Editing
Appendix/Mathematics/EulerAngles
(section)
Jump to navigation
Jump to search
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=Riemann Type I Ellipsoids= ==Tipped Coordinate System== In an accompanying discussion of Riemann Type I ellipsoids, we have presented a [[ThreeDimensionalConfigurations/RiemannTypeI#Try_Again|methodical derivation of orbital parameters]] in a "tipped" reference frame. In the context of our present discussion of Euler angles, it seems clear that this separate coordinate-frame transformation involved only one nonzero Euler angle; specifically, <math>(\phi, \theta, \psi) = (0, \theta, 0)</math>. In terms of Euler angles, then, the transformation between the ellipsoid's unprimed frame and the primed "tipped" frame is given by the [[#FormMatrix|above expressions]] … <table border="0" align="center" cellpadding="8"> <tr> <td align="right"> <math>\begin{bmatrix}x' \\ y' \\ z' \end{bmatrix}_\mathrm{tipped}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> \hat{R} \cdot \begin{bmatrix}x \\ y \\ (z - z_0) \end{bmatrix} \, , </math> </td> </tr> </table> and, <table border="0" align="center" cellpadding="8"> <tr> <td align="right"> <math>\begin{bmatrix}x \\ y \\ (z - z_0) \end{bmatrix}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math> \hat{R}^{-1} \cdot \begin{bmatrix}x' \\ y' \\ z' \end{bmatrix}_\mathrm{tipped} \, , </math> </td> </tr> </table> where, <table border="0" align="center" cellpadding="3"> <tr> <td align="right"> <math>\hat{R}(\phi, \theta, \psi) = \hat{R}_3(\psi) \cdot \hat{R}_1(\theta) \cdot \hat{R}_3(\phi)</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> {\begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}} \cdot {\begin{bmatrix} 1 & 0 & 0 \\ 0 & \cos\theta & \sin\theta \\ 0 & -\sin\theta & \cos\theta \end{bmatrix}} \cdot {\begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> {\begin{bmatrix} 1 & 0 & 0 \\ 0 & \cos\theta & \sin\theta \\ 0 & -\sin\theta & \cos\theta \end{bmatrix}} \, , </math> </td> </tr> </table> and, <table border="0" align="center" cellpadding="3"> <tr> <td align="right"> <math>\hat{R}^{-1}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> {\begin{bmatrix} 1 & 0 & 0 \\ 0 & \cos\theta & -\sin\theta \\ 0 & \sin\theta & \cos\theta \end{bmatrix}} \, . </math> </td> </tr> </table> That is to say, <table border="1" align="center" cellpadding="8"><tr> <td align="center"> <table border="0" align="center" cellpadding="8"> <tr> <td align="right"><math>x'</math></td> <td align="center"><math>=</math></td> <td align="left"><math>x</math></td> </tr> <tr> <td align="right"><math>y'</math></td> <td align="center"><math>=</math></td> <td align="left"><math>y \cos\theta + (z - z_0)\sin\theta</math></td> </tr> <tr> <td align="right"><math>z'</math></td> <td align="center"><math>=</math></td> <td align="left"><math>- y \sin\theta + (z - z_0)\cos\theta</math></td> </tr> </table> </td> <td align="center"> <table border="0" align="center" cellpadding="8"> <tr> <td align="right"><math>x</math></td> <td align="center"><math>=</math></td> <td align="left"><math>x'</math></td> </tr> <tr> <td align="right"><math>y</math></td> <td align="center"><math>=</math></td> <td align="left"><math>y' \cos\theta - z'\sin\theta</math></td> </tr> <tr> <td align="right"><math>(z - z_0)</math></td> <td align="center"><math>=</math></td> <td align="left"><math>y' \sin\theta + z'\cos\theta</math></td> </tr> </table> </td> </tr> </table> which is identical to the coordinate transformations presented in the [[#Try_Again|top two panels of the table in our accompanying ''methodical derivation of orbital parameters]]. Similarly, the three components of the velocity field as viewed from the "tipped" plane can be obtained from the velocity components in the untipped plane <math>(u_1, u_2, u_3)</math> via the expressions, <table border="1" align="center" cellpadding="8"><tr> <td align="center"> <table border="0" align="center" cellpadding="8"> <tr> <td align="right"><math>u_1^'</math></td> <td