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===Other Physical Variables=== The ratio of radiation pressure to gas pressure (see the last column of the above table) is calculated via the relation, <div align="center"> <math> \frac{1}{\Gamma} = \frac{P_\mathrm{rad}}{P_\mathrm{gas}} = \biggl( \frac{\tilde{a}}{3\tilde{r}} \biggr) \frac{T_\mathrm{code}^3}{\rho_\mathrm{code}} . </math> </div> Also note that, <div align="center"> <math> \beta \equiv \frac{P_\mathrm{gas}}{P_\mathrm{total}} = \frac{1}{1+P_\mathrm{rad}/P_\mathrm{gas}} . </math> </div> In order to avoid establishing stellar structures that are convectively unstable, Dominic also needs to choose an ''evolutionary'' ratio of specific heats, <math>\gamma</math>, such that its value is everywhere greater than a critical value, <math>\gamma_c</math>, established at the center of the accretor. From Equation (131) in Chapter II of [[Appendix/References#C67|Chandrasekhar (1967)]] we see that <math>\gamma_c</math> depends on each star's central value of <math>\beta</math> — that is, it depends on <math>\beta_c</math> — and on each star's ''structural'' <math>\Gamma_1 \equiv d\ln P/d\ln \rho</math> (which is <math>5/3</math> for our two {{Math/MP_PolytropicIndex}} <math>=3/2</math> polytropic stars) in the following way: <div align="center"> <math> \gamma_c = \biggl[ \frac{12(1-\beta_c)(\Gamma_1 - \beta_c) -\beta_c(\Gamma_1 - \beta_c) - (4-3\beta_c)^2}{12(1-\beta_c)(\Gamma_1 - \beta_c)- (4-3\beta_c)^2} \biggr]. </math> </div> Plugging <math>\rho_\mathrm{code}^\mathrm{max}</math> into these expressions lets us tabulate various properties at the center of both stars. <table align="center" border="1" cellpadding="5" width="75%"> <tr> <td align="center" colspan="10"> <b><font color="darkblue">Central Stellar Values</font></b> </td> </tr> <tr> <td colspan="2"> </td> <td align="center" colspan="3"> Approximations </td> <td align="center" colspan="5"> From Quartic Solution </td> </tr> <tr> <td align="center"> '''Star''' </td> <td align="center"> <math>\rho^\mathrm{max}_\mathrm{code}</math> </td> <td align="center"> <math>T_\mathrm{code}^\mathrm{max}</math> </td> <td align="center"> <math>\frac{P_\mathrm{rad}}{P_\mathrm{gas}}\biggr|_c</math> </td> <td align="center"> <math>\beta_c</math> </td> <td align="center"> <math>T_\mathrm{code}^\mathrm{max}</math> </td> <td align="center"> <math>\frac{P_\mathrm{rad}}{P_\mathrm{gas}}\biggr|_c</math> </td> <td align="center"> <math>\beta_c</math> </td> <td align="center"> <math>\gamma_c</math> </td> <td align="center"> <math>T_\mathrm{cgs}^\mathrm{max}</math> </td> </tr> <tr> <td align="center"> Accretor </td> <td align="center"> <math>1.0000</math> </td> <td align="center"> <math>0.5843</math> </td> <td align="center"> <math>6.65 \times 10^{-3}</math> </td> <td align="center"> <math>0.99339</math> </td> <td align="center" colspan="1"> 0.5805 </td> <td align="center" colspan="1"> <math>6.522\times 10^{-3}</math> </td> <td align="center" colspan="1"> 0.99352 </td> <td align="center" colspan="1"> 1.67765 </td> <td align="center" colspan="1"> <math>9.39\times 10^{7}~\mathrm{K}</math> </td> </tr> <tr> <td align="center"> Donor </td> <td align="center"> <math>0.6077</math> </td> <td align="center"> <math>0.3854</math> </td> <td align="center"> <math>3.14\times 10^{-3}</math> </td> <td align="center"> <math>0.99687</math> </td> <td align="center" colspan="1"> 0.3842 </td> <td align="center" colspan="1"> <math>3.111\times 10^{-3}</math> </td> <td align="center" colspan="1"> 0.99690 </td> <td align="center" colspan="1"> 1.67188 </td> <td align="center" colspan="1"> <math>6.22\times 10^{7}~\mathrm{K}</math> </td> </tr> </table> The central values of <math>P_\mathrm{rad}/P_\mathrm{gas}</math> obtained via the quartic solution match exactly the values that Dominic read straight from the rad-hydrocode, namely, <math>6.5\times 10^{-3}</math> (for the accretor) and <math>3.1\times 10^{-3}</math> (for the donor). (See email from Dominic to Joel dated 8/4/2010.) In this email, Dominic also stated that he chose <math>\gamma = 1.67114094</math>; I'm not quite sure how he derived this value. {{ SGFfooter }}
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