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===Review Article by Cox (1974)=== In an excellent review of "Pulsating Stars", [http://adsabs.harvard.edu/abs/1974RPPh...37..563C J. P. Cox (1974, Reports on Progress in Physics, 37, 563)] presents a full derivation of, what he refers to as, the ''adiabatic wave equation''. It appears as equation (5.34) in the form displayed in the following boxed-in image: <div align="center"> <table border="1" cellpadding="5" width="75%"> <tr> <th align="center"> ''Adiabatic Wave Equation'' extracted<sup>†</sup> from [http://adsabs.harvard.edu/abs/1974RPPh...37..563C J. P. Cox (1974)]<p></p> "''Pulsating Stars''"<p></p> Reports on Progress in Physics, vol. 37, pp. 563 - 698 © [http://iopscience.iop.org/ IOP Publishing] </th> <tr> <td> [[File:Christy1966Eq5.png|600px|center|Cox (1974)]] </td> </tr> <tr><td align="left"><sup>†</sup>Equation displayed here, as a single digital image, exactly as it appears in the original publication.</td></tr> </table> </div> Recognizing the correspondence with our derived expression requires, first, switching the independent variable from <math>~m</math> to <math>~r_0</math> via the relation [[#Consistent_Lagrangian_Formulation|identified, above]], namely, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ \frac{d}{dm} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{1}{4\pi \rho_0 r_0^2} \cdot \frac{d}{dr_0} \, , </math> </td> </tr> </table> </div> to obtain, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~ \sigma^2 \xi </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - \frac{1}{(4\pi \rho_0 r_0^4)}\frac{d}{dr_0}\biggl[ (4\pi \Gamma_1 P_0 r_0^4) \frac{d\xi}{dr_0} \biggr] - \frac{1}{\rho_0 r_0} \biggl\{ \frac{d}{dr_0} [ (3\Gamma_1-4)P_0] \biggr\} \xi </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - \frac{\Gamma_1 P_0 }{\rho_0 }\frac{d^2 \xi}{dr_0^2} - \frac{\Gamma_1 }{(\rho_0 r_0^4)} \biggl[4P_0 r_0^3 + r_0^4\frac{dP_0}{dr_0} \biggr] \frac{d\xi}{dr_0} + \frac{(4-3\Gamma_1)}{\rho_0 r_0} \biggl[ \frac{dP_0}{dr_0} \biggr] \xi </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~~ 0</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - \frac{\Gamma_1 P_0 }{\rho_0 }\biggl\{ \frac{d^2 \xi}{dr_0^2} + \biggl[\frac{4}{r_0} + \frac{1}{P_0}\frac{dP_0}{dr_0} \biggr] \frac{d\xi}{dr_0} \biggr\} - \biggl\{ \sigma^2 - \frac{(4-3\Gamma_1)}{\rho_0 r_0} \biggl[ \frac{dP_0}{dr_0} \biggr] \biggr\} \xi \, . </math> </td> </tr> </table> </div> Then, using the definition of <math>~g_0</math>, also [[#Euler_.2B_Poisson_Equations|as provided above]], to facilitate the substitution, <div align="center"> <math>~\frac{dP_0}{dr_0} \rightarrow - g_0 \rho_0 \, ,</math> </div> gives, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~0</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{d^2 \xi}{dr_0^2} + \biggl[\frac{4}{r_0} - \frac{g_0 \rho_0}{P_0}\biggr] \frac{d\xi}{dr_0} + \frac{\rho_0 }{\Gamma_1 P_0 }\biggl\{ \sigma^2 + \frac{(4-3\Gamma_1)g_0}{r_0} \biggr\} \xi \, , </math> </td> </tr> </table> </div> which, apart from the adoption of different variable names, exactly matches our derived expression.
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