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===Speculation1=== Building on our experience developing [[Appendix/Ramblings/T3Integrals#Integrals_of_Motion_in_T3_Coordinates|T3 Coordinates]] and, more recently, [[Appendix/Ramblings/EllipticCylinderCoordinates#T5_Coordinates|T5 Coordinates]], let's define the two "angles," <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\Zeta</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~\sinh^{-1}\biggl(\frac{qy}{x} \biggr)</math> </td> <td align="center"> and, </td> <td align="right"> <math>~\Upsilon</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~\sinh^{-1}\biggl(\frac{pz}{x} \biggr) \, ,</math> </td> </tr> </table> in which case we can write, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\lambda_1^2</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~x^2(\cosh^2\Zeta + \sinh^2\Upsilon)\, .</math> </td> </tr> </table> We speculate that the other two orthogonal coordinates may be defined by the expressions, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\lambda_2</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~x \biggl[ \sinh\Zeta \biggr]^{1/(1-q^2)} = x \biggl[ \frac{qy}{x}\biggr]^{1/(1-q^2)} = x \biggl[ \frac{x}{qy}\biggr]^{1/(q^2-1)} = \biggl[ \frac{x^{q^2}}{qy}\biggr]^{1/(q^2-1)} \, ,</math> </td> </tr> <tr> <td align="right"> <math>~\lambda_3</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~x \biggl[ \sinh\Upsilon \biggr]^{1/(1-p^2)} = x \biggl[ \frac{pz}{x}\biggr]^{1/(1-p^2)} = x \biggl[ \frac{x}{pz}\biggr]^{1/(p^2-1)} = \biggl[ \frac{x^{p^2}}{pz}\biggr]^{1/(p^2-1)} \, .</math> </td> </tr> </table> Some relevant partial derivatives are, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\frac{\partial \lambda_2}{\partial x}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl[ \frac{1}{qy}\biggr]^{1/(q^2-1)} \biggl[ \frac{q^2}{q^2-1} \biggr]x^{1/(q^2-1)} = \biggl[ \frac{q^2}{q^2-1} \biggr]\biggl[ \frac{x}{qy}\biggr]^{1/(q^2-1)} = \biggl[ \frac{q^2}{q^2-1} \biggr]\frac{\lambda_2}{x} \, ; </math> </td> </tr> <tr> <td align="right"> <math>~\frac{\partial \lambda_2}{\partial y}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl[ \frac{x^{q^2}}{q}\biggr]^{1/(q^2-1)} \biggl[ \frac{1}{1-q^2} \biggr] y^{q^2/(1-q^2)} = - \biggl[ \frac{1}{q^2-1} \biggr] \frac{\lambda_2}{y} \, ;</math> </td> </tr> <tr> <td align="right"> <math>~\frac{\partial \lambda_3}{\partial x}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{p^2}{p^2-1} \biggr]\frac{\lambda_3}{x} \, ; </math> </td> </tr> <tr> <td align="right"> <math>~\frac{\partial \lambda_3}{\partial z}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - \biggl[ \frac{1}{p^2-1} \biggr] \frac{\lambda_3}{z} \, .</math> </td> </tr> </table> And the associated scale factors are, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~h_2^2</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \biggl[ \biggl( \frac{q^2}{q^2-1} \biggr)\frac{\lambda_2}{x} \biggr]^2 + \biggl[ - \biggl( \frac{1}{q^2-1} \biggr) \frac{\lambda_2}{y} \biggr]^2 \biggr\}^{-1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \biggl( \frac{q^2}{q^2-1} \biggr)^2 \frac{\lambda_2^2}{x^2} + \biggl( \frac{1}{q^2-1} \biggr)^2 \frac{\lambda_2^2}{y^2} \biggr\}^{-1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{x^2 + q^4 y^2 \biggr\}^{-1} \biggl[ \frac{(q^2 - 1)^2x^2 y^2}{\lambda_2^2} \biggr] \, ; </math> </td> </tr> <tr> <td align="right"> <math>~h_3^2</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{x^2 + p^4 z^2 \biggr\}^{-1} \biggl[ \frac{(p^2 - 1)^2x^2 z^2}{\lambda_3^2} \biggr] \, . </math> </td> </tr> </table> We can now fill in the rest of our direction-cosines table, namely, <table border="1" cellpadding="8" align="center" width="60%"> <tr> <td align="center" colspan="4"> '''Direction Cosines for T6 Coordinates''' <br /> <math>~\gamma_{ni} = h_n \biggl( \frac{\partial \lambda_n}{\partial x_i}\biggr)</math> </td> </tr> <tr> <td align="center" width="10%"><math>~n</math></td> <td align="center" colspan="3"><math>~i = x, y, z</math> </tr> <tr> <td align="center"><math>~1</math></td> <td align="center"> <br /> <math>~x\ell_{3D}</math><br /> <td align="center"><math>~q^2 y \ell_{3D}</math> <td align="center"><math>~p^2 z \ell_{3D}</math> </tr> <tr> <td align="center"><math>~2</math></td> <td align="center"> <math>~q^2 y \ell_q </math> <td align="center"> <math>~-x\ell_q</math> <td align="center"> <math>~0</math> </td> </tr> <tr> <td align="center"><math>~3</math></td> <td align="center"> <math>~p^2 z \ell_p</math> </td> <td align="center"> <math>~0</math> </td> <td align="center"> <math>~-x\ell_p</math> </td> </tr> </table> Hence, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\hat{e}_2</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \hat\imath \gamma_{21} + \hat\jmath \gamma_{22} +\hat{k} \gamma_{23} = \hat\imath (q^2y\ell_q) - \hat\jmath (x\ell_q) \, ; </math> </td> </tr> <tr> <td align="right"> <math>~\hat{e}_3</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \hat\imath \gamma_{31} + \hat\jmath \gamma_{32} +\hat{k} \gamma_{33} = \hat\imath (p^2z\ell_p) -\hat{k} (x\ell_p) \, . </math> </td> </tr> </table> Check: <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\hat{e}_2 \cdot \hat{e}_2</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ (q^2y\ell_q)^2 + (x\ell_q)^2 = 1 \, ; </math> </td> </tr> <tr> <td align="right"> <math>~\hat{e}_3 \cdot \hat{e}_3</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ (p^2z\ell_p)^2 + (x\ell_p)^2 = 1 \, ; </math> </td> </tr> <tr> <td align="right"> <math>~\hat{e}_2 \cdot \hat{e}_3</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ (q^2y\ell_q)(p^2z\ell_p) \ne 0 \, . </math> </td> </tr> </table>
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