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===Second Derivative of Free Energy=== The relative stability of an equilibrium configuration can be determined by the sign of the second derivative of the free energy evaluated at the equilibrium radius; if the second derivative is negative, the system is dynamically unstable. The second derivative of the free energy is, <div align="center"> <table border="0"> <tr> <td align="right"> <math>\frac{d^2\mathfrak{G}}{dR^2} \biggr|_{R_\mathrm{eq}}</math> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math>\biggl[ -2A_\mathrm{grav}R^{-3} - 2(2-3\gamma_c)C_\mathrm{core} R^{1-3\gamma_c} - 2(2-3\gamma_e)C_\mathrm{env} R^{1-3\gamma_e} \biggr]_\mathrm{eq} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math>2R^{-2}_\mathrm{eq} \biggl[ W - (2-3\gamma_c)C_\mathrm{core} R^{3-3\gamma_c} - (2-3\gamma_e)C_\mathrm{env} R^{3-3\gamma_e} \biggr]_\mathrm{eq} \, .</math> </td> </tr> </table> </div> From the equilibrium condition derived above, we know that, <div align="center"> <table border="0"> <tr> <td align="right"> <math>- C_\mathrm{env} R^{3-3\gamma_e}</math> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math>C_\mathrm{core} R^{3-3\gamma_c} + \frac{W}{2} \, .</math> </td> </tr> </table> </div> Hence, <div align="center"> <table border="0"> <tr> <td align="right"> <math>\frac{1}{2} R^{2}_\mathrm{eq} \frac{d^2\mathfrak{G}}{dR^2} \biggr|_{R_\mathrm{eq}}</math> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math>W_\mathrm{eq} - (2-3\gamma_c)C_\mathrm{core} R_\mathrm{eq}^{3-3\gamma_c} + (2-3\gamma_e) \biggl[ C_\mathrm{core} R^{3-3\gamma_c} + \frac{W}{2}\biggr]_\mathrm{eq} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math>\biggl( 2 - \frac{3}{2}\gamma_e \biggr) W_\mathrm{eq} + 3 (\gamma_c - \gamma_e)C_\mathrm{core} R_\mathrm{eq}^{3-3\gamma_c} \, .</math> </td> </tr> </table> </div> But, from our above discussion, we can also write, <div align="center"> <table border="0"> <tr> <td align="right"> <math>~C_\mathrm{core}</math> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math>2\pi q^3 P_i R_\mathrm{eq}^{3\gamma_c} (1+\Lambda) \, .</math> </td> </tr> </table> </div> Hence, <div align="center"> <table border="0"> <tr> <td align="right"> <math>\biggl[ \frac{R^{2}_\mathrm{eq}}{2} \biggr] \frac{d^2\mathfrak{G}}{dR^2} \biggr|_{R_\mathrm{eq}}</math> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math>6\pi (\gamma_c - \gamma_e)q^3 P_i R_\mathrm{eq}^{3} (1+\Lambda) + \biggl( 2 - \frac{3}{2}\gamma_e \biggr) W_\mathrm{eq} </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~~ \biggl[ \frac{1}{P_iR_\mathrm{eq}} \biggr] \frac{d^2\mathfrak{G}}{dR^2} \biggr|_{R_\mathrm{eq}}</math> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math> 12\pi (\gamma_c - \gamma_e)q^3 (1+\Lambda) - \frac{1}{P_iR^3_\mathrm{eq}} ( 4 - 3\gamma_e) \biggl[ \frac{3GM_\mathrm{tot}^2}{5 R_\mathrm{eq}} \biggl(\frac{\nu^2}{q}\biggr) f \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math> ~12\pi (\gamma_c - \gamma_e)q^3 (1+\Lambda) - 4\pi ( 4 - 3\gamma_e) q^3 \Lambda f </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~~ \frac{d^2\mathfrak{G}}{dR^2} \biggr|_{R_\mathrm{eq}}</math> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math> ~12\pi P_iR_\mathrm{eq}\biggl[ (\gamma_c - \gamma_e)q^3 (1+\Lambda) - \biggl( \frac{4}{3} - \gamma_e \biggr) q^3 \Lambda f \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math> ~12\pi P_iR_\mathrm{eq} (\gamma_e - \gamma_c) q^3 \Lambda \biggl[ \frac{( \gamma_e - \frac{4}{3})}{(\gamma_e - \gamma_c)} f - \biggl(1+\frac{1}{\Lambda} \biggr) \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=~</math> </td> <td align="left"> <math> ~12\pi P_iR_\mathrm{eq} (\gamma_e - \gamma_c) q^3 \Lambda \biggl[ \frac{( \gamma_e - \frac{4}{3})}{(\gamma_e - \gamma_c)} f -1 -\frac{5}{2} (g^2-1) \biggr] \, . </math> </td> </tr> </table> </div>
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