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===Regarding thought "D"=== <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~v_x\biggr|_\mathrm{tip}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~v_x\biggr|_\mathrm{body}</math> </td> </tr> <tr> <td align="right"> <math>~v_y\biggr|_\mathrm{tip}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~v_y|_\mathrm{body}\cdot \cos\theta + v_z|_\mathrm{body}\cdot \sin\theta</math> </td> </tr> <tr> <td align="right"> <math>~v_z\biggr|_\mathrm{tip}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~-v_y|_\mathrm{body}\cdot \sin\theta + v_z|_\mathrm{body}\cdot \cos\theta</math> </td> </tr> </table> Setting <math>~v_z\biggr|_\mathrm{tip} = 0</math> implies, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~v_y|_\mathrm{body}\cdot \sin\theta </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~v_z|_\mathrm{body}\cdot \cos\theta</math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \tan\theta </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl(\frac{v_z}{v_y}\biggr)_\mathrm{body}</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cdot \biggl[ \frac{b^2}{a^2 + b^2} \biggr]^{-1} \zeta_3^{-1}</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- \frac{\zeta_2}{\zeta_3}\biggl[ \frac{(c/a)^2}{1 + (c/a)^2} \biggr] \biggl[ \frac{(b/a)^2}{1 + (b/a)^2} \biggr]^{-1} \, .</math> </td> </tr> </table> For our particular example, then, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\tan\theta</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- \frac{2.2794}{1.9637}\biggl[ \frac{(0.4703)^2}{1 + (0.4703)^2} \biggr] \biggl[ \frac{(1.25)^2}{1 + (1.25)^2} \biggr]^{-1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- \frac{2.2794}{1.9637}\biggl[ \frac{(0.4703)^2}{1 + (0.4703)^2} \biggr] \biggl[ \frac{(1.25)^2}{1 + (1.25)^2} \biggr]^{-1} = - 0.3448</math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \theta</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\tan^{-1}(-0.3448) = - 19.0^{\circ} \, . </math> </td> </tr> </table> Now, given that, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~x</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~x_t \, ,</math> </td> </tr> <tr> <td align="right"> <math>~y</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~y_t \cos\theta - z_t \sin\theta \, ,</math> </td> </tr> <tr> <td align="right"> <math>~z</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~z_t \cos\theta + y_t \sin\theta \, ,</math> </td> </tr> </table> we can generate the following expressions for the fluid velocity components ''in'' the tipped plane: <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~v_z\biggr|_\mathrm{tip}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~0\, ,</math> </td> </tr> <tr> <td align="right"> <math>~v_x\biggr|_\mathrm{tip}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~v_x\biggr|_\mathrm{body}</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 y + \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 z</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \biggl[ y_t \cos\theta - z_t \sin\theta \biggr] + \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \biggl[ z_t \cos\theta + y_t \sin\theta \biggr]</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ y_t \biggl\{ \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \sin\theta - \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \cos\theta \biggr\} + z_t\biggl\{ \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \sin\theta + \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \cos\theta \biggr\} \, , </math> </td> </tr> <tr> <td align="right"> <math>~v_y\biggr|_\mathrm{tip}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~v_y|_\mathrm{body}\cdot \cos\theta + v_z|_\mathrm{body}\cdot \sin\theta</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 x \cdot \cos\theta - \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 x \cdot \sin\theta</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~x_t \biggl\{ \biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 \cdot \cos\theta - \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cdot \sin\theta \biggr\} \, .</math> </td> </tr> </table> Now, following our [[#Initial_Thoughts|earlier analysis for ''S-Type'' ellipsoids]], let's assume that, <div align="center"> <math>~x_t = x_\mathrm{max}\cos(\varphi t)</math> and, <math>~y_t = y_0 - y_\mathrm{max}\sin(\varphi t) \, .