Editing Appendix/Ramblings/Radiation/CodeUnits (section)

===Response from Dominic===
What he wrote on my whiteboard contained some mistakes.  For example, the correct code units for various quantities are:
* <math>[\rho_\mathrm{max}]_\mathrm{code} = 1.000</math>;
* <math>[M_\mathrm{Accretor}]_\mathrm{code} = 0.403</math>;
* <math>[R_\mathrm{Accretor}]_\mathrm{code} = 0.850</math>;
* <math>[P_\mathrm{orbit}]_\mathrm{code} = 31.2</math>;
* <math>[M_\mathrm{total}]_\mathrm{code} = 0.685</math>; and
* <math>[a_\mathrm{separation}]_\mathrm{code} = 2.58</math>.
And when he applies the unit conversions, he gets:
* <math>[\rho_\mathrm{max}]_\mathrm{cgs} = 5.12\times 10^3~\mathrm{g}~\mathrm{cm}^{-3}</math>;
* <math>[M_\mathrm{Accretor}]_\mathrm{cgs} = 0.569 M_\odot</math>;
* <math>[R_\mathrm{Accretor}]_\mathrm{cgs} = 0.100 R_\odot</math>;
* <math>[P_\mathrm{orbit}]_\mathrm{cgs} = 28.12~\mathrm{minutes}</math>; 
* <math>[M_\mathrm{total}]_\mathrm{cgs} = 0.968 M_\odot</math>; and
* <math>[a_\mathrm{separation}]_\mathrm{cgs} = 0.302 R_\odot</math>.

Two other pieces of information are needed in order to reconcile our numbers.  First, Dominic has included a value of {{Math/MP_MeanMolecularWeight}}<math>= 4/3</math> in his ''cgs'' value of {{Math/C_GasConstant}}, that is, he has set <math>\Re/\bar{\mu} = 6.236\times 10^7~\mathrm{cgs}</math>.  Second, the length-scale he has adopted in his rad-hydro code is different from the one that Wes provided straight from the SCF code.  In particular, Dominic ''thinks'' Wes sets,
<div align="center">
<math>
[\Delta R]_\mathrm{Wes\_code} = \frac{1}{128-3} = 8\times 10^{-3} ,
</math>
</div>
whereas, in order to conform to the constraints imposed by HAD, Dominic sets,
<div align="center">
<math>
[\Delta R]_\mathrm{Nic\_code} = \frac{\pi}{128} = 2.454\times 10^{-2} .
</math>
</div>
Hence, in order to transform from the ''code units'' used by Wes (and the SCF code) to ''code units'' used by Dominic, every quantity that includes a unit of length must be multiplied by,
<div align="center">
<math>\biggl[ \frac{\ell_\mathrm{Nic}}{\ell_\mathrm{Wes}}\biggr]_\mathrm{code} = \frac{\pi (128-3)}{128} = 3.067962.
</math></div>