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====Leading (Upsilon) Coefficient==== <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\Upsilon_{W1}(\eta_0)</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left" colspan="2"> <math>~\biggl[ \frac{\sinh\eta_0}{\cosh\eta_0}\biggr] \biggl\{ K(k_0)\cdot K(k_0) [\cosh\eta_0(1 - \cosh\eta_0)] +~2K(k_0)\cdot E(k_0) [(3\cosh^2\eta_0 - 1)] -~5 E(k_0)\cdot E(k_0) [\cosh\eta_0(1+\cosh\eta_0)] \biggr\} </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow~~~ \biggl[ \frac{e^2}{ (1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left" colspan="2"> <math>~ - (1-e)K(k_0)\cdot K(k_0) +~2(3-e^2)K(k_0)\cdot E(k_0) -~5(1+e) E(k_0)\cdot E(k_0) \, . </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \frac{2^2}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - (1-e) \biggl[ 1 + \frac{1}{2} k_0^2 + \frac{11}{2^5} ~k_0^4 + \frac{17}{2^6} ~ k_0^6 + \frac{1787}{2^{13}} ~k_0^8 + \mathcal{O}(k_0^{10}) \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + 2 (3-e^2) \biggl[ 1 ~+~\frac{1}{2^5} ~k_0^4 ~+~\frac{1}{2^5} ~ k_0^6 ~+~ \frac{231}{2^{13}}~k_0^8 + \mathcal{O}(k_0^{10}) \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ - 5(1+e) \biggl[ 1 - ~\frac{1}{2} ~k_0^2 ~ -~ \frac{1}{2^5} ~ k_0^4 ~ ~-~\frac{1}{2^6} ~ k_0^6 ~-~\frac{77}{2^{13}}~k_0^8 + \mathcal{O}(k_0^{10}) \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - (1-e) \biggl[ 1 + \frac{1}{2} \cdot 2e( 1 - e +e^2 - e^3 ) + \frac{11}{2^5} ~\cdot 4e^2( 1 - 2e + 3e^2 ) + \frac{17}{2^6} ~ \cdot 2^3e^3( 1 - 3e ) + \frac{1787}{2^{13}} ~\cdot 2^4e^4 + \mathcal{O}(e^{5}) \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + 2 (3-e^2) \biggl[ 1 ~+~\frac{1}{2^5} ~\cdot 4e^2( 1 - 2e + 3e^2 ) ~+~\frac{1}{2^5} ~ \cdot 2^3e^3( 1 - 3e ) ~+~ \frac{231}{2^{13}}~\cdot 2^4e^4 + \mathcal{O}(e^{5}) \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ - 5(1+e) \biggl[ 1 - ~\frac{1}{2} ~\cdot 2e( 1 - e +e^2 - e^3 ) ~ -~ \frac{1}{2^5} ~ \cdot 4e^2( 1 - 2e + 3e^2 ) ~-~\frac{1}{2^6} ~ \cdot 2^3e^3( 1 - 3e ) ~-~\frac{77}{2^{13}}~\cdot 2^4e^4 + \mathcal{O}(e^{5}) \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - 2^{-9}(1-e) \biggl[ 2^9 + 2^9e( 1 - e +e^2 - e^3 ) + 2^6 \cdot 11 ~\cdot e^2( 1 - 2e + 3e^2 ) + 2^6\cdot 17 ~ \cdot e^3( 1 - 3e ) + 1787 ~\cdot e^4 + \mathcal{O}(e^{5}) \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + 2^{-9} (6- 2e^2) \biggl[ 2^9 ~+~2^6~\cdot e^2( 1 - 2e + 3e^2 ) ~+~2^7 \cdot e^3( 1 - 3e ) ~+~ 231~\cdot e^4 + \mathcal{O}(e^{5}) \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ - 2^{-9}(5+ 5e) \biggl[ 2^9 - ~2^9 \cdot e( 1 - e +e^2 - e^3 ) ~ -~ 2^6 \cdot e^2( 1 - 2e + 3e^2 ) ~-~2^6 \cdot e^3( 1 - 3e ) ~-~77~\cdot e^4 + \mathcal{O}(e^{5}) \biggr] </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~\frac{2^{11}}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - 2^9 - 2^9e( 1 - e +e^2 - e^3 ) - 2^6 \cdot 11 ~\cdot e^2( 1 - 2e + 3e^2 ) - 2^6\cdot 17 ~ \cdot e^3( 1 - 3e ) - 1787 ~\cdot e^4 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + 2^9e + 2^9e^2( 1 - e +e^2 ) + 2^6 \cdot 11 ~\cdot e^3( 1 - 2e ) + 2^6\cdot 17 ~ \cdot e^4 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + 6\biggl[ 2^9 ~+~2^6~\cdot e^2( 1 - 2e + 3e^2 ) ~+~2^7 \cdot e^3( 1 - 3e ) ~+~ 231~\cdot e^4 \biggr] -2^{10}e^2 ~-~2^7~\cdot e^4 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + 5 \biggl[ -2^9 + ~2^9 \cdot e( 1 - e +e^2 - e^3 ) ~ +~ 2^6 \cdot e^2( 1 - 2e + 3e^2 ) ~+~2^6 \cdot e^3( 1 - 3e ) ~+~77~\cdot e^4 \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ +~5 \biggl[ -2^9e + ~2^9 \cdot e^2( 1 - e +e^2 ) ~ +~ 2^6 \cdot