</math> </div> (Insertion of the extra term, y<sub>0</sub>, acknowledges that the center of the elliptical orbit in the "tipped" plane will be shifted off of the x-axis in the y<sub>t</sub>-direction; the size of this shift should correlate with z<sub>t</sub>, that is, with the vertical location of the tipped plane.) We have, then, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~v_y\biggr|_\mathrm{tip} = \frac{dy_t}{dt} = -y_\mathrm{max} \varphi \cos(\varphi t)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~x_\mathrm{max} \cos(\varphi t) \biggl\{ \biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 \cdot \cos\theta - \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cdot \sin\theta \biggr\} \, ,</math> </td> </tr> <tr> <td align="right"> <math>~v_x\biggr|_\mathrm{tip} = \frac{dx_t}{dt} = -x_\mathrm{max}\varphi \sin(\varphi t)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ y_0 - y_\mathrm{max} \sin(\varphi t) \biggr]\biggl\{ \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \sin\theta - \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \cos\theta \biggr\} + z_t\biggl\{ \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \sin\theta + \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \cos\theta \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - y_\mathrm{max} \sin(\varphi t) \biggl\{ \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \sin\theta - \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \cos\theta \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + y_0 \biggl\{ \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \sin\theta - \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \cos\theta \biggr\} + z_t\biggl\{ \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \sin\theta + \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \cos\theta \biggr\} \, . </math> </td> </tr> </table> So, in terms of the value of z<sub>t</sub>, the offset in y<sub>t</sub> must be, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ - y_0 \biggl\{ \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \sin\theta - \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \cos\theta \biggr\} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ + z_t\biggl\{ \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \sin\theta + \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \cos\theta \biggr\} \, ; </math> </td> </tr> </table> in which case, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ -y_\mathrm{max} \varphi \cos(\varphi t)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~x_\mathrm{max} \cos(\varphi t) \biggl\{ \biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 \cdot \cos\theta - \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cdot \sin\theta \biggr\} \, ,</math> </td> </tr> <tr> <td align="right"> <math>~ \Rightarrow ~~~ \varphi </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~-\biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] \biggl\{ \biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 \cdot \cos\theta - \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cdot \sin\theta \biggr\} \, ,</math> </td> </tr> </table> and, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~-x_\mathrm{max}\varphi \sin(\varphi t)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - y_\mathrm{max} \sin(\varphi t) \biggl\{ \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \sin\theta - \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \cos\theta \biggr\} </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \varphi </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr]\biggl\{ \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \sin\theta - \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \cos\theta \biggr\} \, . </math> </td> </tr> </table> In order for both of these expressions to be simultaneously true, we need, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] \biggl\{ \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cdot \sin\theta - \biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 \cdot \cos\theta \biggr\}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr]\biggl\{ \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \sin\theta - \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \cos\theta \biggr\} </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cdot \sin\theta - \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] \biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 \cdot \cos\theta </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \sin\theta - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \cos\theta </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cdot \sin\theta - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \sin\theta </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] \biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 \cdot \cos\theta - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \cos\theta </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \biggl\{ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] c^2 - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 \biggl\} \frac{\zeta_2 \sin\theta }{(a^2 + c^2)} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] b^2 - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 \biggr\} \frac{\zeta_3 \cos\theta }{(a^2 + b^2)} \, . </math> </td> </tr> </table> ====First Trial Value of θ==== Now, from above, we determined that the "tip" angle must obey the expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\tan\theta </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cdot \biggl[ \frac{b^2}{a^2 + b^2} \biggr]^{-1} \zeta_3^{-1} \, .