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====Step 5==== <font color="red"><b>STEP 5:</b></font> Guess the eigenvector, <math>{\delta r}_i</math>, remembering that a reasonably good trial eigenfunction for the core is one that has a "parabolic dependence on the radius," namely, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\frac{x}{\alpha_\mathrm{scale}}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> 1 - \frac{\xi^2}{15} \, , </math> </td> <td align="center"> where, <td align="right"> <math>\xi</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl(\frac{2\pi}{3}\biggr)^{1 / 2} r_0 \, . </math> </td> </tr> </table> This means, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>x(r_0)</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \alpha_\mathrm{scale}\biggl[1 - \biggl(\frac{2\pi}{45}\biggr)r_0^2 \biggr] \, , </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ \frac{dx}{dr_0}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> -\alpha_\mathrm{scale}\biggl(\frac{4\pi}{45}\biggr)r_0 \, . </math> </td> </tr> </table> Note as well that, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\frac{d\ln x}{d\ln r_0}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> -\alpha_\mathrm{scale}\biggl(\frac{4\pi}{45}\biggr) \frac{r_0^2}{x} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl(\frac{4\pi}{45}\biggr) \frac{3\xi^2}{2\pi} \biggl[\frac{\xi^2}{15}-1\biggr]^{-1} \, . </math> </td> </tr> </table> <table border="1" align="center" width="80%" cellpadding="8"><tr><td align="left"> <div align="center"><b>Finite-Difference Representation of <math>\delta r</math></b></div> Once a "guess" for the fractional displacement vector, <math>(\delta r)_j = [x \cdot r_0]_j\, ,</math> has been specified, we recognize that the perturbed location of each radial shell is given by the expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>r_j</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> (r_0)_j + (\delta r)_j \, . </math> </td> </tr> </table> </td></tr></table> ---- <table border="1" align="center" cellpadding="5"> <tr> <td align="center" colspan="13">Parabolic Displacement Function w/ <math>\alpha_\mathrm{scale} = -0.001</math></td> </tr> <tr> <td align="center" rowspan="2">Shell</td> <td align="center" rowspan="2"><math>m </math></td> <td align="center" rowspan="2"><math>r_0</math></td> <td align="center" rowspan="2"><math>\frac{x}{\alpha_\mathrm{scale}}</math></td> <td align="center" rowspan="2"><math>r_j</math></td> <td align="center" rowspan="1" colspan="2">Analytic</td> <td align="center" rowspan="1" colspan="3">FD</td> <td align="center" rowspan="2"><math>P^*</math></td> <td align="center" rowspan="2"><math>-~\frac{dP^*}{dm}</math></td> <td align="center" rowspan="2"><math>-4\pi (r^*)^2\frac{dP^*}{dm} = g_0</math></td> </tr> <tr> <td align="center" rowspan="1"><math>\rho_0</math></td> <td align="center" rowspan="1"><math>d_\mathrm{analytic}</math></td> <td align="center" rowspan="1"><math>[\rho_{j - 1 / 2}]_0</math></td> <td align="center" rowspan="1"><math>d_{j-1 / 2}</math></td> <td align="center" rowspan="1"><math>\rho_{j - 1 / 2}</math></td> </tr> <tr> <td align="center">0</td> <td align="right">0.000000</td> <td align="right">0.000000</td> <td align="right">1.000000</td> <td align="right">0.000000</td> <td align="right">1.000000</td> <td align="right">+ 0.003000</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">1.000000</td> <td align="center"><math>\infty</math></td> <td align="right">0.000000</td> </tr> <tr> <td align="center">½</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.995868</td> <td align="right">0.003004</td> <td align="right">0.998860</td> <td align="right">1.000000</td> <td align="center"><math>\infty</math></td> <td align="right">0.000000</td> </tr> <tr> <td align="center">1</td> <td align="right">0.001039</td> <td align="right">0.062922</td> <td align="right">0.999447</td> <td align="right">0.062859</td> <td