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==Relationship to Detailed Force Balance Solution== Let's plug these form-factors into our expressions for the dimensionless equilibrium radius, <math>~\chi_\mathrm{ad}</math>, and dimensionless surface pressure, <math>~\Pi_\mathrm{ad}</math>, that have been derived from the identification of extrema in the free-energy function and see how they compare to the dimensionless radius, <math>~r_a \equiv R_\mathrm{eq}/R_\mathrm{Horedt}</math>, and dimensionless pressure, <math>~p_a \equiv P_e/P_\mathrm{Horedt}</math>, given by the detailed force-balance models provided by {{ Horedt70 }}. Note that expressions for <math>~r_a</math> and <math>~p_a</math> are given in our [[SSC/Structure/PolytropesEmbedded#Horedt.27s_Presentation|accompanying discussion of embedded polytropic spheres]] and that the conversion from the {{ Horedt70 }} scaling parameters to our normalization parameters, <math>~R_\mathrm{Horedt}/R_\mathrm{norm}</math> and <math>~P_\mathrm{Horedt}/P_\mathrm{norm}</math>, can be found in our [[SSCpt1/Virial#Normalizations|introductory discussion of the virial equilibrium of spherical configurations]]. <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\chi_\mathrm{ad} \equiv \frac{R_\mathrm{eq}}{R_\mathrm{ad}}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{R_\mathrm{eq}}{R_\mathrm{Horedt}} \biggl( \frac{R_\mathrm{Horedt}}{R_\mathrm{norm}} \biggr) \biggl( \frac{R_\mathrm{norm}}{R_\mathrm{ad}} \biggr)</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~r_a \biggl[ \biggl(\frac{\gamma - 1}{\gamma}\biggr) (4\pi)^{\gamma-1}\biggr]^{1/(4-3\gamma)} \biggl[ 5 \biggl( \frac{4\pi}{3} \biggr)^{1-\gamma_g} \frac{\mathfrak{f}_A}{\mathfrak{f}_W \mathfrak{f}_M^{\gamma_g-2}} \biggr]^{1/(4-3\gamma_g)} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~r_a \biggl[ 5 \cdot 3^{\gamma-1} \biggl(\frac{\gamma - 1}{\gamma}\biggr) \frac{\mathfrak{f}_A \mathfrak{f}_M^{2-\gamma_g}}{\mathfrak{f}_W } \biggr]^{1/(4-3\gamma_g)} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> r_a \biggl[ \frac{5 \cdot 3^{1/n} }{n+1} \cdot \frac{\mathfrak{f}_A \mathfrak{f}_M^{(n-1)/n}}{\mathfrak{f}_W } \biggr]^{n/(n-3)} = r_a \biggl[ 3 \mathfrak{f}_M^{n-1} \biggl( \frac{5 }{n+1} \cdot \frac{\mathfrak{f}_A }{\mathfrak{f}_W }\biggr)^n \biggr]^{1/(n-3)} </math> </td> </tr> <tr> <td align="right"> <math>~\Pi_\mathrm{ad} \equiv \frac{P_\mathrm{e}}{P_\mathrm{ad}}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{P_\mathrm{e}}{P_\mathrm{Horedt}} \biggl( \frac{P_\mathrm{Horedt}}{P_\mathrm{norm}} \biggr) \biggl( \frac{P_\mathrm{norm}}{P_\mathrm{ad}} \biggr)</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~p_a \biggl[ \biggl( \frac{\gamma}{\gamma-1}\biggr)^{3\gamma} (4\pi)^{-\gamma} \biggr]^{1/(4-3\gamma)} \biggl[ \mathfrak{f}_A^{-4} \biggl( \frac{4\pi}{3\cdot 5^3} \cdot \frac{\mathfrak{f}_W^3}{\mathfrak{f}_M^2} \biggr)^{\gamma_g} \biggr]^{1/(4-3\gamma_g)} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~p_a \mathfrak{f}_A^{-4/(4-3\gamma)} \biggl[ \biggl( \frac{\gamma}{\gamma-1}\biggr)^{3} \biggl( \frac{1}{3\cdot 5^3} \cdot \frac{\mathfrak{f}_W^3}{\mathfrak{f}_M^2} \biggr)\biggr]^{\gamma/(4-3\gamma)} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> ~p_a \mathfrak{f}_A^{-4n/(n-3)} \biggl[ \frac{(n+1)^3}{3\cdot 5^3} \cdot \frac{\mathfrak{f}_W^3}{\mathfrak{f}_M^2} \biggr]^{(n+1)/(n-3)} </math> </td> </tr> </table> </div> Now we insert the form-factor expressions [[SSC/Virial/Polytropes#Summary|from above]], to obtain, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\chi_\mathrm{ad} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> r_a \biggl[ 3 \biggl( \frac{5 }{n+1} \biggr)^n \biggr]^{1/(n-3)} \biggl[ \frac{\mathfrak{f}_A^n \mathfrak{f}_M^{n-1} }{\mathfrak{f}_W^n } \biggr]^{1/(n-3)} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> r_a \biggl[ 3 \biggl( \frac{5 }{n+1} \biggr)^n \biggr]^{1/(n-3)} \biggl\{ \biggl[ \frac{3(n+1) }{(5-n)} ~( \Theta^' )^2 \biggr]^n \biggl[ \frac{3^2\cdot 5}{5-n} \biggl( \frac{\Theta^'}{\xi} \biggr)^2 \biggr]^{-n} \biggl[ - \frac{3\Theta^'}{\xi} \biggr]^{n-1} \biggr\}^{1/(n-3)}_{\xi_1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> r_a \biggl\{ 3^n \biggl( \frac{5 }{n+1} \biggr)^n \biggl[ \frac{3(n+1) }{(5-n)} \biggr]^n \biggl[ \frac{5-n}{3^2\cdot 5} \biggr]^{n} \biggr\}^{1/(n-3)} \biggl\{ \xi^{2n} \biggl[ - \frac{\Theta^'}{\xi} \biggr]^{n-1} \biggr\}^{1/(n-3)}_{\xi_1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> r_a \biggl[ \xi^{n+1} ( - \Theta^' )^{n-1} \biggr]^{1/(n-3)}_{\xi_1} </math> </td> </tr> <tr> <td align="right"> <math>~\Pi_\mathrm{ad} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> ~p_a \mathfrak{f}_A^{-4n/(n-3)} \biggl[ \frac{(n+1)^3}{3\cdot 5^3} \cdot \frac{\mathfrak{f}_W^3}{\mathfrak{f}_M^2} \biggr]^{(n+1)/(n-3)} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~p_a \biggl[ \frac{3(n+1) }{(5-n)} ~( \Theta^' )^2 \biggr]_{\tilde\xi}^{-4n/(n-3)} \biggl\{ \frac{(n+1)^3}{3\cdot 5^3} \cdot \biggl[\frac{3^2\cdot 5}{5-n} \biggl( \frac{\Theta^'}{\xi} \biggr)^2\biggr]^3 \biggl[ - \frac{3\Theta^'}{\xi} \biggr]^{-2} \biggr\}^{(n+1)/(n-3)}_{\xi_1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> ~p_a \biggl\{ \biggl[ \frac{5-n}{3(n+1)} \biggr]^{4n} \biggl[ \frac{(n+1)^3 \cdot 3^6 \cdot 5^3}{3^3 \cdot 5^3 (5-n)^3} \biggr]^{(n+1)} \biggr\}^{1/(n-3)} \biggl[ ( \Theta^' )^{-8n} \biggl( \frac{\Theta^'}{\xi} \biggr)^{4(n+1)} \biggr]^{1/(n-3)}_{\xi_1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> ~p_a \biggl[ \frac{5-n}{3(n+1)} \biggr] \biggl[\xi^{n+1} ( \Theta^' )^{n-1} \biggr]^{-4/(n-3)}_{\xi_1} </math> </td> </tr> </table> </div> Notice that the bracketed term that is to be evaluated at <math>\xi_1</math> is identical in both expressions. After [[SSC/Virial/Polytropes#Renormalization|renormalization, as derived above]], the statement of virial equilibrium for embedded polytropes is, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\chi_\mathrm{ad}^4</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{1}{\Pi_\mathrm{ad}} \biggl[ \chi_\mathrm{ad}^{4-3\gamma_g} - 1 \biggr] \, ,</math> </td> </tr> </table> </div> or, setting <math>~\gamma_g = (n+1)/n</math>, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\Pi_\mathrm{ad} \chi_\mathrm{ad}^4</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\chi_\mathrm{ad}^{(n-3)/n} - 1 \, .