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====Improve First Approximation==== After slogging through the preceding "Second thru Fifth" approximations, I have come to appreciate that the approach used way back in the "[[Appendix/Ramblings/51BiPolytropeStability/BetterInterface#First_Approximation|First Approximation]]" was a good one, but that the attempt to introduce an implicit dependence was misguided. I now think I have discovered the preferable implicit treatment. Let's repeat, while improving this approach. =====2<sup>nd</sup>-Order Explicit Approach===== As was done in our earlier [[Appendix/Ramblings/51BiPolytropeStability/BetterInterface#First_Approximation|First Approximation]], let's set up a grid associated with a uniformly spaced spherical radius, where the subscript <math>J</math> denotes the grid zone at which all terms in the finite-difference representation of the governing relations will be evaluated. More specifically, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>\tilde{r}_{J-1}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \tilde{r}_J - \Delta\tilde{r} </math> </td> <td align="center"> and </td> <td align="right"><math>\tilde{r}_{J+1}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \tilde{r}_J + \Delta\tilde{r} \, ; </math> </td> </tr> </table> also, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>\biggl(\frac{dx}{d\tilde{r}}\biggr)_{J}</math></td> <td align="center"><math>\approx</math></td> <td align="left"> <math> \frac{(x_{J+1} - x_{J-1})}{2\Delta\tilde{r}} </math> </td> <td align="center"> and </td> <td align="right"><math>\biggl(\frac{dp}{d\tilde{r}}\biggr)_{J}</math></td> <td align="center"><math>\approx</math></td> <td align="left"> <math> \frac{(p_{J+1} - p_{J-1})}{2\Delta\tilde{r}} \, . </math> </td> </tr> </table> And at each grid location, the governing relations establish the local evaluation of the derivatives, that is, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>\biggl(\frac{dx}{d \tilde{r}}\biggr)_J </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> - \frac{1}{\tilde{r}_J}\biggl[ 3x + \frac{p}{\gamma_g}\biggr]_J \, , </math> </td> <td align="center"> and </td> <td align="right"><math>\biggl(\frac{dp}{d \tilde{r}}\biggr)_J </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{\tilde{\rho}_J}{\tilde{P}_J}\biggl[ (4x + p)\frac{\tilde{M}_r}{\tilde{r}^2} + \tau_c^2 \omega^2 \tilde{r} x \biggr]_J \, . </math> </td> </tr> </table> <span id="1stapprox">So, integrating</span> step-by-step from the center of the configuration, outward, once all the variable values are known at grid locations <math>J</math> and <math>(J-1)</math>, the values of <math>x</math> and <math>p</math> at <math>(J+1)</math> are given by the expressions, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>x_{J+1}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> x_{J-1} - 2\Delta\tilde{r} \biggl\{ \frac{1}{\tilde{r}}\biggl[ 3x + \frac{p}{\gamma_g}\biggr] \biggr\}_J \, , </math> </td> <td align="center"> and </td> <td align="right"><math>p_{J+1}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> p_{J-1} + 2\Delta\tilde{r} \biggl\{ \frac{\tilde{\rho}}{\tilde{P}} \cdot \frac{\tilde{M}_r}{\tilde{r}^2} \biggl[ (4x + p) + \sigma_c^2 \biggl(\frac{2\pi}{3} \cdot \frac{\tilde{\rho}_c \tilde{r}^3 }{\tilde{M}_r}\biggr) x \biggr] \biggr\}_J\, . </math> </td> </tr> </table> Then