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====Basic Properties==== For bipolytropes, in general, let <math>~n =n_c</math> and <math>~j = n_e</math>. The statement of virial equilibrium is, then, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\frac{ b}{n_c c}\cdot x^{(n_c-3)/n_c }_\mathrm{eq} - \frac{a}{3c} + \frac{1}{n_e}\cdot x^{(n_e-3)/n_e}_\mathrm{eq} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ 0 \, .</math> </td> </tr> </table> </div> And the critical equilibrium configuration has, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~[x_\mathrm{eq}^{(n_e-3)/n_e}]_\mathrm{crit} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{a}{3^2c}\biggl[ \frac{n_e^2(n_c-3)}{n_c-n_e} \biggr] \, . </math> </td> </tr> </table> </div> Here we choose to set <math>~n_c = 5</math> and <math>~n_e = 1</math>. Hence, these two conditions become, respectively, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\frac{ b}{5 c}\cdot x^{2/5 }_\mathrm{eq} + x^{-2}_\mathrm{eq} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{a}{3c} \, ,</math> </td> </tr> </table> </div> and, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~[x_\mathrm{eq}]_\mathrm{crit} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \frac{2\cdot 3^2c}{a} \biggr]^{1/2} \, . </math> </td> </tr> </table> </div> <!-- EQUATIONS USEFUL in POWERPOINT PRESENTATION <div align="center"> <math>~\theta_5(\xi) ~~~~\theta_1(\eta)</math> <math>~\mu_e/\mu_c</math> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\ell_i</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~\frac{\xi_i}{\sqrt{3}}</math> </td> </tr> </table> </div> --> Comparing the general free-energy expression at the beginning of this chapter with the free-energy expression provided via our [[SSC/FreeEnergy/PolytropesEmbedded#BiPolytropeFreeEnergy|accompanying summary discussion of five-one bipolytropes]], we find that, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~a</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~(3\mathfrak{L}_i +12\mathfrak{K}_i) x_\mathrm{eq} \biggl[ \biggl( \frac{3^6}{2^5\pi} \biggr)^{1/2} \frac{\ell_i^3}{(1+\ell_i^2)^3} \biggr] </math> </td> </tr> <tr> <td align="right"> <math>~b</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~(5 \mathfrak{L}_i) x_\mathrm{eq}^{3/5} \biggl[ \biggl( \frac{3^6}{2^5\pi} \biggr)^{1/2} \frac{\ell_i^3}{(1+\ell_i^2)^3} \biggr] </math> </td> </tr> <tr> <td align="right"> <math>~c</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~(4\mathfrak{K}_i) x_\mathrm{eq}^{3} \biggl[ \biggl( \frac{3^6}{2^5\pi} \biggr)^{1/2} \frac{\ell_i^3}{(1+\ell_i^2)^3} \biggr] </math> </td> </tr> </table> </div> where, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\mathfrak{L}_i</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~\frac{(\ell_i^4-1)}{\ell_i^2} + \frac{(1+\ell_i^2)^3}{\ell_i^3} \cdot \tan^{-1}\ell_i \, ,</math> </td> </tr> <tr> <td align="right"> <math>~\mathfrak{K}_i</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~\frac{\Lambda_i}{\eta_i} + \frac{(1+\Lambda_i^2)}{\eta_i} \biggl[\frac{\pi}{2} + \tan^{-1}\Lambda_i\biggr] \, ,</math> </td> </tr> <tr> <td align="right"> <math>~\Lambda_i</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~\frac{1}{\eta_i} - \ell_i \, ,</math> </td> </tr> <tr> <td align="right"> <math>~\eta_i</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~3 \biggl( \frac{\mu_e}{\mu_c} \biggr) \biggl[\frac{\ell_i }{(1+\ell_i^2)}\biggr] \, ,</math> </td> </tr> </table> </div> and, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~x_\mathrm{eq} = \frac{R_\mathrm{eq}}{R_\mathrm{norm}}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl(\frac{\pi}{2^3}\biggr)^{1/2} \frac{\nu^2}{q} \cdot \frac{(1+\ell_i^2)^3}{3^3\ell_i^5} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl(\frac{\pi}{2^3}\biggr)^{1/2} \frac{(1+\ell_i^2)^3}{3^3\ell_i^3} \biggl[ \frac{1 }{(1+\Lambda_i^2)} \biggr] \biggl\{ 1 + \frac{1}{\eta_i}\biggl[\frac{\pi}{2} + \tan^{-1}\Lambda_i \biggr] \biggr\}^{-1}</math> </td> </tr> </table> </div> <!-- MORE EXPRESSIONS FOR POWERPOINT PRESENTATION <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~x_\mathrm{eq}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl(\frac{\pi}{2^3}\biggr)^{1/2} \frac{(1+\ell_i^2)^3}{3^3\ell_i^3} \biggl[ \frac{1 }{(1+\Lambda_i^2)} \biggr] \biggl\{ 1 + \frac{1}{\eta_i}\biggl[\frac{\pi}{2} + \tan^{-1}\Lambda_i \biggr] \biggr\}^{-1}</math> </td> </tr> <tr> <td align="right"> <math>~\Lambda_i</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~\frac{1}{\eta_i} - \ell_i </math> </td> </tr> <tr> <td align="right"> <math>~\eta_i</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~3 \biggl( \frac{\mu_e}{\mu_c} \biggr) \biggl[\frac{\ell_i }{(1+\ell_i^2)}\biggr] </math> </td> </tr> <tr> <td align="right"> <math>~R_0 = R_\mathrm{norm}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl( \frac{G}{K_c} \biggr)^{5/2} M_\mathrm{tot}^2 </math> </td> </tr> </table> </div> --> In rewriting this last expression, we have made use of the two relations, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~q \equiv \frac{r_i}{R}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl\{ 1 + \frac{1}{\eta_i}\biggl[\frac{\pi}{2} + \tan^{-1}\Lambda_i \biggr] \biggr\}^{-1} \, ,</math> </td> </tr> <tr> <td align="right"> <math>~\nu \equiv \frac{M_\mathrm{core}}{M_\mathrm{tot}}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{\ell_i q}{(1+\Lambda_i^2)^{1/2}} \, . </math> </td> </tr> </table> </div> Consistent with our [[SSC/BipolytropeGeneralization#Free_Energy_and_Its_Derivatives|generic discussion of the stability of bipolytropes]] and the ''specific'' discussion of [[SSC/Structure/BiPolytropes/Analytic51#Stability_Condition|the stability of bipolytropes having]] <math>~(n_c, n_e) = (5, 1)</math>, it can straightforwardly be shown that <math>~\partial \mathfrak{G}/\partial \chi = 0</math> is satisfied by setting <math>~\Chi = 1</math>; that is, the equilibrium condition is, Furthermore, the equilibrium configuration is unstable whenever <math>~\partial^2 \mathfrak{G}/\partial \chi^2 < 0</math>, that is, the transition from stable to unstable configurations whenever, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\frac{ \mathfrak{L}_i}{\mathfrak{K}_i}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~20 \, .</math> </td> </tr> </table> </div> [[SSC/Structure/BiPolytropes/Analytic51#Stability_Condition|Table 1 of an accompanying chapter]] — and the red-dashed curve in the figure adjacent to that table — identifies some key properties of the model that marks the transition from stable to unstable configurations along equilibrium sequences that have various values of the mean-molecular weight ratio, <math>~\mu_e/\mu_c</math>.
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