e^3( 1 - 2e ) ~+~2^6 \cdot e^4 \biggr] + \mathcal{O}(e^{5}) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ 2^9( e^2 - e^3 + e^4 ) - 2^6 \cdot 11 ~( e^2 - 2e^3 + 3e^4 ) - 2^6\cdot 17 ~( e^3 - 3e^4 ) - 1787 ~e^4 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ +2^9 ( e^2 - e^3 +e^4 ) + 2^6 \cdot 11 ( e^3 - 2e^4 ) + 2^6\cdot 17 ~ e^4 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ +~ 3\cdot 2^7~( e^2 - 2e^3 + 3e^4 ) ~+~3\cdot 2^8 ( e^3 - 3e^4 ) ~+~ 2\cdot 3^2 \cdot 7\cdot 11~\cdot e^4 -2^{10}e^2 ~-~2^7~\cdot e^4 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + 5\cdot 2^9 ( - e^2 +e^3 - e^4 ) ~ +~ 5\cdot 2^6 ( e^2 - 2e^3 + 3e^4 ) ~+~5\cdot 2^6 ( e^3 - 3e^4 ) ~+~5\cdot 77~e^4 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ +5\cdot 2^9 ( e^2 - e^3 +e^4 ) ~ +~ 5\cdot 2^6 ( e^3 - 2e^4 ) ~+~5\cdot 2^6 e^4 + \mathcal{O}(e^{5}) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ e^2 [ 2^9 - 2^6\cdot 11 + 2^9 + 3\cdot 2^7 -2^{10} -5\cdot 2^9 + 5\cdot 2^6 + 5\cdot 2^9 ] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + e^3 [ -2^9 - 2^7\cdot 11 - 2^6\cdot 17 - 2^9 +2^6\cdot 11 - 3\cdot 2^8+3\cdot 2^8 + 5\cdot 2^9-5\cdot 2^7 +5\cdot 2^6 -5\cdot 2^9 + 5\cdot 2^6] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + e^4 [ 2^9 - 3\cdot 11\cdot 2^6+3\cdot 17\cdot 2^6 - 1787 + 2^9 - 11\cdot 2^7 + 17\cdot 2^6 + 3^2\cdot 2^7 - 3^2\cdot 2^8+ 2\cdot 3^2\cdot 7\cdot 11 - 2^7 - 5\cdot 2^9 + 3\cdot 5\cdot 2^6 - 3\cdot 5\cdot 2^6 + 5\cdot 7\cdot 11 + 5\cdot 2^9 - 5\cdot 2^7 +5\cdot 2^6] + \mathcal{O}(e^{5}) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ e^2 [ - 2^6\cdot 11 + 3\cdot 2^7 + 5\cdot 2^6 ] + e^3 [ -2^{10} - 2^7\cdot 11 - 2^6\cdot 17 +2^6\cdot 11 ] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + e^4 [ 2^{10}~-~ 1787~+~ 2\cdot 3^2\cdot 7\cdot 11~+~ 5\cdot 7\cdot 11 ~+~ 2^6\cdot (3\cdot 17 - 3\cdot 11 - 22 + 17 + 18 - 36 - 2 - 10 + 5) ] + \mathcal{O}(e^{5}) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ 2^6 e^2 [ 0 ] ~- 2^8 \cdot 11 e^3 + e^4 [ 2^{10}~-~ 1787~+~ 7\cdot 11\cdot 23 ~-~ 2^8\cdot 3 ] + \mathcal{O}(e^{5}) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - 2^8 \cdot 11 e^3 + 2^4\cdot 3\cdot 5e^4 + \mathcal{O}(e^{5}) </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~\frac{2^{2}}{\pi^2} \biggl[ \frac{e^2}{(1 - e^2)^{1 / 2}} \biggr] \Upsilon_{W1}(\eta_0)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ - \frac{11}{2} e^3 + \frac{3\cdot 5}{2^5} e^4 + \mathcal{O}(e^{5}) \, . </math> </td> </tr> </table> <table border="1" cellpadding="8" align="center" width="90%"> <tr> <td align="center" bgcolor="black"><font color="white">'''Floating Comparison Summary'''</font></td> </tr> <tr><td align="left"> As [[#Step01|shown above]], the first three terms of the [https://ui.adsabs.harvard.edu/abs/2020MNRAS.494.5825H/abstract Huré, et al. (2020)] series expression may be written as, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~- \frac{\pi \Delta_0}{2} \biggl[ \frac{ \Psi_0 + \Psi_1 + \Psi_2 }{GM} \biggr] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \boldsymbol{K}([k_H]_0) - \frac{e^2}{2^4} \cdot \boldsymbol{K}(k_H) + \frac{e^2}{2^4} \biggl[ \frac{ \Delta_0^2 - 2R_c(R_c + R)}{(1 - k_H^2) \Delta_0^2} \biggr] \boldsymbol{E}(k_H) \, . </math> </td> </tr> </table> Let's see how it compares to the first term of Wong's (1973) expression which, as [[#Step02|shown separately above]], can be written in the form, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \Delta_0 \biggl( \frac{2^{2} }{3\pi^2} \biggr) \Upsilon_{W0}(\eta_0) \biggl\{ \frac{\boldsymbol{K}(k) }{ r_1 } \biggr\}\, . </math> </td> </tr> </table> ---- First, as [[#Step03|shown above]], <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\frac{2^2}{3\pi^2} \Upsilon_{W0}(\eta_0)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[1 + \biggl(\frac{5\cdot 13}{2^4\cdot 3} \biggr)e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2} \, . </math> </td> </tr> </table> Note that, in order to determine the functional form of the <math>~\mathcal{O}(e^{2})</math> term in this expression, we will have to include <math>~k_0^8</math> terms in the various expressions for products of elliptic integrals. Second, [[#Step04|we have shown that]], <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\frac{ r_1^2}{\Delta_0^2} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~1 -e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{\Delta_0^2}\biggr] - \frac{\varpi_W R_c}{\Delta_0^2} \biggl[\frac{1}{2^2} e^4 + \frac{1}{2^3}e^6 + \frac{5}{2^6} e^8 + \mathcal{O}(e^{10}) \biggr] </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~ \frac{\Delta_0}{r_1} </math> </td> <td align="center"> <math>~\approx</math> </td> <td align="left"> <math>~ 1 + e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{2\Delta_0^2}\biggr] \, ,</math> and we are defining <math>~\delta_K</math> such that, </td> </tr> <tr> <td align="right"> <math>~K(k)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~K(k_H) + \frac{\pi}{2} \cdot \delta_K \, .</math> </td> </tr> </table> ---- Hence, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~-\frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W0}}{GM} \biggr] </math> </td> <td align="center"> <math>~\approx</math> </td> <td align="left"> <math>~ \biggl\{ K(k_H) + \frac{\pi}{2} \cdot \delta_K\biggr\} \biggl\{ 1 + e^2 \biggl[ \frac{R_c(R_c + \varpi_W) }{2\Delta_0^2}\biggr] \biggr\}\biggl[1 + \biggl(\frac{5\cdot 13}{2^4\cdot 3} \biggr)e^2 + \mathcal{O}(e^{3}) \biggr]\cdot (1 - e^2)^{1 / 2} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~\approx</math> </td> <td align="left"> <math>~ \boldsymbol{K}([k_H]_0) + \boldsymbol{K}(k_H) e^2 \cdot \mathcal{A} +~\frac{\pi}{2} \biggl[ \frac{e^2 \cdot \varpi_W R_c}{ \Delta_0^4 } \biggr] \biggl\{ - R_c^2 - \cos\theta_H [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ +~(\varpi_W R_c + R_c^2 ) - \frac{1}{2}[ (\varpi_W^2 + R_c)^2 + z_W^2 ] - R_c^2 - 2R_c\cos\theta_H (R_c \cos\theta_H+ \varpi_W \cos\theta_H - z_W \sin\theta_H) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + \frac{ [2\varpi_W R_c \cos\theta_H + 2 R_c^2 \cos\theta_H - 2z_W R_c \sin\theta_H]^2 }{ \Delta_0^2} \biggr\} \, , </math> </td> </tr> </table> and, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\mathcal{A}</math> </td> <td align="center"> <math>~\approx</math> </td> <td align="left"> <math>~\biggl[ \frac{R_c(R_c + \varpi_W)}{2\Delta_0^2}\biggr] + \biggl( \frac{41}{2^4\cdot 3}\biggr) \, . </math> </td> </tr> </table> ---- Second, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~- \frac{\pi \Delta_0}{2} \biggl[ \frac{\Phi_\mathrm{W1}}{GM} \biggr] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \boldsymbol{E}(k) \biggl\{ \frac{\Delta_0 \cdot \cos\theta}{r_2} \biggr\} \biggl[ \biggl( \frac{2^{2} }{3\pi^2} \biggr) \Upsilon_{W1}(\eta_0) \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl\{ \boldsymbol{E}(k_H) + \frac{\pi}{2}\cdot \delta_E \biggr\} \biggl\{ \frac{\Delta_0 \cdot \cos\theta}{r_2} \biggr\} \biggl[- \biggl(\frac{11}{2\cdot 3} \biggr) e + \biggl(\frac{5}{2^5}\biggr) e^2 + \mathcal{O}(e^{5}) \biggr]\cdot (1 - e^2)^{1 / 2} \, . </math> </td> </tr> </table> </td></tr> </table>
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