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=Entropy as a Step Function= Useful Chapters: <ul> <li>[[Appendix/Mathematics/StepFunction|Appendix/Mathematics/Stepfunction]]</li> <li>[[SSC/Structure/BiPolytropes/Analytic51Renormalize#From_Step-Function_Behavior_of_Specific_Entropy|Step-Function Behavior of Specific Entropy]]</li> </ul> ==Review== The unit — or, [https://en.wikipedia.org/wiki/Heaviside_step_function Heaviside] — step function, <math>H(x)</math>, is defined such that, <table border="0" align="center" cellpadding="8"> <tr> <td align="center"> <math> H(x) = \begin{cases} 0; & ~~ x < 0 \\ 1; & ~~ x > 0 \end{cases} </math> <p><br /> [<b>[[Appendix/References#MF53|<font color="red">MF53</font>]]</b>], Part I, §2.1 (p. 123), Eq. (2.1.6) </td> <td align="center" rowspan="2"> [[File:Heaviside01.png|300px|Heaviside Function]] </td> </tr> </table> In evaluating this function at <math>x=0</math>, we will adopt the ''half-maximum convention'' and set <math>H(0) = \tfrac{1}{2}</math>. As has been pointed out in, for example, [https://en.wikipedia.org/wiki/Heaviside_step_function a relevant Wikipedia discussion], the derivative of the unit step function is, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\frac{dH(x)}{dx}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>\delta(x) \, ,</math> </td> </tr> </table> where, <math>\delta(x)</math> is the Dirac Delta function. ==Perturbed Density== Let, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\zeta</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left"> <math>\frac{r}{r_i} - 1 </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ [\rho^*]_\mathrm{eq}</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left"> <math>H(\zeta)\cdot \rho^*_\mathrm{env} + H(-\zeta) \cdot \rho^*_\mathrm{core} \, ;</math> </td> </tr> </table> and, more generally after a perturbation, <math>\delta\rho(\zeta)</math>, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\rho^* = [\rho^*]_\mathrm{eq} + \delta\rho</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>[\rho^*]_\mathrm{eq} \biggl\{1 + \frac{\delta\rho}{[\rho^*]_\mathrm{eq}}\biggr\} = [\rho^*]_\mathrm{eq} \biggl\{1 + de^{i\omega t}\biggr\} \, .</math> </td> </tr> </table> Hence, in the [[SSC/Perturbations#Continuity_Equation|linearized version of the continuity equation]], we recognize that, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>d e^{i \omega t}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>\frac{\delta\rho}{[\rho^*]_\mathrm{eq}} \, .</math> </td> </tr> </table> <font color="red"><b>CORE:</b></font> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\rho^*_\mathrm{core}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl(1+ \frac{\xi^2}{3}\biggr)^{-5/2}</math> </td> <td align="center"> and </td> <td align="right"> <math>~\gamma_g</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{6}{5} </math> </td> <td align="center"> and </td> <td align="right"> <math>~\mathcal{S}_\mathrm{core} \equiv \frac{s(\gamma_g-1)}{\Re/\bar{\mu}}\biggr|_\mathrm{core}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \ln (5) \, . </math> </td> </tr> </table> <font color="red"><b>ENVELOPE:</b></font> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\rho^*_\mathrm{env}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\biggl(\frac{\mu_e}{\mu_c}\biggr)\theta_i^5 [\phi(\eta)]</math> </td> <td align="center"> and </td> <td align="right"> <math>~\gamma_g</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~2 </math> </td> <td align="center"> and </td> <td align="right"> <math>~\mathcal{S}_\mathrm{env} \equiv \frac{s(\gamma_g-1)}{\Re/\bar{\mu}}\biggr|_\mathrm{env}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ \ln \biggl[ \biggl(\frac{\mu_e}{\mu_c}\biggr)^{-2} \biggl( 1 + \frac{\xi_i^2}{3}\biggr)^2 \biggr] \, . </math> </td> </tr> </table> ==Perturbed Pressure== <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>P^*</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>(\rho^*)^{\gamma_g} \cdot \exp\biggl[ \frac{s(\gamma_g-1)}{\Re/\bar{\mu}} \biggr]</math> </td> </tr> </table> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>[P^*]_\mathrm{eq}</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left"> <math>H(\zeta)\cdot P^*_\mathrm{env} + H(-\zeta) \cdot P^*_\mathrm{core} \, ;</math> </td> </tr> </table> and, more generally after a perturbation, <math>\delta P(\zeta)</math>, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>P^* = [P^*]_\mathrm{eq} + \delta P</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>[P^*]_\mathrm{eq} \biggl\{1 + \frac{\delta P}{[P^*]_\mathrm{eq}}\biggr\} = [P^*]_\mathrm{eq} \biggl\{1 + pe^{i\omega t}\biggr\} \, .