align="right">0.993123</td> <td align="right">0.002997</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.991754</td> <td align="right">5.275715</td> <td align="right">0.262476</td> </tr> <tr> <td align="center">1½</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.981896</td> <td align="right">0.002999</td> <td align="right">0.984840</td> <td align="right">1.000000</td> <td align="center"><math>\infty</math></td> <td align="right">0.000000</td> </tr> <tr> <td align="center">2</td> <td align="right">0.008211</td> <td align="right">0.125843</td> <td align="right">0.997789</td> <td align="right">0.125718</td> <td align="right">0.972886</td> <td align="right">0.002989</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.967552</td> <td align="right">2.605474</td> <td align="right">0.518508</td> </tr> <tr> <td align="center">2½</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.955465</td> <td align="right">0.002988</td> <td align="right">0.958319</td> <td align="right">1.000000</td> <td align="center"><math>\infty</math></td> <td align="right">0.000000</td> </tr> <tr> <td align="center">3</td> <td align="right">0.027155</td> <td align="right">0.188765</td> <td align="right">0.995025</td> <td align="right">0.188577</td> <td align="right">0.940420</td> <td align="right">0.002975</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.928937</td> <td align="right">1.701968</td> <td align="right">0.762083</td> </tr> <tr> <td align="center">3½</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.917695</td> <td align="right">0.002971</td> <td align="right">0.920421</td> <td align="right">1.000000</td> <td align="center"><math>\infty</math></td> <td align="right">0.000000</td> </tr> <tr> <td align="center">4</td> <td align="right">0.062586</td> <td align="right">0.251686</td> <td align="right">0.991155</td> <td align="right">0.251437</td> <td align="right">0.897462</td> <td align="right">0.002956</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.878252</td> <td align="right">1.241164</td> <td align="right">0.988001</td> </tr> <tr> <td align="center" colspan="13"><font size="+1"><b>⋮</b></td> </tr> <tr> <td align="center">95</td> <td align="right">6.769823</td> <td align="right">5.977546</td> <td align="right">- 3.988996</td> <td align="right">6.001390</td> <td align="right">0.0002917</td> <td align="right">- 0.021945</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.000057</td> <td align="right">0.000422</td> <td align="right">0.189466</td> </tr> <tr> <td align="center">95½</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.0002844</td> <td align="right">- 0.021852</td> <td align="right">0.0002782</td> <td align="right">1.000000</td> <td align="center"><math>\infty</math></td> <td align="right">0.000000</td> </tr> <tr> <td align="center">96</td> <td align="right">6.777942</td> <td align="right">6.040467</td> <td align="right">- 4.094580</td> <td align="right">6.065200</td> <td align="right">0.0002773</td> <td align="right">- 0.022473</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.000054</td> <td align="right">0.000405</td> <td align="right">0.185762</td> </tr> <tr> <td align="center">96½</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.002705</td> <td align="right">- 0.022366</td> <td align="right">0.0002644</td> <td align="right">1.000000</td> <td align="center"><math>\infty</math></td> <td align="right">0.000000</td> </tr> <tr> <td align="center">97</td> <td align="right">6.785828</td> <td align="right">6.103389</td> <td align="right">- 4.201270</td> <td align="right">6.129031</td> <td align="right">0.0002638</td> <td align="right">- 0.023006</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.000051</td> <td align="right">0.000389</td> <td align="right">0.182163</td> </tr> <tr> <td align="center">97½</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.0002574</td> <td align="right">- 0.022884</td> <td align="right"> 0.0002515 </td> <td align="right">1.000000</td> <td