we will obtain the "<math>x_J</math>" and "<math>p_J</math>" values via the ''average'' expressions, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>x_{J}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{1}{2}(x_{J-1} + x_{J+1}) \, , </math> </td> <td align="center"> and </td> <td align="right"><math>p_{J}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{1}{2}(p_{J-1} + p_{J+1}) \, . </math> </td> </tr> </table> =====Convert to Implicit Approach===== Consider implementing an ''implicit'' finite-difference analysis that improves on our earlier [[Appendix/Ramblings/51BiPolytropeStability/BetterInterface#First_Approximation|First Approximation]]. The general form of the source term expressions is, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>x_{J+1}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> x_{J-1} + 2\Delta\tilde{r} \biggl\{ \mathfrak{A}x_J + \mathfrak{B}p_J \biggr\} </math> </td> </tr> </table> where, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>\mathfrak{A}</math></td> <td align="center"><math>\equiv</math></td> <td align="left"> <math> - \biggl\{ \frac{3}{\tilde{r}} \biggr\}_J \, , </math> </td> <td align="center"> and </td> <td align="right"><math>\mathfrak{B}</math></td> <td align="center"><math>\equiv</math></td> <td align="left"> <math> - \biggl\{ \frac{1}{\gamma_g \tilde{r}} \biggr\}_J \, ; </math> </td> </tr> </table> and, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>p_{J+1}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> p_{J-1} + 2\Delta\tilde{r} \biggl\{ \mathfrak{C}x_J + \mathfrak{D}p_J \biggr\} </math> </td> </tr> </table> where, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>\mathfrak{C}</math></td> <td align="center"><math>\equiv</math></td> <td align="left"> <math> \biggl\{ \mathfrak{D} \biggl[ 4 + \sigma_c^2 \biggl(\frac{2\pi}{3} \cdot \frac{\tilde{\rho}_c \tilde{r}^3 }{\tilde{M}_r}\biggr) \biggr] \biggr\}_J\, , </math> </td> <td align="center"> and </td> <td align="right"><math>\mathfrak{D}</math></td> <td align="center"><math>\equiv</math></td> <td align="left"> <math> \biggl\{ \frac{\tilde{\rho}}{\tilde{P}} \cdot \frac{\tilde{M}_r}{\tilde{r}^2} \biggr\}_J\, . </math> </td> </tr> </table> Now, wherever a "<math>J+1</math>" index appears in the source term, replace it with the ''average expressions''; specifically, <math>x_{J+1} \rightarrow (2 x_J - x_{J-1})</math> and <math>p_{J+1} \rightarrow (2 p_J - p_{J-1})</math>. For the fractional radial displacement, we have, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>x_J </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> x_{J-1} + \Delta\tilde{r} \biggl\{ \mathfrak{A}x_J + \mathfrak{B}p_J \biggr\} \, ; </math> </td> </tr> </table> and for the fractional pressure displacement, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>p_{J} </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> p_{J-1} + \Delta\tilde{r} \biggl\{ \mathfrak{C}x_J + \mathfrak{D}p_J \biggr\} \, . </math> </td> </tr> </table> Solving for <math>p_J</math> in this second expression, we obtain, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>p_{J}\biggl[ 1 - \mathfrak{D}\Delta\tilde{r}\biggr] </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> p_{J-1} + (\mathfrak{C}\Delta\tilde{r}) x_J </math> </td> </tr> </table> in which case the first expression