</math> </td> </tr> </table> Hence, we require, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~- \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \cdot \biggl[ \frac{b^2}{a^2 + b^2} \biggr]^{-1} \zeta_3^{-1} \biggl\{ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] c^2 - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 \biggl\} \frac{\zeta_2 }{(a^2 + c^2)} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] b^2 - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 \biggr\} \frac{\zeta_3 }{(a^2 + b^2)} </math> </td> </tr> <tr> <td align="right"> <math>~ \Rightarrow ~~~ \biggl\{ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 - \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] c^2 \biggl\} \frac{c^2 \zeta_2^2 }{(a^2 + c^2)^2} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] b^2 - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 \biggr\} \frac{b^2\zeta_3^2 }{(a^2 + b^2)^2} </math> </td> </tr> <tr> <td align="right"> <math>~ \Rightarrow ~~~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr]^2 \frac{a^2 c^2 \zeta_2^2 }{(a^2 + c^2)^2} - \frac{c^4 \zeta_2^2 }{(a^2 + c^2)^2} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{b^4 \zeta_3^2 }{(a^2 + b^2)^2} - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr]^2 \frac{a^2 b^2\zeta_3^2 }{(a^2 + b^2)^2} \, . </math> </td> </tr> </table> That is, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr]^2 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{b^4 \zeta_3^2 }{(a^2 + b^2)^2} + \frac{c^4 \zeta_2^2 }{(a^2 + c^2)^2} \biggr] \biggl[ \frac{a^2 c^2 \zeta_2^2 }{(a^2 + c^2)^2} + \frac{a^2 b^2\zeta_3^2 }{(a^2 + b^2)^2} \biggr]^{-1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ b^4 \zeta_3^2 (a^2 + c^2)^2 + c^4 \zeta_2^2 (a^2 + b^2)^2 \biggr] \biggl[ a^2 c^2 \zeta_2^2 (a^2 + b^2)^2 + a^2 b^2\zeta_3^2 (a^2 + c^2)^2 \biggr]^{-1} \, . </math> </td> </tr> </table> So for the example parameters provided above, we have, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr]^2 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ 14.04 + 1.669 \biggr] \biggl[ 7.546 + 8.985 \biggr]^{-1} = 0.9502 </math> </td> </tr> <tr> <td align="right"> <math>~ \Rightarrow~~~ \frac{y_\mathrm{max}}{x_\mathrm{max}} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ 0.9748 </math> </td> </tr> </table> ====Second Trial Value of θ==== Instead, what if we obtain the tip angle straight from the tabulated expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\tan\theta</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{\zeta_3}{\zeta_2} \, .</math> </td> </tr> </table> Then we have, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ \biggl\{ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] c^2 - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 \biggl\} \frac{1 }{(a^2 + c^2)} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] b^2 - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 \biggr\} \frac{1 }{(a^2 + b^2)} </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] c^2 (a^2 + b^2) - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 (a^2 + b^2) </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] b^2 (a^2 + c^2) - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 (a^2 + c^2) </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow~~~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr]^2 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ c^2 (a^2 + b^2)- b^2 (a^2 + c^2) \biggr] \biggl[ a^2 (a^2 + b^2) - a^2 (a^2 + c^2) \biggr]^{-1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ [ c^2 - b^2 ] [ b^2 - c^2 ]^{-1} = -1 \, . </math> </td> </tr> </table> And this is not physically acceptable. What if, instead, we set, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\tan\theta</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- \frac{\zeta_3}{\zeta_2} ~~~\Rightarrow ~~~ \theta = -40.74^\circ \, .</math> </td> </tr> </table> Then we have, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ - \biggl\{ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] c^2 - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 \biggl\} \frac{1 }{(a^2 + c^2)} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] b^2 - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 \biggr\} \frac{1 }{(a^2 + b^2)} </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ - \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] c^2 (a^2 + b^2) + \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 (a^2 + b^2) </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] b^2 (a^2 + c^2) - \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] a^2 (a^2 + c^2) </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] [ a^2 (a^2 + b^2) + a^2 (a^2 + c^2) ] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] [ b^2 (a^2 + c^2) + c^2 (a^2 + b^2) ] </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr]^2 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ [ b^2 (a^2 + c^2) + c^2 (a^2 + b^2) ] [ a^2 (a^2 + b^2) + a^2 (a^2 + c^2) ]^{-1} \, . </math> </td> </tr> </table> In our particular example, this means, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr]^2 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ [ 2.4749 ] [ 3.7837 ]^{-1} = 0.6541 </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \biggl[ \frac{y_\mathrm{max}}{x_\mathrm{max}} \bigg] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ 0.8088 \, . </math> </td> </tr> </table>
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