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==Examples== ===Isothermal Core with <math>n_e=3/2</math>=== Consider the case examined by [http://adsabs.harvard.edu/abs/1942ApJ....96..161S Schönberg & Chandrasekhar (1942)], that is, the case of an isothermal core and an envelope with <math>n_e = 3/2</math>. The equilibrium radius is given by the expression, <div align="center"> <table border="0" cellpadding="5"> <tr> <td align="right"> <math> \chi_E^{-1} </math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \alpha - \beta_I \chi_E \, </math> </td> </tr> <tr> <td align="right"> <math> \Rightarrow ~~~~~ \beta_I \chi_E^{2} -\alpha \chi_E + 1 </math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 0 \, </math> </td> </tr> <tr> <td align="right"> <math> \Rightarrow ~~~~~ \chi_E </math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{1}{2\beta_I} \biggl[\alpha \pm \biggr(\alpha^2-4\beta_I \biggr)^{1/2}\biggr] \, </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{\alpha}{2\beta_I} \biggl[1 \pm \biggr(1-\frac{4\beta_I}{\alpha^2} \biggr)^{1/2}\biggr] \, . </math> </td> </tr> </table> </div> And the system is stable when, <div align="center"> <math> \chi_E < \chi_0 \equiv \frac{\alpha }{2\beta_I} \, . </math> </div> A couple of physical attributes are now clear: *Physical configurations only exist for <math>(4\beta_I/\alpha^2) \le 1</math>. *For each value of <math>(4\beta_I/\alpha^2) < 1 \,</math>, there are two equilibrium configurations, given by the <math>\pm</math> roots of the quadratic equation for <math>\chi_E</math>; the "negative" branch is stable but the "positive" branch is unstable. Note that, <div align="center"> <math> \chi_0 \equiv \frac{\alpha }{2\beta_I} = \biggl( \frac{GM_\mathrm{tot}}{10R_0 c_s^2} \biggr) \frac{\nu f(\nu,q)}{q} ~~~\Rightarrow ~~~ \biggl( \frac{10R_0 c_s^2}{GM_\mathrm{tot}} \biggr) = \frac{\nu f(\nu,q)}{q \chi_0} \, , </math> </div> and, <div align="center"> <math> \frac{4\beta_I}{\alpha^2 } = \biggl( \frac{10 R_0 c_s^2 }{GM_\mathrm{tot}} \biggr)^2 \biggl[ \frac{K_e (\rho_e|_0)^{1/n_e}}{c_s^2} \biggr] \frac{q^2(1-\nu)}{\nu^3 f^2(\nu,q)} = \biggl[ \frac{K_e (\rho_e|_0)^{1/n_e}}{c_s^2} \biggr] \frac{q^2(1-\nu)}{\nu^3 f^2(\nu,q)} \biggl[\frac{\nu f(\nu,q)}{q \chi_0} \biggr]^2 = \biggl[ \frac{\mu_c}{\mu_e} \biggr] \biggl( \frac{1}{\nu} - 1 \biggr) \, . </math> </div> But, this last expression must be less than or equal to unity, which implies, <div align="center"> <math> \frac{1}{\nu} \le 1 + \frac{\mu_e}{\mu_c} ~~~\Rightarrow ~~~ \nu \ge \biggl(1 + \frac{\mu_e}{\mu_c} \biggr)^{-1} </math> This doesn't seem to have the correct behavior, for example, the smaller values of <math>\nu</math> should be the stable ones, so there must be a mistake in the derivation. </div> ===Adiabatic Core with <math>n_c = 5</math> and <math>n_e=1</math>=== Consider the case with an analytical structure derived by [http://adsabs.harvard.edu/abs/1998MNRAS.298..831E Eagleton, Faulkner, and Cannon] (1998, MNRAS, 298, 831), that is, the case of an adiabatic core having <math>n_c=5</math> and an envelope with <math>n_e = 1</math>. The equilibrium radius is,
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