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==Set of Linearized Equations== Borrowing from [[SSC/Perturbations#Summary_Set_of_Linearized_Equations|an accompanying discussion]], we have … <div align="center"> <table border="1" cellpadding="10"> <tr><td align="center"> <font color="#770000">'''Linearized'''</font><br /> <span id="Continuity"><font color="#770000">'''Equation of Continuity'''</font></span><br /> <math> r_0 \frac{dx}{dr_0} = - 3 x - d , </math><br /> <font color="#770000">'''Linearized'''</font><br /> <span id="PGE:Euler"><font color="#770000">'''Euler + Poisson Equations'''</font></span><br /> <math> \frac{P_0}{\rho_0} \frac{dp}{dr_0} = (4x + p)g_0 + \omega^2 r_0 x , </math><br /> <font color="#770000">'''Linearized'''</font><br /> <span id="PGE:AdiabaticFirstLaw">Adiabatic Form of the<br /> <font color="#770000">'''First Law of Thermodynamics'''</font></span><br /> <math> p = \gamma_\mathrm{g} d \, . </math> </td></tr> </table> </div> Rearranging terms in the "Linearized Euler + Poisson Equations" as follows … <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\frac{1}{\rho_0} \cdot \frac{dp}{dr_0}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{1}{P_0}\biggl[ (4x + p)g_0 + \omega^2 r_0 x \biggr] </math> </td> </tr> </table> we realize that the expression on the RHS has the same value at the interface, whether you're viewing the equation from the point of view of the core or the envelope; and we recognize as well that <math>\rho_0</math> is a simple step function at the interface. Hence, letting a prime indicate differentiation with respect to <math>r_0</math>, we can write, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> H(\zeta)\cdot (p')_\mathrm{env} + H(-\zeta)\cdot (p')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{[\rho_0]_\mathrm{core}}{P_0}\biggl[ (4x + p)g_0 + \omega^2 r_0 x \biggr] \biggl\{ H(\zeta)\cdot \biggl[ \frac{\mu_e}{\mu_c} \biggr] + H(-\zeta) \biggr\} \, . </math> </td> </tr> </table> Analogously, the "Linearized Equation of Continuity" can be rewritten as, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> H(\zeta)\cdot (x')_\mathrm{env} + H(-\zeta)\cdot (x')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \frac{3x}{r_0} - \frac{1}{r_0}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} \, . </math> </td> </tr> </table> Now, given that <math>\zeta = (r_0/r_i - 1)</math>, we see that, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> \frac{dH(\zeta)}{dr_0} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{\partial H(\zeta)}{\partial \zeta} \cdot \frac{d\zeta}{dr_0} = r_o^{-1} \delta(\zeta) \, ; </math> </td> </tr> </table> and, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> \frac{dH(-\zeta)}{dr_0} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> -\frac{\partial H(\zeta)}{\partial \zeta} \cdot \frac{d\zeta}{dr_0} = -r_o^{-1} \delta(\zeta) \, . </math> </td> </tr> </table> Hence, differentiation of the "Linearized Equation of Continuity" gives, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> \frac{d}{dr_0}\biggl[H(\zeta)\cdot (x')_\mathrm{env}\biggr] + \frac{d}{dr_0}\biggl[H(-\zeta)\cdot (x')_\mathrm{core}\biggr] </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] - \frac{1}{r_0} \frac{d}{dr_0}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} + \frac{1}{r_0^2}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ (x')_\mathrm{env}\frac{d}{dr_0}\biggl[H(\zeta)\biggr] + H(\zeta)\cdot (x'')_\mathrm{env} + (x')_\mathrm{core}\frac{d}{dr_0}\biggl[H(-\zeta)\biggr] + H(-\zeta)\cdot (x'')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] + \frac{1}{r_0^2}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env}\frac{d}{dr_0}\biggl\{H(\zeta) \biggr\} - \frac{1}{r_0} \biggl\{ H(\zeta)\cdot \biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{env} \biggr\} - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \frac{d}{dr_0}\biggl\{H(-\zeta) \biggr\} - \frac{1}{r_0} \biggl\{H(-\zeta)\biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{core} \biggr\} </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ (x')_\mathrm{env} \biggl[\frac{\delta(\zeta)}{r_0}\biggr] + H(\zeta)\cdot (x'')_\mathrm{env} - (x')_\mathrm{core}\biggl[\frac{\delta(\zeta)}{r_0}\biggr] + H(-\zeta)\cdot (x'')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] + \frac{1}{r_0^2}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} - \frac{1}{r_0} \biggl\{ H(\zeta)\cdot \biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{env} \biggr\} + \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} - \frac{1}{r_0} \biggl\{H(-\zeta)\biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{core} \biggr\} </math> </td> </tr> </table> ===From the Perspective of the Core=== When <math>r_0/r_i \le 1</math> — that is, from the perspective of the core while including the interface, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> - (x')_\mathrm{core}\biggl[\frac{\delta(\zeta)}{r_0}\biggr] + H(-\zeta)\cdot (x'')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] + \frac{1}{r_0^2}\biggl\{ H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} + \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} - \frac{1}{r_0} \biggl\{H(-\zeta)\biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{core} \biggr\} </math> </td> </tr> </table> And examining only the interface, where <math>\delta(\zeta) = 1</math> while <math>H(-\zeta) = 0</math>, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> - (x')_\mathrm{core}\biggl[\frac{\delta(\zeta)}{r_0}\biggr] </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} + \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} </math> </td> </tr> <tr> <td align="right"> <math> \Rightarrow ~~~ - (x')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ 3x' - \frac{3x}{r_0}\biggr] - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} </math> </td> </tr> </table> ===From the Perspective of the Envelope=== When <math>r_0/r_i \ge 1</math> — that is, from the perspective of the envelope while including the interface, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> (x')_\mathrm{env} \biggl[\frac{\delta(\zeta)}{r_0}\biggr] + H(\zeta)\cdot (x'')_\mathrm{env} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] + \frac{1}{r_0^2}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} - \frac{1}{r_0} \biggl\{ H(\zeta)\cdot \biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{env} \biggr\} + \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} </math> </td> </tr> </table>
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