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=====Second Guess===== Let's try again, keeping the same values of the <math>~b_0</math> and <math>~b_2</math> — that is, <div align="center"> <math>~(b_0 + b_2x^2) = (2-x^2)</math> <math>~\Rightarrow</math> <math>~b_0 = 2</math> and <math>~b_2 = -1</math> </div> — but leaving the values of <math>~a_0</math> and <math>~a_2</math> unspecified. In this case, the LAWE becomes, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ 0 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \alpha(a_0 + a_2x^2) (2 - x^2) + 2x^2(2n a_2 - m a_0) - 2x^4 (na_2 + m a_2) \biggr](5-3x^2)(a_0 + a_2x^2) -\sigma^2 (a_0 + a_2x^2)^2 (2 - x^2) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ - \biggl[ n a_2(2 - x^2) -m (a_0 + a_2x^2) + 4(2n a_2 - m a_0) - 4(na_2 + m a_2)x^2 - 4n m a_2 x^2 \biggr](1-x^2)(2-x^2)(a_0 + a_2x^2) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ - \biggl[2n(n-1) a_2^2(2 - x^2)^2 + 2m(m-1) (a_0 + a_2x^2)^2 \biggr]x^2 (1-x^2) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \alpha [2a_0 ] + x^2[(4n a_2 - 2m a_0) + \alpha (2a_2-a_0) ] - x^4 [(2na_2 + 2ma_2 ) + a_2\alpha ]\biggr\} [ 5a_0 + (5a_2-3a_0)x^2 -3a_2x^4] -\sigma^2 [ 2a_0 + (2a_2-a_0)x^2 - a_2x^4 ] (a_0+a_2x^2) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + \biggl[ ( 5m a_0 - 10n a_2) + (4n m a_2 + 5na_2 + 5m a_2)x^2 \biggr] (1-x^2)[ 2a_0 + (2a_2-a_0)x^2 - a_2x^4 ] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ - \biggl\{ [ 8n(n-1) a_2^2 + 2m(m-1)a_0^2 ] + [ -8n(n-1) a_2^2 + 4m(m-1)a_0 a_2 ]x^2 + [ 2n(n-1) a_2^2 + 2m(m-1)a_2^2 ]x^4 \biggr\} x^2 (1-x^2) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \alpha [2a_0 ] + x^2[(4n a_2 - 2m a_0) + \alpha (2a_2-a_0) ] - x^4 [(2na_2 + 2ma_2 ) + a_2\alpha ]\biggr\} [ 5a_0 + (5a_2-3a_0)x^2 -3a_2x^4] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ -\sigma^2\biggl\{ 2a_0^2 + [2a_0a_2 + a_0(2a_2-a_0)]x^2 +[a_2(2a_2-a_0) -a_0a_2]x^4 - a_2^2 x^6 \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + \biggl\{ [ ( 5m a_0 - 10n a_2) ] + [(4n m a_2 + 5na_2 + 5m a_2)- ( 5m a_0 - 10n a_2) ]x^2 - [ 4n m a_2 + 5na_2 + 5m a_2 ]x^4 \biggr\} [ 2a_0 + (2a_2-a_0)x^2 - a_2x^4 ] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ - \biggl\{ [ 8n(n-1) a_2^2 + 2m(m-1)a_0^2 ]x^2 + [ -8n(n-1) a_2^2 + 4m(m-1)a_0 a_2 ]x^4 + [ 2n(n-1) a_2^2 + 2m(m-1)a_2^2 ]x^6 \biggr\} (1-x^2) \, . </math> </td> </tr> </table> </div> So, the coefficients of each even power of <math>~x^n</math> are: <div align="center" id="FirstTable"> <table border="1" cellpadding="8" align="center"> <tr> <td align="right"><math>~x^0</math></td> <td align="center"> : </td> <td align="left"> <math>~ 10a_0^2 \alpha - 2a_0^2\sigma^2 + 2a_0[ ( 5m a_0 - 10n a_2) ] </math> </td> </tr> <tr> <td align="right"><math>~x^2</math></td> <td align="center"> : </td> <td align="left"> <math>~5a_0[(4n a_2 - 2m a_0) + \alpha (2a_2-a_0) ] + \alpha [2a_0 ](5a_2-3a_0)-\sigma^2[2a_0a_2 + a_0(2a_2-a_0)] </math><p> <math>~+ 2a_0[(4n m a_2 + 5na_2 + 5m a_2)- ( 5m a_0 - 10n a_2) ] + (2a_2-a_0)[ ( 5m a_0 - 10n a_2) ] - [ 8n(n-1) a_2^2 + 2m(m-1)a_0^2 ] </math></p> </td> </tr> <tr> <td align="right"><math>~x^4</math></td> <td align="center"> : </td> <td align="left"> <math>~ - 5a_0[(2na_2 + 2ma_2 ) + a_2\alpha ] + (5a_2-3a_0)[(4n a_2 - 2m a_0) + \alpha (2a_2-a_0) ] - 6a_0 a_2\alpha -\sigma^2[a_2(2a_2-a_0) -a_0a_2] </math><p> <math>~- 2a_0[ 4n m a_2 + 5na_2 + 5m a_2 ] + (2a_2-a_0)[(4n m a_2 + 5na_2 + 5m a_2)- ( 5m a_0 - 10n a_2) ] - a_2(5ma_0 - 10na_2) </math></p><p> <math>~-[ -8n(n-1) a_2^2 + 4m(m-1)a_0 a_2 ] + [ 8n(n-1) a_2^2 + 2m(m-1)a_0^2 ] </math></p> </td> </tr> <tr> <td align="right"><math>~x^6</math></td> <td align="center"> : </td> <td align="left"> <math>~ -3a_2[(4n a_2 - 2m a_0) + \alpha (2a_2-a_0) ] - (5a_2-3a_0)[(2na_2 + 2ma_2 ) + a_2\alpha ] +\sigma^2 a_2^2 </math><p> <math>~- (2a_2-a_0)[ 4n m a_2 + 5na_2 + 5m a_2 ] - a_2[(4n m a_2 + 5na_2 + 5m a_2)- ( 5m a_0 - 10n a_2) ] </math></p><p> <math>~- [ 2n(n-1) a_2^2 + 2m(m-1)a_2^2 ] + [ -8n(n-1) a_2^2 + 4m(m-1)a_0 a_2 ] </math></p> </td> </tr> <tr> <td align="right"><math>~x^8</math></td> <td align="center"> : </td> <td align="left"> <math>~ 3a_2 a_2\alpha + a_2[ 4n m a_2 + 11na_2 + 11m a_2 ] + [ 2n(n-1) a_2^2 + 2m(m-1)a_2^2 ] </math> </td> </tr> </table> </div> After simplification: <div align="center" id="FirstTable"> <table border="1" cellpadding="8" align="center"> <tr> <td align="right"><math>~x^0</math></td> <td align="center"> : </td> <td align="left"> <math>~ 10a_0^2 \alpha - 2a_0^2\sigma^2 + 10m a_0^2 - 20n a_0a_2 </math> </td> </tr> <tr> <td align="right"><math>~x^2</math></td> <td align="center"> : </td> <td align="left"> <math>~\alpha (20a_0a_2-11a_0^2) -\sigma^2[4a_0a_2 -a_0^2] </math><p> <math>~+ 60na_0a_2 -20na_2^2 + 20m a_0a_2 -25m a_0^2 + 8n m a_0a_2 - [ 8n(n-1) a_2^2 + 2m(m-1)a_0^2 ] </math></p> </td> </tr> <tr> <td align="right"><math>~x^4</math></td> <td align="center"> : </td> <td align="left"> <math>~ \alpha (10a_2^2 - 22a_0a_2+3a_0^2) -\sigma^2 (2a_2^2 -2a_0a_2) -47n a_0a_2 + 60n a_2^2 - 50ma_0a_2 + 11m a_0^2 + 10m a_2^2-12n m a_0a_2 + 8n m a_2^2 </math><p> <math>~+ 16n(n-1) a_2^2 - 4m(m-1)a_0 a_2 + 2m(m-1)a_0^2 </math></p> </td> </tr> <tr> <td align="right"><math>~x^6</math></td> <td align="center"> : </td> <td align="left"> <math>~ \alpha (-11a_2^2 + 6a_0 a_2) +\sigma^2 a_2^2 -47n a_2^2 + 11na_0a_2+ 22 m a_0a_2 -25ma_2^2 -12n m a_2^2 + 4n m a_0a_2 </math><p> <math>~-10n(n-1) a_2^2 - 2m(m-1)a_2^2 + 4m(m-1)a_0 a_2 </math></p> </td> </tr> <tr> <td align="right"><math>~x^8</math></td> <td align="center"> : </td> <td align="left"> <math>~ \{ 3\alpha + [ 4n m + 11n + 11m ] + [ 2n(n-1) + 2m(m-1) ]\}a_2^2 </math> </td> </tr> </table> </div> ----
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