align="center"><math>=</math></td> <td align="left"><math>u_1</math></td> </tr> <tr> <td align="right"><math>u_2^'</math></td> <td align="center"><math>=</math></td> <td align="left"><math>u_2 \cos\theta + u_3\sin\theta</math></td> </tr> <tr> <td align="right"><math>u_3^'</math></td> <td align="center"><math>=</math></td> <td align="left"><math>- u_2 \sin\theta + u_3\cos\theta</math></td> </tr> </table> </td> </tr> </table> ==Velocity in Tipped Plane== Now, according to EFE — see eq. 154 of Chapter 7, §51 (p. 156) — <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~u_1</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 y + \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 z</math> </td> </tr> <tr> <td align="right"> <math>~u_2</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~+\biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 x</math> </td> </tr> <tr> <td align="right"> <math>~u_3</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 x</math> </td> </tr> </table> Hence, in the "tipped" plane we find, <table border="0" align="center" cellpadding="8"> <tr> <td align="right"><math>u_1^'</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 z - \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 y </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \biggl[z_0 + y'\sin\theta + z'\cos\theta\biggr] + \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \biggl[ z' \sin\theta - y'\cos\theta \biggr] \, , </math> </td> </tr> <tr> <td align="right"><math>u_2^'</math></td> <td align="center"><math>=</math></td> <td align="left"><math>\cos\theta\biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 x - \sin\theta\biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 x</math></td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math>\biggl\{\cos\theta\biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 - \sin\theta\biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggr\}x' \, , </math> </td> </tr> <tr> <td align="right"><math>u_3^'</math></td> <td align="center"><math>=</math></td> <td align="left"><math>- \sin\theta\biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 x - \cos\theta\biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 x</math></td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"><math> \biggl\{ - \sin\theta\biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 - \cos\theta\biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggr\} x' \, . </math> </td> </tr> </table> Ideally, we would like to choose the orientation of our "tipped" plane such that there are no vertical motions as viewed from that plane, that is, such that <math>u_3^' = 0</math>. This means that, <table border="0" align="center" cellpadding="8"> <tr> <td align="right"><math>\sin\theta\biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> - \cos\theta\biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 </math> </td> </tr> <tr> <td align="right"><math>\Rightarrow ~~~ \tan\theta</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> - \frac{\zeta_2}{\zeta_3}\biggl[ \frac{a^2 + b^2}{a^2 + c^2} \biggr]\frac{c^2}{b^2} \, . </math> </td> </tr> </table> Given, as well, that we are only analyzing motion in the <math>z' = 0</math> plane, we have for the other two velocity components, <table border="0" align="center" cellpadding="8"> <tr> <td align="right"><math>u_2^'</math></td> <td align="center"><math>=</math></td> <td align="left"> <math>\cos\theta \biggl\{\biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 - \tan\theta\biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggr\}x' </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math>\cos\theta \biggl\{\biggl[ \frac{b^2}{a^2 + b^2} \biggr] \zeta_3 + \frac{\zeta_2}{\zeta_3}\biggl[ \frac{a^2 + b^2}{a^2 + c^2} \biggr]\frac{c^2}{b^2} \biggl[ \frac{c^2}{a^2 + c^2} \biggr] \zeta_2 \biggr\}x' </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math>\biggl[ \frac{b^2}{a^2 + b^2} \biggr]\zeta_3 \cos\theta \biggl\{1 + \frac{\zeta_2^2}{\zeta_3^2}\biggl[ \frac{a^2 + b^2}{a^2 + c^2} \biggr]^2\frac{c^4}{b^4} \biggr\}x' </math> </td> </tr> <tr> <td align="right"><math>u_1^'</math></td> <td align="center"><math>=</math></td> <td align="left"> <math>\cos\theta \biggl\{ \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \zeta_2 \biggl[\frac{z_0}{\cos\theta} + y'\tan\theta + \cancelto{0}{z'}\biggr] + \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \zeta_3 \biggl[ \cancelto{0}{z'} \tan\theta - y'\biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ \frac{a^2}{a^2 + c^2} \biggr] z_0 \zeta_2 - \zeta_3 \cos\theta \biggl\{ \biggl[ \frac{a^2}{a^2 + c^2} \biggr] \frac{\zeta_2^2}{\zeta_3^2}\biggl[ \frac{a^2 + b^2}{a^2 + c^2} \biggr]\frac{c^2}{b^2} + \biggl[ \frac{a^2}{a^2 + b^2} \biggr] \biggr\}y' </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ \frac{a^2}{a^2 + c^2} \biggr] z_0 \zeta_2 - \biggl[ \frac{a^2}{a^2 + b^2} \biggr]\zeta_3 \cos\theta \biggl\{ \frac{\zeta_2^2}{\zeta_3^2}\biggl[ \frac{a^2 + b^2}{a^2 + c^2} \biggr]^2\frac{c^2}{b^2} + 1 \biggr\}y' \, . </math> </td> </tr> </table> ==Rewrite Velocity-Component Expressions== After defining the term, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\Lambda^2</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left"> <math>\frac{\zeta_2^2}{\zeta_3^2}\biggl[ \frac{a^2 + b^2}{a^2 + c^2} \biggr]^2\frac{c^2}{b^2} \, ,</math> </td> </tr> </table> the expressions for the two "tipped" velocity components may be rewritten as, <table border="0" align="center" cellpadding="8"> <tr> <td align="right"><math>\biggl[ \frac{a^2 + b^2}{\zeta_3 \cos\theta}\biggr] u_2^'</math></td> <td align="center"><math>=</math></td> <td align="left"> <math>\biggl\{b^2 + \Lambda^2 \cdot c^2 \biggr\}x' \, , </math> </td> </tr> <tr> <td align="right"><math>\biggl[ \frac{a^2 + b^2}{\zeta_3 \cos\theta}\biggr] u_1^'</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ \frac{a^2 + b^2}{\zeta_3 \cos\theta}\biggr] \biggl[ \frac{a^2}{a^2 + c^2} \biggr] z_0 \zeta_2 - \biggl\{ a^2 + \Lambda^2 \cdot a^2 \biggr\}y' \, . </math> </td> </tr> </table> Or, <table border="0" align="center" cellpadding="8"> <tr> <td align="right"><math>\biggl\{\frac{1+\Lambda^2}{b^2 + \Lambda^2 \cdot c^2 }\biggr\}\biggl[ \frac{a^2 + b^2}{\zeta_3 \cos\theta}\biggr] u_2^'</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> ( 1 + \Lambda^2 )x' \, , </math> </td> </tr> <tr> <td align="right"><math>\biggl[ \frac{a^2 + b^2}{a^2 \zeta_3 \cos\theta}\biggr] u_1^'</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ \frac{a^2 + b^2}{\zeta_3 \cos\theta}\biggr] \biggl[ \frac{z_0 \zeta_2}{a^2 + c^2} \biggr] - ( 1 + \Lambda^2 )y' </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> ( 1 + \Lambda^2 )(y_0 - y') \, , </math> </td> </tr> </table> where, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>y_0</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left"> <math> \frac{1}{1+\Lambda^2}\biggl[ \frac{a^2 + b^2}{\zeta_3 \cos\theta}\biggr] \biggl[ \frac{z_0 \zeta_2}{a^2 + c^2} \biggr] \, . </math> </td> </tr> </table> ==Lagrangian Particle Motion== Now, if we assume that each Lagrangian particle executes a closed elliptical orbit ''in the plane'' of the tipped coordinate system (''i.e.,'' <math>~z' = \dot{z}' = 0</math> ), but whose orbit-center may be shifted by an amount, <math>~y_0</math>, away from the z'-axis, we expect … <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~x'</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~x_\mathrm{max}\cos(\varphi t)</math> </td> <td align="center"> and, <td align="right"> <math>~y' - y_0</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~y_\mathrm{max}\sin(\varphi t) \, ,</math> </td> </tr> </table> which implies, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\dot{x}'</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~- x_\mathrm{max}~ \varphi \cdot \sin(\varphi t)</math> </td> <td align="center"> and, <td align="right"> <math>~\dot{y}' </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~y_\mathrm{max}~\varphi \cdot \cos(\varphi t) \, .