align="center"><math>\infty</math></td> <td align="right">0.000000</td> </tr> <tr> <td align="center">98</td> <td align="right">6.793488</td> <td align="right">6.166310</td> <td align="right">- 4.309066</td> <td align="right">6.192881</td> <td align="right">0.0002511</td> <td align="right">- 0.023545</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.000048</td> <td align="right">0.000374</td> <td align="right">0.178666</td> </tr> <tr> <td align="center">98½</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.0002450</td> <td align="right">- 0.023408</td> <td align="right"> 0.0002393 </td> <td align="right">1.000000</td> <td align="center"><math>\infty</math></td> <td align="right">0.000000</td> </tr> <tr> <td align="center">99</td> <td align="right">6.800930</td> <td align="right">6.229232</td> <td align="right">- 4.417967</td> <td align="right">6.256752</td> <td align="right">0.0002391</td> <td align="right">- 0.024090</td> <td align="center">---</td> <td align="center">---</td> <td align="center">---</td> <td align="right">0.000045</td> <td align="right">0.000359</td> <td align="right">0.175267</td> </tr> </table> ---- [[File:DensityPert51Core02.png|325px|right|Density perturbation]]Hence, from the [[SSC/Perturbations#Continuity_Equation|linearized continuity equation]], <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>d</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> - r_0 \frac{dx}{dr_0} - 3 x </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \alpha_\mathrm{scale} \biggl\{ \biggl(\frac{4\pi}{45}\biggr)r_0^2 - 3 \biggl[1 - \biggl(\frac{2\pi}{45}\biggr)r_0^2 \biggr] \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \alpha_\mathrm{scale} \biggl\{ 2\biggl(\frac{2\pi}{45}\biggr)r_0^2 -3 + 3 \biggl(\frac{2\pi}{45}\biggr)r_0^2 \biggr\} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \alpha_\mathrm{scale} \biggl\{ \biggl(\frac{2\pi}{9}\biggr)r_0^2 -3 \biggr\} \, . </math> </td> </tr> </table> The solid black curve in the figure shown here, on the right, displays this analytically specified density perturbation, <math>d(m)</math>, for the case <math>\alpha_\mathrm{scale} = - 0.001</math>. <table border="1" align="center" width="80%" cellpadding="8"><tr><td align="left"> <div align="center"><b>Finite-Difference Representation of <math>d</math></b></div> Our finite-difference representation of the mass-density at each radial shell in the equilibrium configuration (subscript "0") is, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\biggl[{\bar\rho}_{j-1/2} \biggr]_0</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[m_j - m_{j-1}\biggr]_0\biggl[\frac{4\pi}{3} (r_j^3 - r_{j-1}^3) \biggr]_0^{-1} \, . </math> </td> </tr> </table> After perturbing the radial location of each shell — that is, after setting <math>r_j = (r_0)_j + [x \cdot r_0]_j</math> — the resulting finite-difference representation of the perturbed mass density of each shell is given by the expression, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>{\bar\rho}_{j-1/2} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl[m_j - m_{j-1}\biggr]_0\biggl[\frac{4\pi}{3} (r_j^3 - r_{j-1}^3) \biggr]^{-1} \, . </math> </td> </tr> </table> (Note that we retain a subscript "0" on the mass, <math>m_j</math>, because it serves as our Lagrangian identifier for each shell.) The fractional density perturbation at each discrete shell is, then, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math> d_{j-1/2} \equiv \biggl[ \frac{\delta \rho}{\rho_0} \biggr]_{j-1/2} = \biggl\{ \frac{ {\bar\rho}_{j-1 / 2} }{ [{\bar\rho}_{j-1 / 2}]_0 } - 1 \biggr\} </math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>\frac{(r_j^3 - r_{j-1}^3)_0}{(r_j^3 - r_{j-1}^3)} -1 \, . </math> </td> </tr> </table> The red dots in the above "density perturbation" figure display how <math>d_j</math> varies with mass shell when <math>x</math> is specified by the parabolic dependence on radius. The dots lie virtually on