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==Basics== Here we attempt to bring together — in as succinct a manner as possible — [[2DStructure/ToroidalCoordinates#Using_Toroidal_Coordinates_to_Determine_the_Gravitational_Potential|our approach]] and [http://adsabs.harvard.edu/abs/1973AnPhy..77..279W C.-Y. Wong's (1973)] approach to determining the gravitational potential of an axisymmetric, uniform-density torus that has a major radius, <math>~R</math>, and a minor, cross-sectional radius, <math>~d</math>. The relevant toroidal coordinate system is one based on an ''anchor ring'' of major radius, <div align="center"> <math>~a^2 \equiv R^2 - d^2 \, .</math> </div> If the meridional-plane location of the ''anchor ring'' — as written in cylindrical coordinates — is, <math>~(\varpi, z) = (a,Z_0)</math>, then the preferred toroidal-coordinate system has meridional-plane coordinates, <math>~(\eta, \theta)</math>, defined such that, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\eta</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\ln\biggl(\frac{r_1}{r_2} \biggr) \, ,</math> </td> <td align="center"> and, </td> <td align="right"> <math>~\cos\theta</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{(r_1^2 + r_2^2 - 4a^2)}{2r_1 r_2} \, ,</math> </td> </tr> </table> </div> where, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~r_1^2 </math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~(\varpi + a)^2 + (z-Z_0)^2 \, ,</math> </td> <td align="center"> and, </td> <td align="right"> <math>~r_2^2 </math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~(\varpi - a)^2 + (z-Z_0)^2 \, ,</math> </td> </tr> </table> </div> and <math>~\theta</math> has the same sign as <math>~(z-Z_0)</math>. Mapping the other direction, we have, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\varpi</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{a \sinh\eta }{(\cosh\eta - \cos\theta)} \, ,</math> </td> <td align="center"> and, </td> <td align="right"> <math>~z-Z_0</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{a \sin\theta}{(\cosh\eta - \cos\theta)} \, .</math> </td> </tr> </table> </div> <span id="DiffVolElement">The three-dimensional differential volume element is,</span> <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~d^3 r</math> </td> <td align="center"> <math>~=</math> </td> <td align="center"> <math>\varpi d\varpi ~dz ~d\psi</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl[ \frac{a^3\sinh\eta}{(\cosh\eta - \cos\theta)^3} \biggr] d\eta~ d\theta~ d\psi \, .</math> </td> </tr> </table> </div> Note that, if <math>~\eta_0</math> identifies the surface of the uniform-density torus, then, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\cosh\eta_0</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{R}{d} \, ,</math> </td> <td align="center"> </td> <td align="right"> <math>~\sinh\eta_0</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{a}{d} \, ,</math> </td> <td align="center"> and, </td> <td align="right"> <math>~\coth\eta_0</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{R}{a} \, ;</math> </td> </tr> </table> </div> and when the integral over the volume element is completed — that is, over all <math>~\psi</math>, over all <math>~\theta</math>, and over the "radial" interval, <math>~\eta_0 \le \eta \le \infty</math> — the resulting volume is, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~V</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{2\pi^2 \cosh\eta_0}{\sinh^3\eta_0}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~2\pi^2 Rd^2 \, .</math> </td> </tr> </table> </div> Also, given that, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\cosh\eta</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{1}{2}\biggl[ e^\eta + e^{-\eta} \biggr]</math> </td> <td align="center"> and, </td> <td align="right"> <math>~\sinh\eta</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{1}{2}\biggl[ e^\eta - e^{-\eta} \biggr] \, ,</math> </td> </tr> </table> </div> we have, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\coth\eta</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl[ e^\eta + e^{-\eta} \biggr]\biggl[ e^\eta - e^{-\eta} \biggr]^{-1}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl[ \frac{r_1}{r_2} + \frac{r_2}{r_1} \biggr]\biggl[ \frac{r_1}{r_2} - \frac{r_2}{r_1} \biggr]^{-1}</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left" colspan="1"> <math>~\biggl[ \frac{r_1^2 + r_2^2}{r_1 r_2} \biggr]\biggl[ \frac{r_1^2 - r_2^2}{r_1 r_2} \biggr]^{-1}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left" colspan="1"> <math>~\biggl[ \frac{r_1^2 + r_2^2}{r_1^2 - r_2^2} \biggr]</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left" colspan="3"> <math>~ \frac{ \varpi^2 + a^2 + (z - Z_0)^2 }{ 2a\varpi } \, . </math> </td> </tr> </table> </div>
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