</math> </td> </tr> </table> That is to say, we expect that the two velocity components will exhibit the form, respectively, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>u_1^'</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[\frac{x_\mathrm{max}}{y_\mathrm{max}} \biggr] \varphi \cdot (y_0 - y') \, , </math> </td> <td align="center"> and, </td> <td align="right"> <math>u_2^'</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[\frac{y_\mathrm{max}}{x_\mathrm{max}} \biggr] \varphi \cdot x' \, . </math> </td> </tr> </table> This pair of expressions will only match the underlying Riemann Type I flow if, <table border="0" align="center" cellpadding="8"> <tr> <td align="right"> <math>\biggl\{\frac{1+\Lambda^2}{b^2 + \Lambda^2 \cdot c^2 }\biggr\}\biggl[ \frac{a^2 + b^2}{\zeta_3 \cos\theta}\biggr] </math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{x_\mathrm{max}}{y_\mathrm{max}} \, , </math> and, </td> </tr> <tr> <td align="right"><math>\biggl[ \frac{a^2 + b^2}{a^2 \zeta_3 \cos\theta}\biggr] </math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \frac{y_\mathrm{max}}{x_\mathrm{max}} \, . </math> </td> </tr> </table> That is, <table border="0" align="center" cellpadding="8"> <tr> <td align="right"> <math>\biggl\{\frac{1+\Lambda^2}{b^2 + \Lambda^2 \cdot c^2 }\biggr\}\biggl[ \frac{a^2 + b^2}{\zeta_3 \cos\theta}\biggr] </math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl[ \frac{a^2 \zeta_3 \cos\theta}{a^2 + b^2}\biggr] </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ \frac{1}{a^2}\biggl\{\frac{1+\Lambda^2}{b^2 + \Lambda^2 \cdot c^2 }\biggr\}\biggl[ \frac{a^2 + b^2}{\zeta_3 \cos\theta}\biggr]^2 </math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> 1 \, . </math> </td> </tr> </table> Let's try the numerical values from the [[ThreeDimensionalConfigurations/RiemannTypeI#Example_b1.25c0.470|example Type I ellipsoid used in an accompanying discussion]], namely, <math>b/a = 1.25, c/a = 0.4703, \zeta_2 = -2.2794, \zeta_3 = -1.9637</math>. Hence, <table border="0" align="center" cellpadding="8"> <tr> <td align="right"><math>\tan\theta</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> - \frac{\zeta_2}{\zeta_3}\biggl[ \frac{a^2 + b^2}{a^2 + c^2} \biggr]\frac{c^2}{b^2} = - 0.3448 ~~~ \Rightarrow ~~~ \theta = -0.3320 \, , </math> </td> </tr> <tr> <td align="right"><math>\Rightarrow ~~~ \cos\theta</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> - 0.9454 \, . </math> </td> </tr> </table> And, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\Lambda^2</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left"> <math>\frac{\zeta_2^2}{\zeta_3^2}\biggl[ \frac{a^2 + b^2}{a^2 + c^2} \biggr]^2\frac{c^2}{b^2} = \tan^2\theta \cdot \frac{b^2}{c^2} = 0.8399 \, .</math> </td> </tr> </table> Hence, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\Rightarrow ~~~ \frac{1}{a^2}\biggl\{\frac{1+\Lambda^2}{b^2 + \Lambda^2 \cdot c^2 }\biggr\}\biggl[ \frac{a^2 + b^2}{\zeta_3 \cos\theta}\biggr]^2 </math> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl\{ 1.0524 \biggr\} \biggl[ 1.3803 \biggr]^2 = 2.005 \, . </math> </td> </tr> </table>
Summary:
Please note that all contributions to JETohlineWiki may be edited, altered, or removed by other contributors. If you do not want your writing to be edited mercilessly, then do not submit it here.
You are also promising us that you wrote this yourself, or copied it from a public domain or similar free resource (see
JETohlineWiki:Copyrights
for details).
Do not submit copyrighted work without permission!
Cancel
Editing help
(opens in new window)
Navigation menu
Personal tools
Not logged in
Talk
Contributions
Log in
Namespaces
Page
Discussion
English
Views
Read
Edit
View history
More
Search
Navigation
Main page
Tiled Menu
Table of Contents
Old (VisTrails) Cover
Appendices
Variables & Parameters
Key Equations
Special Functions
Permissions
Formats
References
lsuPhys
Ramblings
Uploaded Images
Originals
Recent changes
Random page
Help about MediaWiki
Tools
What links here
Related changes
Special pages
Page information