta + y'\sin\theta) \cos\theta}{c^2}\biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ \biggl[\frac{1}{2x'} \biggr] \mathbf{u'}_\mathrm{EFE} \cdot \nabla P'</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[\frac{1}{a^2+b^2}\biggr] \zeta_3 (y'\cos\theta - z'\sin\theta) + \biggl[ \frac{1}{a^2 + c^2}\biggr] \zeta_2 (z_0 + y'\sin\theta + z'\cos\theta) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> + \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 \biggl\{ \biggl[\frac{( y'\cos\theta - z'\sin\theta )\cos^2\theta}{b^2}\biggr] + \biggl[\frac{( z_0 + z'\cos\theta + y'\sin\theta) \sin\theta \cos\theta}{c^2}\biggr] \biggr\} - \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggl\{ \biggl[\frac{( y'\cos\theta - z'\sin\theta )\sin\theta\cos\theta}{b^2}\biggr] + \biggl[\frac{( z_0 + z'\cos\theta + y'\sin\theta) \sin^2\theta}{c^2}\biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> + \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 \biggl\{\biggl[\frac{( y'\cos\theta - z'\sin\theta) \sin^2\theta}{b^2}\biggr] - \biggl[\frac{ ( z_0 + z'\cos\theta + y'\sin\theta) \sin\theta \cos\theta}{c^2}\biggr] \biggr\} + \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggl\{\biggl[\frac{( y'\cos\theta - z'\sin\theta) \sin\theta \cos\theta}{b^2}\biggr] - \biggl[\frac{ ( z_0 + z'\cos\theta + y'\sin\theta) \cos^2\theta}{c^2}\biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[\frac{1}{a^2+b^2}\biggr] \zeta_3 (y'\cos\theta - z'\sin\theta) + \biggl[ \frac{1}{a^2 + c^2}\biggr] \zeta_2 (z_0 + y'\sin\theta + z'\cos\theta) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> + \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 \biggl[\frac{( y'\cos\theta - z'\sin\theta )}{b^2}\biggr] - \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggl[\frac{( z_0 + z'\cos\theta + y'\sin\theta)}{c^2}\biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[ \frac{( y'\cos\theta - z'\sin\theta )}{a^2 + b^2}\biggr] \zeta_3 - \biggl[\frac{1}{a^2+b^2}\biggr] \zeta_3 (y'\cos\theta - z'\sin\theta) + \biggl[ \frac{1}{a^2 + c^2}\biggr] \zeta_2 (z_0 + y'\sin\theta + z'\cos\theta) - \biggl[ \frac{( z_0 + z'\cos\theta + y'\sin\theta)}{a^2 + c^2} \biggr] \zeta_2 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> 0 \, . </math> </td> </tr> </table> Q. E. D. ===For Specific Tip Angle=== So … we have demonstrated that the velocity vectors are everywhere orthogonal to the normal to the ellipsoid for <b>all</b> values of the "tip" angle, <math>\theta</math>. So why have we been unable to demonstrate the same result in the case where, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\tan\theta</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \frac{\beta \Omega_2}{\gamma \Omega_3} = - \biggl[ \frac{c^2 (a^2 + b^2)}{b^2(a^2 + c^2)}\biggr]\frac{\zeta_2}{\zeta_3} \, . </math> </td> </tr> </table> Remember that, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>1 + \tan^2\theta</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{\sin^2\theta + \cos^2\theta}{\cos^2\theta} = \frac{1}{\cos^2\theta} </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ \cos^2\theta = \frac{1}{1 + \tan^2\theta}</math> </td> <td align="center"> and, </td> <td align="left"> <math> \sin^2\theta = \frac{\tan^2\theta}{1 + \tan^2\theta} \, . </math> </td> </tr> </table> Rearranging terms in the expression for the "tipped plane" Riemann flow velocity, we have, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\boldsymbol{u'}_\mathrm{EFE}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \boldsymbol{\hat\imath'} \biggl\{ - \cos\theta \biggl[\frac{a^2}{a^2+b^2}\biggr] \zeta_3 (y' - z'\tan\theta) + \cos\theta \biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 (y'\tan\theta + z') + \biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 z_0 \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + \boldsymbol{\hat\jmath'} \biggl\{ \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 - \tan\theta \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggr\} x' \cos\theta - \mathbf{\hat{k}'} \biggl\{ \tan\theta \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 + \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggr\} x' \cos\theta </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \boldsymbol{\hat\imath'} \biggl\{ - \cos\theta \biggl[\frac{a^2}{a^2+b^2}\biggr] \zeta_3 (y' - z'\tan\theta) + \cos\theta \biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 (y'\tan\theta + z') + \biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 z_0 \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + \boldsymbol{\hat\jmath'} \biggl\{ 1 - \tan\theta \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggl[ \frac{a^2 + b^2}{b^2}\biggr] \frac{1}{\zeta_3} \biggr\} x' \cos\theta \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 - \mathbf{\hat{k}'} \biggl\{ \tan\theta + \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggl[ \frac{a^2 + b^2}{b^2}\biggr] \frac{1}{\zeta_3} \biggr\} x' \cos\theta \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 </math> </td> </tr> </table> <span id="SpecificTipAngle">Then, for this specific tip angle</span>, the Riemann flow velocity is, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\boldsymbol{u'}_\mathrm{EFE}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \boldsymbol{\hat\imath'} \biggl\{\biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 z_0 \biggr\} + \boldsymbol{\hat\imath'} \biggl\{ \zeta_3 (z'\tan\theta - y' ) \cos\theta + \cos\theta \biggl[ \frac{a^2+b^2}{a^2 + c^2}\biggr] \zeta_2 (y'\tan\theta + z') \biggr\}\biggl[\frac{a^2}{a^2+b^2}\biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + \boldsymbol{\hat\jmath'} \biggl\{ 1 + \tan^2\theta \biggr\} x' \cos\theta \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \zeta_3 - \mathbf{\hat{k}'} \biggl\{ 0\biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \boldsymbol{\hat\imath'} \biggl\{\biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 z_0 \biggr\} + \boldsymbol{\hat\imath'} \biggl\{ \zeta_3 (z'\tan\theta - y' )\cos\theta - \cos\theta \biggl[ \frac{b^2 \zeta_3 \tan\theta}{c^2 \zeta_2}\biggr] \zeta_2 (y'\tan\theta + z') \biggr\}\biggl[\frac{a^2}{a^2+b^2}\biggr] + \boldsymbol{\hat\jmath'} \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \frac{\zeta_3~x' }{\cos\theta} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \boldsymbol{\hat\imath'} \biggl\{\biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 z_0 \biggr\} + \boldsymbol{\hat\imath'} \biggl\{ c^2 (z'\tan\theta - y' )\cos\theta - b^2 \sin\theta (y'\tan\theta + z') \biggr\}\frac{\zeta_3 }{c^2}\biggl[\frac{a^2}{a^2+b^2}\biggr] + \boldsymbol{\hat\jmath'} \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \frac{\zeta_3~x' }{\cos\theta} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \boldsymbol{\hat\imath'} \biggl\{\biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 z_0 \biggr\} + \boldsymbol{\hat\imath'} \biggl\{ z' (c^2 - b^2 )\tan\theta - y' [c^2 + b^2 \tan^2\theta ] \biggr\}\frac{\zeta_3 \cos\theta}{c^2}\biggl[\frac{a^2}{a^2+b^2}\biggr] + \boldsymbol{\hat\jmath'} \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \frac{\zeta_3~x' }{\cos\theta} </math> </td> </tr> </table> As we have [[#gradP|already stated]], <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\nabla P'(x', y', z')</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \boldsymbol{\hat\imath'} \biggl(\frac{2x'}{a^2}\biggr) + \boldsymbol{\hat\jmath'} \biggl\{ \biggl[\frac{2( y'\cos\theta - z'\sin\theta )\cos\theta}{b^2}\biggr] + \biggl[\frac{2( z_0 + z'\cos\theta + y'\sin\theta) \sin\theta}{c^2}\biggr] \biggr\} + \mathbf{\hat{k}'}\biggl\{- \biggl[\frac{2( y'\cos\theta - z'\sin\theta) \sin\theta}{b^2}\biggr] + \biggl[\frac{2 ( z_0 + z'\cos\theta + y'\sin\theta) \cos\theta}{c^2}\biggr] \biggr\} \, . </math> </td> </tr> </table> <span id="Orthogonal">Hence,</span> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\biggl( \frac{1}{2 x'}\biggr)\boldsymbol{u'}_\mathrm{EFE} \cdot \nabla P'</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl(\frac{1}{a^2}\biggr)\biggl\{\biggl[ \frac{a^2}{a^2 + c^2}\biggr] \zeta_2 z_0 \biggr\} + \biggl(\frac{1}{a^2}\biggr)\biggl\{ z' (c^2 - b^2 )\tan\theta - y' [c^2 + b^2 \tan^2\theta ] \biggr\}\frac{\zeta_3 \cos\theta}{c^2}\biggl[\frac{a^2}{a^2+b^2}\biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> + \biggl[ \frac{b^2}{a^2 + b^2}\biggr] \frac{\zeta_3 }{\cos\theta} \biggl\{ \biggl[\frac{( y'\cos\theta - z'\sin\theta )\cos\theta}{b^2}\biggr] + \biggl[\frac{( z_0 + z'\cos\theta + y'\sin\theta) \sin\theta}{c^2}\biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{\zeta_3 }{c^2(a^2 + b^2)}\biggr] b^2 z_0 \tan\theta + \biggl\{ z' (c^2 - b^2 )\tan\theta - y' [c^2 + b^2 \tan^2\theta ] \biggr\}\cos\theta \biggl[\frac{\zeta_3}{c^2(a^2+b^2)}\biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> + \biggl[ \frac{\zeta_3 }{c^2 (a^2 + b^2)}\biggr] \frac{1}{\cos\theta} \biggl\{ \biggl[c^2( y'\cos\theta - z'\sin\theta )\cos\theta\biggr] + \biggl[b^2 ( z_0 + z'\cos\theta + y'\sin\theta) \sin\theta\biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ \biggl[ \frac{c^2(a^2 + b^2)}{\zeta_3 }\biggr] \biggl( \frac{1}{2 x'}\biggr)\boldsymbol{u'}_\mathrm{EFE} \cdot \nabla P'</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - b^2 z_0 \tan\theta + \biggl\{ z' (c^2 - b^2 )\tan\theta - y' [c^2 + b^2 \tan^2\theta ] \biggr\}\cos\theta + \biggl[c^2( y'\cos\theta - z'\sin\theta )\biggr] + \biggl[b^2 ( z_0 + z'\cos\theta + y'\sin\theta) \tan\theta\biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl\{ z' (c^2 - b^2 )\tan\theta - y' [c^2 + b^2 \tan^2\theta ] \biggr\}\cos\theta + \biggl[c^2( y'\cos\theta - z'\sin\theta )\biggr] + \biggl[b^2 ( z'\cos\theta + y'\sin\theta) \tan\theta\biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> y' \cos\theta \biggl[- c^2 - b^2\tan^2\theta + c^2 + b^2\tan^2\theta \biggr] + z' \biggl[(c^2 - b^2) \sin\theta - c^2\sin\theta + b^2\sin\theta \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>0 \, .</math> </td> </tr> </table>
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