gives, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>x_J </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> x_{J-1} + (\mathfrak{A} \Delta\tilde{r})x_J + (\mathfrak{B} \Delta\tilde{r}) \biggl[ p_{J-1} + (\mathfrak{C}\Delta\tilde{r}) x_J\biggr]\biggl[ 1 - \mathfrak{D}\Delta\tilde{r}\biggr]^{-1} </math> </td> </tr> <tr> <td align="right"><math>\Rightarrow ~~~ x_J \biggl[ 1 - \mathfrak{D}\Delta\tilde{r}\biggr]</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl\{ x_{J-1} + (\mathfrak{A} \Delta\tilde{r})x_J \biggr\}\biggl[ 1 - \mathfrak{D}\Delta\tilde{r}\biggr] + (\mathfrak{B} \Delta\tilde{r}) \biggl[ p_{J-1} + (\mathfrak{C}\Delta\tilde{r}) x_J\biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> x_{J-1} \biggl[ 1 - \mathfrak{D}\Delta\tilde{r}\biggr] + (\mathfrak{B} \Delta\tilde{r}) p_{J-1} + (\mathfrak{A} \Delta\tilde{r})x_J \biggl[ 1 - \mathfrak{D}\Delta\tilde{r}\biggr] + (\mathfrak{B} \Delta\tilde{r}) (\mathfrak{C}\Delta\tilde{r}) x_J </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> x_{J-1} ( 1 - \mathfrak{D}\Delta\tilde{r}) + (\mathfrak{B} \Delta\tilde{r}) p_{J-1} +\biggl[ (\mathfrak{A} \Delta\tilde{r}) ( 1 - \mathfrak{D}\Delta\tilde{r}) + (\mathfrak{B} \Delta\tilde{r}) (\mathfrak{C}\Delta\tilde{r}) \biggr] x_J </math> </td> </tr> <tr> <td align="right"><math> \Rightarrow ~~~ x_J \biggl\{ ( 1 - \mathfrak{D}\Delta\tilde{r} )- \biggl[ (\mathfrak{A} \Delta\tilde{r}) ( 1 - \mathfrak{D}\Delta\tilde{r}) + (\mathfrak{B} \Delta\tilde{r}) (\mathfrak{C}\Delta\tilde{r}) \biggr] \biggr\} </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> x_{J-1} ( 1 - \mathfrak{D}\Delta\tilde{r}) + (\mathfrak{B} \Delta\tilde{r}) p_{J-1} </math> </td> </tr> <tr> <td align="right"><math> \Rightarrow ~~~ x_J \biggl\{ 1 - \biggl[ (\mathfrak{A} \Delta\tilde{r}) + \frac{(\mathfrak{B} \Delta\tilde{r}) (\mathfrak{C}\Delta\tilde{r})}{ ( 1 - \mathfrak{D}\Delta\tilde{r} ) } \biggr] \biggr\} </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> x_{J-1} + \biggl[\frac{(\mathfrak{B} \Delta\tilde{r})}{( 1 - \mathfrak{D}\Delta\tilde{r} )}\biggr] p_{J-1} </math> </td> </tr> <tr> <td align="right"><math> \Rightarrow ~~~ x_J </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl\{ x_{J-1} + \biggl[\frac{(\mathfrak{B} \Delta\tilde{r})}{( 1 - \mathfrak{D}\Delta\tilde{r} )}\biggr] p_{J-1} \biggr\} \biggl\{ 1 - \biggl[ (\mathfrak{A} \Delta\tilde{r}) + \frac{(\mathfrak{B} \Delta\tilde{r}) (\mathfrak{C}\Delta\tilde{r})}{ ( 1 - \mathfrak{D}\Delta\tilde{r} ) } \biggr] \biggr\}^{-1} \, . </math> </td> </tr> </table> Then, <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math>p_{J}( 1 - \mathfrak{D}\Delta\tilde{r} ) </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> p_{J-1} + (\mathfrak{C}\Delta\tilde{r}) x_J </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> p_{J-1} + (\mathfrak{C}\Delta\tilde{r}) \biggl\{ x_{J-1} + \biggl[\frac{(\mathfrak{B} \Delta\tilde{r})}{( 1 - \mathfrak{D}\Delta\tilde{r} )}\biggr] p_{J-1} \biggr\} \biggl\{ 1 - \biggl[ (\mathfrak{A} \Delta\tilde{r}) + \frac{(\mathfrak{B} \Delta\tilde{r}) (\mathfrak{C}\Delta\tilde{r})}{ ( 1 - \mathfrak{D}\Delta\tilde{r} ) } \biggr] \biggr\}^{-1} </math> </td> </tr> </table> <table border=1 align="center" cellpadding="10" width="80%"><tr><td bgcolor="lightblue" align="left"> This is test of our "implicit" scheme for the <math>(n_c, n_e) = (5, 1)</math> bipolytrope with <math>\mu_e/\mu_c = 0.31</math> and (Model A) <math>\xi_i = 9.12744</math>; here, we also assume <math>\sigma_c^2 = 0.000109</math> and <math>J = i+2</math>. Here are the quantities that we assume are <b>known</b> … <table border="1" align="center" cellpadding="5"> <tr> <td align="center" bgcolor="white"><math>\tilde{r}</math></td> <td align="center" bgcolor="white"><math>\tilde\rho</math></td> <td align="center" bgcolor="white"><math>\tilde{P}</math></td> <td align="center" bgcolor="white"><math>\tilde{M}_r</math></td> <td align="center" bgcolor="white"><math>\tilde{\rho}_c</math></td> <td align="center" bgcolor="white"><math>\mathfrak{A}</math></td> <td align="center" bgcolor="white"><math>\mathfrak{B}</math></td> <td align="center" bgcolor="white"><math>\frac{\mathfrak{C}}{\mathfrak{D}}</math></td> <td align="center" bgcolor="white"><math>\mathfrak{D}</math></td> </tr> <tr> <td align="center" bgcolor="white">0.0193368</td> <td align="center" bgcolor="white">192.21728</td> <td align="center" bgcolor="white">1913.1421</td> <td align="center" bgcolor="white">0.3403116</td> <td align="center" bgcolor="white">3359266.406</td> <td align="center" bgcolor="white">-155.14459</td> <td align="center" bgcolor="white">-25.85743</td> <td align="center" bgcolor="white">4.0162932</td> <td align="center" bgcolor="white">91.443479</td> </tr> </table> <table border="1" align="center" cellpadding="5"> <tr> <td align="center" bgcolor="white"><math>\Delta\tilde{r}</math></td> <td align="center" bgcolor="white"><math>x_{J-1}</math></td> <td align="center" bgcolor="white"><math>p_{J-1}</math></td> <td align="center" bgcolor="white"><font size="-1">determined</font><br /><math>x_J</math></td> <td align="center" bgcolor="white"><font size="-1">determined</font><br /><math>p_J</math></td> </tr> <tr> <td align="center" bgcolor="white">0.001936393</td> <td align="center" bgcolor="white">-4.755073</td> <td align="center" bgcolor="white">32.25497</td> <td align="center" bgcolor="white">-4.999355</td> <td align="center" bgcolor="white">34.874915</td> </tr> </table> </td></tr> <tr><td bgcolor="white" align="center"> <table border="0" align="center" cellpadding="5"> <tr> <td align="right"><math> x_J </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl\{ x_{J-1} + \biggl[\frac{(\mathfrak{B} \Delta\tilde{r})}{( 1 - \mathfrak{D}\Delta\tilde{r} )}\biggr] p_{J-1} \biggr\} \biggl\{ 1 - \biggl[ (\mathfrak{A} \Delta\tilde{r}) + \frac{(\mathfrak{B} \Delta\tilde{r}) (\mathfrak{C}\Delta\tilde{r})}{ ( 1 - \mathfrak{D}\Delta\tilde{r} ) } \biggr] \biggr\}^{-1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl\{ x_{J-1} + \biggl[-0.06084379\biggr] p_{J-1} \biggr\} \biggl\{ 1 - \biggl[-0.3436910 \biggr] \biggr\}^{-1} = -4.999354 \, ; </math> </td> </tr> <tr> <td align="right"><math>p_{J}( 1 - \mathfrak{D}\Delta\tilde{r} ) </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ p_{J-1} + (\mathfrak{C}\Delta\tilde{r}) x_J \biggr]( 1 - \mathfrak{D}\Delta\tilde{r} )^{-1} = 34.87491 \, . </math> </td> </tr> </table> <tr><td bgcolor="lightblue" align="left"> <b>Best values:</b><br />Nodes 0: n/a <br />Nodes 1: <math>\sigma_c^2 = 8.958784\times 10^{-5}</math> <br />Nodes 2: <math>\sigma_c^2 = 3.021\times 10^{-4}</math> <br />Nodes 3: <math>\sigma_c^2 = 6.09\times 10^{-4}</math> </td></tr> </table> </td></tr></table>
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