</math> </td> </tr> </table> Hence, in the [[SSC/Perturbations#Adiabatic_form_of_the_First_Law_of_Thermodynamics|linearized version of the first law of thermodynamics]], we recognize that, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>p e^{i \omega t}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>\frac{\delta P}{[P^*]_\mathrm{eq}} \, .</math> </td> </tr> </table> ==Obtaining Perturbed Density from Perturbed Pressure== Given that, quite generally, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> \frac{P}{\rho^{\gamma_g}} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \exp\biggl[ \frac{s(\gamma_g - 1)}{\mathfrak{R}/\bar\mu}\biggr]\, , </math> </td> </tr> </table> let's define the density-like quantity, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\mathcal{Q}^*</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left"> <math> e^{-\mathcal{S/\gamma_g}}\biggl[P^*\biggr]^{1/\gamma_g} \, ,</math> </td> </tr> </table> in which case, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\rho^*_\mathrm{eq}</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left"> <math> H(\zeta)\cdot [ \mathcal{Q}^*_\mathrm{eq}]_\mathrm{env} + H(-\zeta) \cdot [ \mathcal{Q}^*_\mathrm{eq}]_\mathrm{core} \, .</math> </td> </tr> </table> What happens if we perturb the pressure? In either region (core or envelope), <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\mathcal{Q}^*</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> e^{-\mathcal{S/\gamma_g}} [P^*_\mathrm{eq}]^{1/\gamma_g}\biggl[ 1 + \frac{\delta P}{P^*_\mathrm{eq}}\biggr]^{1/\gamma_g} \approx e^{-\mathcal{S/\gamma_g}} [P^*_\mathrm{eq}]^{1/\gamma_g}\biggl[ 1 + \frac{1}{\gamma_g} \cdot \frac{\delta P}{P^*_\mathrm{eq}}\biggr] = [Q^*_\mathrm{eq}]\biggl[ 1 + \frac{1}{\gamma_g} \cdot \frac{\delta P}{P^*_\mathrm{eq}}\biggr] \, .</math> </td> </tr> </table> As a result, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\rho^* = \rho^*_\mathrm{eq} + \delta \rho</math> </td> <td align="center"> <math>\equiv</math> </td> <td align="left"> <math> H(\zeta)\cdot [ \mathcal{Q}^*]_\mathrm{env} + H(-\zeta) \cdot [ \mathcal{Q}^*]_\mathrm{core} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> H(\zeta)\cdot \biggl\{[Q^*_\mathrm{eq}]\biggl[ 1 + \frac{1}{\gamma_g} \cdot \frac{\delta P}{P^*_\mathrm{eq}}\biggr]\biggr\}_\mathrm{env} + H(-\zeta) \cdot \biggl\{[Q^*_\mathrm{eq}]\biggl[ 1 + \frac{1}{\gamma_g} \cdot \frac{\delta P}{P^*_\mathrm{eq}}\biggr]\biggr\}_\mathrm{core} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> H(\zeta)\cdot [Q^*_\mathrm{eq}]_\mathrm{env} + H(-\zeta) \cdot [Q^*_\mathrm{eq}]_\mathrm{core} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> +~ H(\zeta)\cdot \biggl\{[Q^*_\mathrm{eq}]\biggl[ \frac{1}{\gamma_g} \cdot \frac{\delta P}{P^*_\mathrm{eq}}\biggr]\biggr\}_\mathrm{env} + H(-\zeta) \cdot \biggl\{[Q^*_\mathrm{eq}]\biggl[ \frac{1}{\gamma_g} \cdot \frac{\delta P}{P^*_\mathrm{eq}}\biggr]\biggr\}_\mathrm{core} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \rho^*_\mathrm{eq} +~ H(\zeta)\cdot \biggl\{[Q^*_\mathrm{eq}]\biggl[ \frac{1}{\gamma_g} \cdot \frac{\delta P}{P^*_\mathrm{eq}}\biggr]\biggr\}_\mathrm{env} + H(-\zeta) \cdot \biggl\{[Q^*_\mathrm{eq}]\biggl[ \frac{1}{\gamma_g} \cdot \frac{\delta P}{P^*_\mathrm{eq}}\biggr]\biggr\}_\mathrm{core} </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ \frac{\delta\rho}{\rho^*_\mathrm{eq}}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{H(\zeta)}{\rho^*_\mathrm{eq}} \cdot \biggl\{[Q^*_\mathrm{eq}]\biggl[ \frac{1}{\gamma_g} \cdot \frac{\delta P}{P^*_\mathrm{eq}}\biggr]\biggr\}_\mathrm{env} + \frac{H(-\zeta)}{\rho^*_\mathrm{eq}} \cdot \biggl\{[Q^*_\mathrm{eq}]\biggl[ \frac{1}{\gamma_g} \cdot \frac{\delta P}{P^*_\mathrm{eq}}\biggr]\biggr\}_\mathrm{core} </math> </td> </tr> </table> ==Set of Linearized Equations== Borrowing from [[SSC/Perturbations#Summary_Set_of_Linearized_Equations|an accompanying discussion]], we have … <div align="center"> <table border="1" cellpadding="10"> <tr><td align="center"> <font color="#770000">'''Linearized'''</font><br /> <span id="Continuity"><font color="#770000">'''Equation of Continuity'''</font></span><br /> <math> r_0 \frac{dx}{dr_0} = - 3 x - d , </math><br /> <font color="#770000">'''Linearized'''</font><br /> <span id="PGE:Euler"><font color="#770000">'''Euler + Poisson Equations'''</font></span><br /> <math> \frac{P_0}{\rho_0} \frac{dp}{dr_0} = (4x + p)g_0 + \omega^2 r_0 x , </math><br /> <font color="#770000">'''Linearized'''</font><br /> <span id="PGE:AdiabaticFirstLaw">Adiabatic Form of the<br /> <font color="#770000">'''First Law of Thermodynamics'''</font></span><br /> <math> p = \gamma_\mathrm{g} d \, . </math> </td></tr> </table> </div> Rearranging terms in the "Linearized Euler + Poisson Equations" as follows … <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\frac{1}{\rho_0} \cdot \frac{dp}{dr_0}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{1}{P_0}\biggl[ (4x + p)g_0 + \omega^2 r_0 x \biggr] </math> </td> </tr> </table> we realize that the expression on the RHS has the same value at the interface, whether you're viewing the equation from the point of view of the core or the envelope; and we recognize as well that <math>\rho_0</math> is a simple step function at the interface. Hence, letting a prime indicate differentiation with respect to <math>r_0</math>, we can write, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> H(\zeta)\cdot (p')_\mathrm{env} + H(-\zeta)\cdot (p')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{[\rho_0]_\mathrm{core}}{P_0}\biggl[ (4x + p)g_0 + \omega^2 r_0 x \biggr] \biggl\{ H(\zeta)\cdot \biggl[ \frac{\mu_e}{\mu_c} \biggr] + H(-\zeta) \biggr\} \, . </math> </td> </tr> </table> Analogously, the "Linearized Equation of Continuity" can be rewritten as, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> H(\zeta)\cdot (x')_\mathrm{env} + H(-\zeta)\cdot (x')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \frac{3x}{r_0} - \frac{1}{r_0}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} \, . </math> </td> </tr> </table> Now, given that <math>\zeta = (r_0/r_i - 1)</math>, we see that, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> \frac{dH(\zeta)}{dr_0} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{\partial H(\zeta)}{\partial \zeta} \cdot \frac{d\zeta}{dr_0} = r_o^{-1} \delta(\zeta) \, ; </math> </td> </tr> </table> and, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> \frac{dH(-\zeta)}{dr_0} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> -\frac{\partial H(\zeta)}{\partial \zeta} \cdot \frac{d\zeta}{dr_0} = -r_o^{-1} \delta(\zeta) \, . </math> </td> </tr> </table> Hence, differentiation of the "Linearized Equation of Continuity" gives, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> \frac{d}{dr_0}\biggl[H(\zeta)\cdot (x')_\mathrm{env}\biggr] + \frac{d}{dr_0}\biggl[H(-\zeta)\cdot (x')_\mathrm{core}\biggr] </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] - \frac{1}{r_0} \frac{d}{dr_0}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} + \frac{1}{r_0^2}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ (x')_\mathrm{env}\frac{d}{dr_0}\biggl[H(\zeta)\biggr] + H(\zeta)\cdot (x'')_\mathrm{env} + (x')_\mathrm{core}\frac{d}{dr_0}\biggl[H(-\zeta)\biggr] + H(-\zeta)\cdot (x'')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] + \frac{1}{r_0^2}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env}\frac{d}{dr_0}\biggl\{H(\zeta) \biggr\} - \frac{1}{r_0} \biggl\{ H(\zeta)\cdot \biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{env} \biggr\} - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \frac{d}{dr_0}\biggl\{H(-\zeta) \biggr\} - \frac{1}{r_0} \biggl\{H(-\zeta)\biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{core} \biggr\} </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ (x')_\mathrm{env} \biggl[\frac{\delta(\zeta)}{r_0}\biggr] + H(\zeta)\cdot (x'')_\mathrm{env} - (x')_\mathrm{core}\biggl[\frac{\delta(\zeta)}{r_0}\biggr] + H(-\zeta)\cdot (x'')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] + \frac{1}{r_0^2}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} - \frac{1}{r_0} \biggl\{ H(\zeta)\cdot \biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{env} \biggr\} + \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} - \frac{1}{r_0} \biggl\{H(-\zeta)\biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{core} \biggr\} </math> </td> </tr> </table> ===From the Perspective of the Core=== When <math>r_0/r_i \le 1</math> — that is, from the perspective of the core while including the interface, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> - (x')_\mathrm{core}\biggl[\frac{\delta(\zeta)}{r_0}\biggr] + H(-\zeta)\cdot (x'')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] + \frac{1}{r_0^2}\biggl\{ H(-\zeta)\biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} + \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} - \frac{1}{r_0} \biggl\{H(-\zeta)\biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{core} \biggr\} </math> </td> </tr> </table> And examining only the interface, where <math>\delta(\zeta) = 1</math> while <math>H(-\zeta) = 0</math>, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> - (x')_\mathrm{core}\biggl[\frac{\delta(\zeta)}{r_0}\biggr] </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} + \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} </math> </td> </tr> <tr> <td align="right"> <math> \Rightarrow ~~~ - (x')_\mathrm{core} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ 3x' - \frac{3x}{r_0}\biggr] - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} + \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} </math> </td> </tr> </table> ===From the Perspective of the Envelope=== When <math>r_0/r_i \ge 1</math> — that is, from the perspective of the envelope while including the interface, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> (x')_\mathrm{env} \biggl[\frac{\delta(\zeta)}{r_0}\biggr] + H(\zeta)\cdot (x'')_\mathrm{env} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - \biggl[ \frac{3}{r_0} \cdot x' - \frac{3x}{r_0^2}\biggr] + \frac{1}{r_0^2}\biggl\{ H(\zeta)\cdot \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} \biggr\} \, . </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> - \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{env} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} - \frac{1}{r_0} \biggl\{ H(\zeta)\cdot \biggl[ \frac{p'}{\gamma_g} \biggr]_\mathrm{env} \biggr\} + \frac{1}{r_0} \biggl[ \frac{p}{\gamma_g} \biggr]_\mathrm{core} \biggl\{\frac{\delta(\zeta)}{r_0} \biggr\} </math> </td> </tr> </table> ==Focus on Nonlinear Continuity Equation== A spherical shell of ''core'' density, <math>\rho_0</math>, where the inner radius of the shell is <math>(r_0 - \Delta r)</math> and its outer radius is <math>(r_0+\Delta r)</math> has a ''shell'' mass given by the expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>(\Delta m)_\mathrm{core}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{4\pi}{3} \cdot \rho_0 \biggl[ (r_0+\Delta r)^3 - (r_0 - \Delta r)^3 \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{4\pi}{3} \cdot \rho_0 r_0^3 \biggl[ \biggl(1 + \frac{\Delta r}{r_0} \biggr)^3 - \biggl(1 - \frac{\Delta r}{r_0} \biggr)^3 \biggr] </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ \biggl[ \frac{3}{4\pi \rho_0 r_0^3} \biggr](\Delta m)_\mathrm{core}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[1 + \frac{2\Delta r}{r_0} + \biggl(\frac{\Delta r}{r_0}\biggr)^2\biggr] \biggl(1 + \frac{\Delta r}{r_0} \biggr) - \biggl[1 - \frac{2\Delta r}{r_0} + \biggl(\frac{\Delta r}{r_0}\biggr)^2\biggr] \biggl(1 - \frac{\Delta r}{r_0} \biggr) </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[1 + \frac{3\Delta r}{r_0} + 3\biggl(\frac{\Delta r}{r_0}\biggr)^2 + \biggl(\frac{\Delta r}{r_0}\biggr)^3\biggr] - \biggl[1 - \frac{3\Delta r}{r_0} + 3\biggl(\frac{\Delta r}{r_0}\biggr)^2 - \biggl(\frac{\Delta r}{r_0}\biggr)^3\biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[ \frac{6\Delta r}{r_0} + 2\biggl(\frac{\Delta r}{r_0}\biggr)^3\biggr] </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ (\Delta m)_\mathrm{core}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[ \frac{4\pi \rho_0 r_0^3}{3} \biggr] \biggl[ \frac{6\Delta r}{r_0} + 2\biggl(\frac{\Delta r}{r_0}\biggr)^3\biggr] \, . </math> </td> </tr> </table> Similarly, as viewed from the perspective of the envelope, it has a shell mass of, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>(\Delta m)_\mathrm{env}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{4\pi}{3} \cdot \biggl(\frac{\mu_e}{\mu_c}\biggr) \rho_0 \biggl[ (r_0+\Delta r)^3 - (r_0 - \Delta r)^3 \biggr] </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl(\frac{\mu_e}{\mu_c}\biggr) \biggl[ \frac{4\pi \rho_0 r_0^3}{3} \biggr] \biggl[ \frac{6\Delta r}{r_0} + 2\biggl(\frac{\Delta r}{r_0}\biggr)^3\biggr] \, . </math> </td> </tr> </table> Better yet, pick the two edges of the shell, <math>r_+</math> and <math>r_-</math>, and let <math>r_0 \equiv (r_+ + r_-)/2</math> and <math>\Delta r = (r_+ - r_-)/2</math>. Given the value of <math>\rho_0</math>, the unperturbed mass in the shell is given by the above expression, that is, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>(\Delta m)_0</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[ \frac{4\pi \rho_0 r_0^3}{3} \biggr] \biggl[ \frac{6\Delta r}{r_0} + 2\biggl(\frac{\Delta r}{r_0}\biggr)^3\biggr] \, . </math> </td> </tr> </table> Now, let <math>r_+ \rightarrow (r_+)_0 + (\delta r_+), ~r_- \rightarrow (r_-)_0 + (\delta r_-), </math> and, <math>\rho_0 \rightarrow (\rho_0)_0 + (\delta \rho)</math>. We then have, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>2r_0</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> [(r_+)_0 + (\delta r_+)] + [(r_-)_0 + (\delta r_-)] = 2(r_0)_0 + [\delta r_+ + \delta r_-] \, ; </math> </td> </tr> <tr> <td align="right"> <math>2\Delta r</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> [(r_+)_0 + (\delta r_+)] - [(r_-)_0 + (\delta r_-)] = 2(\Delta r)_0 + [\delta r_+ - \delta r_-] \, ; </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ \frac{\Delta r}{r_0}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{2(\Delta r)_0 + [\delta r_+ - \delta r_-]}{ 2(r_0)_0 + [\delta r_+ + \delta r_-] } = \frac{(\Delta r)_0}{(r_0)_0} \times \biggl\{1 + \biggl[ \frac{\delta r_+ - \delta r_-}{2(\Delta r)_0} \biggr] \biggr\} \biggl\{1 + \biggl[ \frac{\delta r_+ + \delta r_-}{2(r_0)_0} \biggr] \biggr\}^{-1} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>\approx</math> </td> <td align="left"> <math> \frac{(\Delta r)_0}{(r_0)_0} \times \biggl\{1 + \biggl[ \frac{\delta r_+ - \delta r_-}{2(\Delta r)_0} \biggr] \biggr\} \biggl\{1 - \biggl[ \frac{\delta r_+ + \delta r_-}{2(r_0)_0} \biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>\approx</math> </td> <td align="left"> <math> \frac{(\Delta r)_0}{(r_0)_0} \times \biggl\{1 + \biggl[ \frac{\delta r_+ - \delta r_-}{2(\Delta r)_0} \biggr] - \biggl[ \frac{\delta r_+ + \delta r_-}{2(r_0)_0} \biggr] \biggr\} </math> </td> </tr> </table> In order for the shell to have the same <math>\Delta m</math> in both the unperturbed and perturbed cases, the following relation must hold: <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> \biggl[ \frac{8\pi (\rho_0)_0 (r_0)_0^3}{3} \biggr] \biggl\{ \frac{3(\Delta r)_0}{(r_0)_0} + \biggl[ \frac{(\Delta r)_0}{(r_0)_0}\biggr ]^3 \biggr\} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl\{ \frac{\pi [(\rho_0)_0 + \delta\rho] [2r_0]^3}{2\cdot 3} \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math> \times 2\biggl\{ \frac{3\Delta r}{r_0} + \biggl(\frac{\Delta r}{r_0}\biggr)^3\biggr\} </math> </td> </tr> </table>
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