</math> </td> </tr> </table> </div> This relation can now be written in terms of the {{ Horedt70 }} dimensionless radius and pressure. <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> ~p_a \biggl[ \frac{5-n}{3(n+1)} \biggr] \biggl[\xi^{n+1} ( \Theta^' )^{n-1} \biggr]^{-4/(n-3)}_{\xi_1} \cdot r_a^4 \biggl[ \xi^{n+1} ( - \Theta^' )^{n-1} \biggr]^{4/(n-3)}_{\xi_1} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ r_a^{(n-3)/n} \biggl[ \xi^{n+1} ( - \Theta^' )^{n-1} \biggr]^{1/n}_{\xi_1} - 1</math> </td> </tr> </table> </div> <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> \Rightarrow ~~~~ p_a r_a^4 \biggl[ \frac{5-n}{3(n+1)} \biggr] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ r_a^{(n-3)/n} \biggl[ \xi^{n+1} ( - \Theta^' )^{n-1} \biggr]^{1/n}_{\xi_1} - 1 \, ,</math> </td> </tr> </table> </div> where, from our separate [[SSC/Structure/PolytropesEmbedded#Horedt.27s_Presentation|summary of Horedt's presentation]], <div align="center"> <table border="0" cellpadding="3"> <tr> <td align="right"> <math> ~r_a </math> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math> \tilde\xi ( -\tilde\xi^2 \tilde\theta' )^{(1-n)/(n-3)} = \biggl[ \tilde\xi^{n+1} (-\tilde\theta^')^{n-1} \biggr]^{-1/(n-3)}\, , </math> </td> </tr> <tr> <td align="right"> <math> ~p_a </math> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math> \tilde\theta_n^{n+1}( -\tilde\xi^2 \tilde\theta' )^{2(n+1)/(n-3)} \, . </math> </td> </tr> </table> </div> Hence, the virial relation becomes, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> ~1 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \frac{ [ \xi^{n+1} ( - \Theta^' )^{n-1} ]_{\xi_1} }{ [ \tilde\xi^{n+1} (-\tilde\theta^')^{n-1} ] } \biggr\}^{1/n} - \biggl[ \frac{5-n}{3(n+1)} \biggr] \tilde\theta_n^{n+1} \biggl\{ \frac{( -\tilde\xi^2 \tilde\theta' )^{2(n+1)/(n-3)}}{ [ \tilde\xi^{n+1} (-\tilde\theta^')^{n-1} ]^{4/(n-3)} } \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{ \xi_1^{n+1} ( - \Theta^' )^{n-1}_{\xi_1} }{ \tilde\xi^{n+1} (-\tilde\theta^')^{n-1} } \biggr]^{1/n} - \biggl[ \frac{5-n}{3(n+1)} \biggr] \tilde\theta_n^{n+1} \biggl\{ \frac{ \tilde\xi^{4n+4} ( -\tilde\theta' )^{2n+2}}{ \tilde\xi^{4n+4} (-\tilde\theta^')^{4n-4} } \biggr\}^{1/(n-3)} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{ \xi_1^{n+1} ( - \Theta^' )^{n-1}_{\xi_1} }{ \tilde\xi^{n+1} (-\tilde\theta^')^{n-1} } \biggr]^{1/n} - \biggl[ \frac{5-n}{3(n+1)} \biggr] \frac{ \tilde\theta_n^{n+1} }{ ( -\tilde\theta' )^{2} } \, .</math> </td> </tr> </table> </div> This needs to be checked, perhaps with specific applications to the cases <math>~n=1</math> and <math>~n=5</math>.
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