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====Using Our Adopted Notation==== Consider the simple model of two spherical stars in circular orbit about one another, as depicted here on the right. In addition to the physical parameters explicitly labeled in this diagram, we adopt the following variable notation: <div align="center"> <table border="0" cellpadding="5" align="center" width="100%"> <tr><td align="left"> * The total system mass is, <div align="center"> <math>~M_\mathrm{tot} \equiv M + M^' \, ;</math> </div> * The ratio of the primary to secondary mass is, <div align="center"> <math>~\lambda \equiv \frac{M}{M^'} \, ;</math> </div> * And the separation between the two centers is, <div align="center"> <math>~d \equiv r_\mathrm{cm} + r^'_\mathrm{cm} \, .</math> </div> </td> <td align="center"> [[File:BinarySimpleModel02.png|350px|Simple Binary Model]] </td> </tr> </table> </div> For a circular orbit, the angular velocity is related to the the system mass and separation via the Kepler relation, <div align="center"> <math>~\omega^2 d^3 = GM_\mathrm{tot} \, ,</math> </div> and the distances, <math>~r_\mathrm{cm}</math> and <math>~r^'_\mathrm{cm}</math>, between the center of each star and the center of mass (cm) of the system must be related to one another via the expression, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~\frac{r^'_\mathrm{cm}}{r_\mathrm{cm}} </math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{M}{M^'} = \lambda \, .</math> </td> </tr> </table> </div> Note that the following relations also hold: <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~M = M_\mathrm{tot} \biggl( \frac{\lambda}{1+\lambda}\biggr)</math> </td> <td align="center"> and </td> <td align="left"> <math>~M^' = M_\mathrm{tot} \biggl( \frac{1}{1+\lambda}\biggr)</math> </td> </tr> <tr> <td align="right"> <math>~r_\mathrm{cm} = d \biggl( \frac{1}{1+\lambda}\biggr) \, ;</math> </td> <td align="center"> and </td> <td align="left"> <math>~r^'_\mathrm{cm} = d \biggl( \frac{\lambda}{1+\lambda}\biggr) \, .</math> </td> </tr> </table> </div> Hence, the orbital angular momentum is, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~L_\mathrm{orb}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ [M r^2_\mathrm{cm} + M^' (r^'_\mathrm{cm})^2]\omega </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ M_\mathrm{tot} d^2 \biggl[\biggl( \frac{\lambda}{1+\lambda}\biggr) \biggl( \frac{1}{1+\lambda}\biggr)^2 + \biggl( \frac{1}{1+\lambda}\biggr) \biggl( \frac{\lambda}{1+\lambda}\biggr)^2 \biggr] \biggl[\frac{GM_\mathrm{tot}}{d^3}\biggr]^{1 / 2} </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ (G M_\mathrm{tot}^3 d)^{1 / 2} \biggl[\frac{\lambda}{(1+\lambda)^2} \biggr] \, .</math> </td> </tr> </table> </div> Assuming that both stars are rotating synchronously with the orbit, their respective spin angular momenta are, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~L_M = I_M \omega</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{2}{5}MR^2 \omega</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{2}{5}M_\mathrm{tot} \biggl(\frac{\lambda}{1+\lambda}\biggr) R^2 \biggl[ \frac{G M_\mathrm{tot}}{d^3} \biggr]^{1 / 2}</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{2}{5}(GM_\mathrm{tot}^3 d)^{1 / 2} \biggl(\frac{\lambda}{1+\lambda}\biggr) \biggl( \frac{R}{d}\biggr)^2 \, ,</math> </td> </tr> <tr> <td align="right"> <math>~L_{M^'} = I_{M^'} \omega</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{2}{5}{M^'}(R^')^2 \omega</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{2}{5}M_\mathrm{tot} \biggl(\frac{1}{1+\lambda}\biggr) (R^')^2 \biggl[ \frac{G M_\mathrm{tot}}{d^3} \biggr]^{1 / 2}</math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~\frac{2}{5}(GM_\mathrm{tot}^3 d)^{1 / 2} \biggl(\frac{1}{1+\lambda}\biggr) \biggl( \frac{R^'}{d}\biggr)^2 \, .</math> </td> </tr> </table> </div> <span id="SphericalLtot">Hence, the total angular momentum of the system is,</span> <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~L_\mathrm{tot} = L_\mathrm{orb} + L_M + L_{M^'}</math> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ (G M_\mathrm{tot}^3 d)^{1 / 2} \biggl[\frac{\lambda}{(1+\lambda)^2} \biggr] + \frac{2}{5}(GM_\mathrm{tot}^3 d)^{1 / 2} \biggl(\frac{\lambda}{1+\lambda}\biggr) \biggl( \frac{R}{d}\biggr)^2 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> </td> <td align="left"> <math>~ + \frac{2}{5}(GM_\mathrm{tot}^3 d)^{1 / 2} \biggl(\frac{1}{1+\lambda}\biggr) \biggl( \frac{R^'}{d}\biggr)^2 </math> </td> </tr> <tr> <td align="right"> </td> <td align="center"> <math>~=</math> </td> <td align="left"> <math>~ (G M_\mathrm{tot}^3 R)^{1 / 2} \biggl\{ \biggl[\frac{\lambda}{(1+\lambda)^2} \biggr] \biggl( \frac{d}{R}\biggr)^{1 / 2} + \frac{2}{5} \biggl(\frac{1}{1+\lambda}\biggr)\biggl[ \lambda + \biggl( \frac{R^'}{R}\biggr)^{2} \biggr] \biggl( \frac{d}{R}\biggr)^{-3/2} \biggr\} </math> </td> </tr> </table> </div> If we assume that the two stars have the same (uniform) densities, <math>~\rho</math>, then, following Darwin (1906; see immediately below), the two stellar radii can be related to the mass ratio, <math>~\lambda</math> via the expressions, <div align="center"> <table border="0" cellpadding="5" align="center"> <tr> <td align="right"> <math>~R = a\biggl( \frac{\lambda}{1+\lambda}\biggr) \, ,</math> </td> <td align="center"> and </td> <td align="left"> <math>~R^' = a\biggl( \frac{1}{1+\lambda}\biggr) \, ,</math> </td> </tr> </table> </div> where, the characteristic length scale is, <div align="center"> <math>a \equiv \biggl(\frac{3M_\mathrm{tot}}{4\pi \rho}\biggr)^{1 / 3} \, .</math> </div> Replacing <math>~R</math> and <math>~R^'</math> by these expressions in our equation for <math>~L_\mathrm{tot}</math> results in the simplistic/illustrative expression for <math>~L_1</math> derived by Darwin (1906) and presented in the [[#DarwinL1L2|boxed-in image, below]]. Darwin's expression for <math>~L_2</math> is obtained by using the same expression for <math>~R</math> but treating the secondary as a point mass, that is, setting <math>~R^' = 0</math>.
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