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====Revise Overlap Discussion==== Let's reassess the conclusions drawn in our [[#Overlap_Between_Two_Off-Center_Circles|overlap discussion, above]]. Rather than varying <math>~r_0</math> while holding <math>~R_0</math> fixed, let's consider varying <math>~\xi_1</math> while fixing the coordinate location of the origin of the toroidal coordinate system, <math>~(a, Z_0)</math>. This is the approach that is appropriately aligned with integration over the (pink) toroidal mass distribution. Re-expressed, the pair of boundaries of the "region of overlap," <math>~r_\pm</math>, give: <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~(r_0 \pm r_t)^2 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~(\varpi_t - R_0)^2 + Z_0^2</math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~~ \biggl[ \frac{a}{(\xi_1^2 - 1)^{1/2}} \pm r_t \biggr]^2 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl[ \varpi_t - \frac{a\xi_1}{(\xi_1^2 - 1)^{1/2}} \biggr]^2 + Z_0^2</math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow ~~~~ \biggl[ a \pm r_t (\xi_1^2 - 1)^{1/2}\biggr]^2 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl[ \varpi_t (\xi_1^2 - 1)^{1/2} - a\xi_1 \biggr]^2 + Z_0^2 (\xi_1^2 - 1)</math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow~~~~ a^2 \pm 2a r_t (\xi_1^2 - 1)^{1/2} + r_t^2 (\xi_1^2 - 1)</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\varpi_t^2 (\xi_1^2 - 1) - 2a \varpi_t \xi_1 (\xi_1^2 - 1)^{1/2} + a^2\xi_1^2 + Z_0^2 (\xi_1^2 - 1)</math> </td> </tr> <tr> <td align="right"> <math> ~\Rightarrow~~~~(\xi_1^2 - 1)^{1/2}[2a \varpi_t \xi_1 \pm 2a r_t ] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~[\varpi_t^2 +a^2 + Z_0^2](\xi_1^2 - 1) </math> </td> </tr> <tr> <td align="right"> <math> ~\Rightarrow~~~~(\xi_1^2 - 1)^{1/2} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{2a(\varpi_t \xi_1 \pm r_t )}{(\varpi_t^2 +a^2 + Z_0^2)} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{1}{\ell} \biggl[ \xi_1 \pm \frac{r_t}{\varpi_t} \biggr] \, ,</math> </td> </tr> </table> </div> where, <div align="center"> <math>\ell \equiv \frac{1}{2}\biggl[ \frac{a^2 + \varpi_t^2 + Z_0^2}{a\varpi_t} \biggr] \, .</math> </div> After squaring both sides of this equation, we find that the values of <math>~\xi_1</math> corresponding to the limits of overlap can be obtained from the roots of the following quadratic equation: <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> ~\ell^2 (\xi_1^2 - 1) </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \xi_1 \pm \frac{r_t}{\varpi_t} \biggr]^2</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \xi_1^2 \pm \xi_1\biggl(\frac{2r_t}{\varpi_t}\biggr) + \biggl(\frac{r_t}{\varpi_t}\biggr)^2 \, ,</math> </td> </tr> </table> </div> that is, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~0 </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~(1-\ell^2) \xi_1^2 \pm \xi_1\biggl(\frac{2r_t}{\varpi_t}\biggr) + \biggl[ \biggl(\frac{r_t}{\varpi_t}\biggr)^2 +\ell^2\biggr] \, .</math> </td> </tr> </table> </div> <!-- COMMENT OUT determination of quadratic roots because result is likely irrelevant The roots are: <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\xi_1\biggr|_\pm</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{1}{2(1-\ell^2)} \biggl\{ \mp \biggl(\frac{2r_t}{\varpi_t}\biggr) \pm \sqrt{\biggl( \frac{2r_t}{\varpi_t}\biggr)^2 - 4(1-\ell^2) \biggl[ \biggl(\frac{r_t}{\varpi_t}\biggr)^2 +\ell^2\biggr]} \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{1}{(1-\ell^2)} \biggl(\frac{r_t}{\varpi_t}\biggr)\biggl\{ \mp 1 \pm \sqrt{1 - (1-\ell^2) \biggl[ 1 +\biggl(\frac{\ell \varpi_t}{r_t}\biggr)^2\biggr]} \biggr\} \, .</math> </td> </tr> </table> </div> --> After setting up this expression, it dawned on me that the "plus or minus" generalization is not appropriate in this situation. While either result — say, the "plus" result — can be shifted from a <math>~r_0 - R_0</math> specification to a <math>~a - \xi_1</math> specification, the pair of results generally will not share the same value of the scale length, <math>~a</math>. Hence the pair of solutions will be unrelated when viewed from the perspective of the toroidal coordinate system. Instead, let's determine the value of <math>~a</math> from the "first contact" solution — the ''superior'' sign in the expression — then figure out what the "final contact" solution will be if this scale length is held fixed. The solution to the quadratic equation is: <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\xi_1</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{1}{2(1-\ell^2)} \biggl\{ - \biggl(\frac{2r_t}{\varpi_t}\biggr) \pm \sqrt{\biggl(\frac{2r_t}{\varpi_t}\biggr)^2 -4(1-\ell^2) \biggl[ \biggl(\frac{r_t}{\varpi_t}\biggr)^2 +\ell^2\biggr]} \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{r_t}{\varpi_t(1-\ell^2)} \biggl\{ - 1 \pm \sqrt{1 -(1-\ell^2) \biggl[ 1 +\biggl(\frac{\ell \varpi_t}{r_t}\biggr)^2\biggr]} \biggr\} \, . </math> </td> </tr> </table> </div> Given that the allowed range of values for the "radial" toroidal coordinate is, <math>~1 \leq \xi_1 \leq \infty</math>, the relevant root is, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\xi_1\biggr|_\mathrm{first}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{r_t}{\varpi_t(1-\ell^2)} \biggl\{ \sqrt{1 -(1-\ell^2) \biggl[ 1 +\biggl(\frac{\ell \varpi_t}{r_t}\biggr)^2\biggr]} -1 \biggr\} \, . </math> </td> </tr> </table> </div>
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