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===Integration Through the n = 5 Envelope=== For an <math>~n = 5</math> envelope, we have, <div align="center"> <math> \phi_i = \frac{B_0^{-1}\sin\Delta}{\eta^{1/2}(3-2\sin^2\Delta)^{1/2}} </math> and <math> Q_i = - \frac{d\ln\phi}{d\ln\eta} = \frac{ 3\sin\Delta - 3\cos\Delta - 2\sin^3\Delta }{2 \sin\Delta (3-2\sin^2\Delta)}\, , </math> </div> where <math>~A_0</math> is a "homology factor," <math>~B_0</math> is an overall scaling coefficient, and we have introduced the notation, <div align="center"> <math>~\Delta \equiv \ln(A_0\eta)^{1/2} = \frac{1}{2} (\ln A_0 + \ln\eta) \, .</math> </div> Hence, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\mathcal{A}_\mathrm{env}</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~ \phi_i [ 4 - (n+1)Q_i] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{B_0^{-1}\sin\Delta}{\eta^{1/2}(3-2\sin^2\Delta)^{1/2}}\biggl\{ 4 ~-~ 6 \biggl[ \frac{ 3\sin\Delta - 3\cos\Delta - 2\sin^3\Delta }{2 \sin\Delta (3-2\sin^2\Delta)} \biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> <math>~\mathcal{B}_\mathrm{env}</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~ \frac{\sigma_c^2}{\gamma_e} - 2\alpha_\mathrm{env} \biggl(- \frac{3\phi^'}{\eta} \biggr)_i </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{1}{\gamma_e}\biggl[ \gamma_c (\mathfrak{F}_\mathrm{core} + 6) -8 \biggr] - 2\biggl[ 3 - \frac{4}{\gamma_e}\biggr] Q_i \biggl( \frac{3\phi_i }{\eta_i^2} \biggr) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{\gamma_c}{\gamma_e}\biggl[ \mathfrak{F}_\mathrm{core} + 6 -\frac{8}{\gamma_c} \biggr] - 6\biggl[ 3 - \frac{4}{\gamma_e}\biggr] \frac{B_0^{-1}\sin\Delta}{\eta^{5/2}(3-2\sin^2\Delta)^{1/2}} \biggl[ \frac{ 3\sin\Delta - 3\cos\Delta - 2\sin^3\Delta }{2 \sin\Delta (3-2\sin^2\Delta)} \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \frac{\gamma_c}{\gamma_e}\biggl[ \mathfrak{F}_\mathrm{core} + 6 -\frac{8}{\gamma_c} \biggr] - 3B_0^{-1}\biggl[ 3 - \frac{4}{\gamma_e}\biggr] \biggl[ \frac{ 3\sin\Delta - 3\cos\Delta - 2\sin^3\Delta }{ \eta^{5/2}(3-2\sin^2\Delta)^{3 / 2}} \biggr] \, . </math> </td> </tr> </table> This leads to a discrete, finite-difference representation of the form, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~y_+ \biggl[2\phi_i + \frac{\delta\eta}{\eta_i} \cdot \mathcal{A}_\mathrm{env} \biggr] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ y_- \biggl[\frac{\delta\eta }{\eta_i} \cdot \mathcal{A}_\mathrm{env} - 2\phi_i\biggr] + y_i\biggl[4\phi_i - 2(\delta\eta)^2 \cdot \mathcal{B}_\mathrm{env} \biggr] </math> </td> </tr> </table> </div> This provides an approximate expression for <math>~y_+ \equiv y_{i+1}</math>, given the values of <math>~y_- \equiv y_{i-1}</math> and <math>~y_i</math>; this works for all zones, <math>~i = 3 \rightarrow M</math> as long as the interface between the core and the envelope of the configuration is denoted by the grid index, <math>~i=1</math>. Note that, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\delta\eta</math> </td> <td align="center"> <math>~\equiv</math> </td> <td align="left"> <math>~\frac{\eta_\mathrm{surf}- \eta_\mathrm{interface} }{M - 1} </math> </td> <td align="center"> and </td> <td align="right"> <math>~\eta_i</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\eta_\mathrm{interface} + (i-1)\delta\eta \, . </math> </td> </tr> </table> At the interface, we need special treatment in order to ensure that both the amplitude and the first derivative of the displacement function behave properly. Specifically, when <math>~i = 1</math>, we must set, <math>~y_1 = x_N</math> and <math>~\eta_1 = (\mu_e/\mu_c)\xi_N/\sqrt{3}</math>. Then the value of <math>~y_2</math> is obtained from the expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~y_2 \biggl[2\phi_1 + \frac{\delta\eta}{\eta_1} \cdot \mathcal{A}_\mathrm{env} \biggr] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ y_0 \biggl[\frac{\delta\eta }{\eta_1} \cdot \mathcal{A}_\mathrm{env} - 2\phi_1\biggr] + y_1\biggl\{4\phi_1 - 2(\delta\eta)^2 \cdot \mathcal{B}_\mathrm{env} \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ y_1\biggl[ 4\phi_1 - 2(\delta\eta)^2 \cdot \mathcal{B}_\mathrm{env} \biggr] + \biggl[\frac{\delta\eta }{\eta_1} \cdot \mathcal{A}_\mathrm{env} - 2\phi_1\biggr] \biggl\{ y_2 ~-~ \frac{2 (\delta\eta) y_1}{\eta_1} \biggl[ 3\biggl(\frac{\gamma_c}{\gamma_e} -1\biggr) + \frac{\gamma_c}{\gamma_e} \cdot \frac{d\ln x}{d\ln\xi}\biggr|_\mathrm{interface} \biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow~~~y_2 \biggl[4\phi_1 \biggr] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ y_1\biggl[ 4\phi_1 - 2(\delta\eta)^2 \cdot \mathcal{B}_\mathrm{env} \biggr] ~-~ \frac{2 (\delta\eta) y_1}{\eta_1} \biggl[\frac{\delta\eta }{\eta_1} \cdot \mathcal{A}_\mathrm{env} - 2\phi_1\biggr] \biggl\{3\biggl(\frac{\gamma_c}{\gamma_e} -1\biggr) + \frac{\gamma_c}{\gamma_e} \cdot \frac{d\ln x}{d\ln\xi}\biggr|_\mathrm{interface} \biggr\} </math> </td> </tr> <tr> <td align="right"> <math>~\Rightarrow~~~\frac{y_2}{y_1} \biggl[\phi_1 \biggr] </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \biggl[ \phi_1 - \frac{(\delta\eta)^2}{2} \cdot \mathcal{B}_\mathrm{env} \biggr] ~-~ \frac{ (\delta\eta) }{2\eta_1} \biggl[\frac{\delta\eta }{\eta_1} \cdot \mathcal{A}_\mathrm{env} - 2\phi_1\biggr] \biggl\{3\biggl(\frac{\gamma_c}{\gamma_e} -1\biggr) + \frac{\gamma_c}{\gamma_e} \cdot \frac{d\ln x}{d\ln\xi}\biggr|_\mathrm{interface} \biggr\} \, . </math> </td> </tr> </table>
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