top of the solid black curve in this figure, indicating that our finite-difference representation of the perturbed mass density matches well the analytically specified perturbed mass density. </td></tr></table> And, from [[SSC/Perturbations#Entropy_Conservation|linearized entropy conservation]], <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>p</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \alpha_\mathrm{scale} \biggl\{ \biggl(\frac{2\pi}{9}\biggr)r_0^2 -3 \biggr\} \gamma_c </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \alpha_\mathrm{scale} \biggl\{\biggl(\frac{2\pi}{9}\biggr)r_0^2 -3 \biggr\} \frac{6}{5} </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ \frac{dp}{dr_0}</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \alpha_\mathrm{scale} \biggl(\frac{8\pi}{15}\biggr)r_0 \, . </math> </td> </tr> </table> Now, [[#Model_Amodel2|from below]] we find that, <table border="0" cellpadding="8" align="center"> <tr> <td align="right"><math>\frac{P_0}{\rho_0} = \frac{P^*}{\rho^*}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl(1 + \frac{\xi^2}{3}\biggr)^{-3} \biggl(1 + \frac{\xi^2}{3}\biggr)^{5 / 2} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl(1 + \frac{\xi^2}{3}\biggr)^{-1 / 2} \, , </math> </td> </tr> <tr> <td align="right"><math>g_0 = \frac{m}{(r^*)^2}</math></td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl( \frac{2\cdot 3}{\pi } \biggr)^{1/2} \biggl[ \xi^3 \biggl( 1 + \frac{1}{3}\xi^2 \biggr)^{-3/2} \biggr] \biggl[ \biggl(\frac{3}{2\pi}\biggr)^{1 / 2}\xi \biggr]^{-2} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"><math>=</math></td> <td align="left"> <math> \biggl( \frac{8\pi}{3 } \biggr)^{1/2} \biggl[ \xi \biggl( 1 + \frac{1}{3}\xi^2 \biggr)^{-3/2} \biggr] \, . </math> </td> </tr> </table> Hence, the [[SSC/Perturbations#Euler_+_Poisson_Equations|linearized Euler + Poisson Equations]] expression gives, <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>\omega^2 r_0 x</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \frac{P_0}{\rho_0} \frac{dp}{dr_0} - (4x + p)g_0 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \alpha_\mathrm{scale} \biggl(1 + \frac{\xi^2}{3}\biggr)^{-1 / 2} \biggl(\frac{8\pi}{15}\biggr)r_0 - \biggl\{ 4\alpha_\mathrm{scale}\biggl[1 - \biggl(\frac{2\pi}{45}\biggr)r_0^2 \biggr] + \alpha_\mathrm{scale} \biggl[\biggl(\frac{2\pi}{9}\biggr)r_0^2 -3 \biggr] \frac{6}{5} \biggr\} \biggl( \frac{8\pi}{3 } \biggr)^{1/2} \biggl[ \xi \biggl( 1 + \frac{1}{3}\xi^2 \biggr)^{-3/2} \biggr] </math> </td> </tr> <tr> <td align="right"> <math>\Rightarrow ~~~ \biggl(\frac{\omega^2}{\alpha_\mathrm{scale}}\biggr)\biggl( 1 + \frac{1}{3}\xi^2 \biggr)^{3/2} r_0 x</math> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl(1 + \frac{\xi^2}{3}\biggr) \biggl(\frac{8\pi}{15}\biggr)r_0 - \biggl\{ 4 - \biggl(\frac{8\pi}{45}\biggr)r_0^2 + \biggl(\frac{12\pi}{45}\biggr)r_0^2 - \frac{18}{5} \biggr\} \biggl( \frac{8\pi}{3 } \biggr)^{1/2} \xi </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl(1 + \frac{\xi^2}{3}\biggr) \biggl(\frac{8\pi}{15}\biggr)r_0 - \biggl[ \frac{2}{5} + \biggl(\frac{4\pi}{45}\biggr)r_0^2 \biggr] \biggl( \frac{8\pi}{3 } \biggr)^{1/2} \xi </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl(1 + \frac{\xi^2}{3}\biggr) \biggl(\frac{8\pi}{15}\biggr)\biggl(\frac{3}{2\pi}\biggr)^{1 / 2} \xi - \biggl[ \frac{2}{5} + \biggl(\frac{4\pi}{45}\biggr)\biggl(\frac{3}{2\pi}\biggr) \xi^2 \biggr] \biggl( \frac{8\pi}{3 } \biggr)^{1/2} \xi </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math> \biggl(\frac{2^5\pi}{3 \cdot 5^2}\biggr)^{1 / 2} \xi - \frac{2}{5} \biggl( \frac{8\pi}{3 } \biggr)^{1/2} \xi + \biggl(\frac{2^5\pi}{3^3\cdot 5^2}\biggr)^{1 / 2} \xi^3 - \biggl( \frac{2^5\pi}{3^3\cdot 5^2 } \biggr)^{1/2} \xi^3 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>=</math> </td> <td align="left"> <math>0</math> <font color="red">Exactly!</font> </td> </tr> </table>
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